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A low-pressure heat exchanger transfers heat between two helium streams, each with a flow rate of \(m