/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 To prevent misting of the windsc... [FREE SOLUTION] | 91Ó°ÊÓ

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To prevent misting of the windscreen of an automobile, recirculated warm air at \(37^{\circ} \mathrm{C}\) is blown over the inner surface. The windscreen glass \((k=1.0 \mathrm{~W} / \mathrm{m} \mathrm{K})\) is 4 \(\mathrm{mm}\) thick, and the ambient temperature is \(5^{\circ} \mathrm{C}\). The outside and inside heat transfer coefficients are 70 and \(35 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\), respectively. (i) Determine the temperature of the inside surface of the glass. (ii) If the air inside the automobile is at \(20^{\circ} \mathrm{C}, 1\) atm, and \(80 \%\) relative humidity, will misting occur? (Refer to your thermodynamics text for the principles of psychrometry.)

Short Answer

Expert verified
(i) The inside surface temperature is \(17.48^{\circ} \mathrm{C}\). (ii) No misting will occur since the inside temperature is above the dew point.

Step by step solution

01

Understand Heat Transfer Model

We will use the concept of heat transfer through a multi-layer system, modeled by the resistance method. For the inside surface temperature of the glass, we need the thermal resistance due to conduction through the glass and convection on both sides.
02

Calculate Conduction Resistance

The conduction resistance through the glass is given by \( R_c = \frac{L}{kA} \), where \( L = 0.004 \) m is the thickness of the glass, \( k = 1.0 \, \mathrm{W/mK} \) is the thermal conductivity, and \( A \) is the area (which cancels out later). So, \( R_c = \frac{0.004}{1.0} = 0.004 \, \mathrm{m^2K/W} \).
03

Calculate Convection Resistances

The convection resistance on the inside is \( R_\text{{conv, in}} = \frac{1}{h_\text{{in}}A} \) where \( h_\text{{in}} = 35 \, \mathrm{W/m^2K} \), so \( R_\text{{conv, in}} = \frac{1}{35} = 0.02857 \, \mathrm{m^2K/W} \). The convection resistance on the outside is \( R_\text{{conv, out}} = \frac{1}{70} = 0.01429 \, \mathrm{m^2K/W} \).
04

Evaluate Total Thermal Resistance

The total thermal resistance \( R_t \) is the sum of the resistances: \( R_t = R_\text{{conv, in}} + R_c + R_\text{{conv, out}} = 0.02857 + 0.004 + 0.01429 = 0.04686 \, \mathrm{m^2K/W} \).
05

Use Heat Transfer Equation

Using the formula \( q = \frac{T_\text{{in}} - T_\text{{out}}}{R_t} \), where \( T_\text{{in}} = 37^{\circ} \mathrm{C} \) and \( T_\text{{out}} = 5^{\circ} \mathrm{C} \), we have \( q = \frac{37 - 5}{0.04686} = 683.10 \, \mathrm{W/m^2} \).
06

Determine Inside Surface Temperature

Using the inside heat transfer equation, \( q = h_\text{{in}}(T_\text{{glass, in}} - T_\text{{air, in}}) \), solve for \( T_\text{{glass, in}} \), where \( h_\text{{in}} = 35 \, \mathrm{W/m^2K} \): \( 683.10 = 35(T_\text{{glass, in}} - 37) \). Solving gives \( T_\text{{glass, in}} = 37 - \frac{683.10}{35} = 17.48^{\circ} \mathrm{C} \).
07

Assess Misting Potential

Misting occurs when the air has enough moisture to cause condensation on a surface cooler than the dew point temperature. Use the gas law and psychrometric properties: Calculate the dew point at \(20^{\circ} \mathrm{C}\) and 80% humidity, which is above \(17.48^{\circ} \mathrm{C}\) (dew point \( \approx 16.5^{\circ} \mathrm{C}\)). Since \( T_\text{glass, in} > T_\text{dew} \), no misting will occur.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conduction
Conduction is the transfer of heat through a material without the movement of the material itself. This happens when heat travels due to the temperature difference from the hotter to the cooler region. Think of it like a domino effect where energy is passed from one atom to the next in a solid.
In the provided exercise, conduction is explored in the context of a windscreen glass. The glass has a thermal conductivity of 1.0 W/mK, meaning it allows that amount of heat to pass through one meter of the material with one degree of temperature difference per second. It's relatively effective for glass but shows how much insulation or resistance to heat flow is there.
The formula for conduction resistance is given by the equation, \( R_c = \frac{L}{kA} \).
  • \( R_c \) is the conduction resistance.
  • \( L \) is the thickness of the material.
  • \( k \) is the thermal conductivity.
  • \( A \) is the cross-sectional area.
In this scenario, the conduction resistance comes out to be about 0.004 m²K/W, showing the resistance to heat flow through the glass.
Convection
Convection is another method of heat transfer that involves the movement of fluid, which can be liquid or gas. In a car's windscreen situation, it involves air transferring heat either inside the car or to the colder outside air. It is an efficient way of removing or providing heat due to the fluid movement involved.
When you blow warm air onto the car's windscreen, the inner surface gains heat through convection. Convection relies on heat transfer coefficients, which are expressed in W/m²K.
In this exercise, there are two different convection resistances considered:
  • Inside the car, the convection resistance is mapped with a heat transfer coefficient of 35 W/m²K.
  • Outside, it is modeled with a coefficient of 70 W/m²K.
Calculating these convection resistances helps us understand how different rates of heat transfer occur due to the moving air both inside and outside the glass.
Psychrometry
Psychrometry is the study of the mixture of air and water vapor, and it is crucial when looking at air conditioning or any other systems involving humid air. This concept helps us understand whether mist or condensation will occur under specific conditions.
In the exercise example, we look at the air inside the car, which is at a certain temperature and humidity level. Here, the parameters are given as 20°C, 1 atm, and 80% relative humidity. This setup helps to check whether the air will condense on the glass, which could fog the windows.
We need to determine if the inside surface temperature exceeds the dew point (the temperature at which air holds water vapor before condensation occurs). Given our temperature calculations, the glass's inside surface temperature (17.48°C) is higher than the dew point (~16.5°C). Hence, according to psychrometric principles, mist will not form because the surface remains above the dew point.
Thermal Resistance
The concept of thermal resistance brings together the ideas of conduction and convection in a unified framework for analyzing heat transfer. Consider it like the thermal version of electrical resistance in a circuit. It helps quantify how much a layer of materials, such as a car windshield, resists the flow of heat.
The total thermal resistance in a system like this includes:
  • Conduction resistance through the glass, calculated previously as 0.004 m²K/W.
  • Convection resistances inside and outside the car glass.
We sum these to get the total thermal resistance: \[ R_t = R_{conv, in} + R_c + R_{conv, out} = 0.04686 \, \text{m}^2\text{K/W}. \]This value tells us the combined resistance to heat flow through the glass, considering all effects. Understanding how to compute and use thermal resistance is critical in engineering applications involving heat flow, as it simplifies complex problems into manageable calculations.

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Most popular questions from this chapter

Electronic components are often mounted with good heat conduction paths to a finned aluminum base plate, which is exposed to a stream of cooling air from a fan. The sum of the mass times specific heat products for a base plate and components is \(5000 \mathrm{~J} / \mathrm{K}\), and the effective heat transfer coefficient times surface area product is \(10 \mathrm{~W} / \mathrm{K}\). The initial temperature of the plate and the cooling air temperature are \(295 \mathrm{~K}\) when \(300 \mathrm{~W}\) of power are switched on. Find the plate temperature after 10 minutes.

A kitchen oven has a maximum operating temperature of \(280^{\circ} \mathrm{C}\). Determine the thickness of fiberglass insulation required to ensure that the outside surfaces do not exceed \(40^{\circ} \mathrm{C}\) when the kitchen air temperature is \(25^{\circ} \mathrm{C}\). The inside and outside heat transfer coefficients can be taken as \(40 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\) and \(15 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\), respectively, and the conductivity of the fiberglass insulation as \(0.07 \mathrm{~W} / \mathrm{m} \mathrm{K}\).

A freezer is \(1 \mathrm{~m}\) wide and deep and \(2 \mathrm{~m}\) high, and must operate at \(-10^{\circ} \mathrm{C}\) when the ambient air is at \(30^{\circ} \mathrm{C}\). What thickness of polystyrene is required if the load on the refrigeration unit should not exceed 200 W? Assume that the outer surface of the insulation is approximately at the ambient air temperature and that the base of the freezer is perfectly insulated.

A reactor vessel's contents are initially at \(290 \mathrm{~K}\) when a reactant is added, leading to an exothermic chemical reaction that releases heat at a rate of \(4 \times 10^{5} \mathrm{~W} / \mathrm{m}^{3}\). The volume and exterior surface area of the vessel are \(0.008 \mathrm{~m}^{3}\) and \(0.24 \mathrm{~m}^{2}\), respectively, and the overall heat transfer coefficient between the vessel contents and the ambient air at \(300 \mathrm{~K}\) is \(5 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\). If the reactants are well stirred, estimate their temperature after (i) I minute. (ii) 10 minutes. Take \(\rho=1200 \mathrm{~kg} / \mathrm{m}^{3}\) and \(c=3000 \mathrm{~J} / \mathrm{kg} \mathrm{K}\) for the reactants.

A system consists of a body in which heat is continuously generated at a rate \(\underline{Q}_{v}\), while heat is lost from the body to its surroundings by convection. Using the lumped thermal capacity model, derive the differential equation governing the temperature response of the body. If the body is at temperature \(T_{o}\) when time \(t=0\), solve the differential equation to obtain \(T(t) .\) Also determine the steady-state temperature.

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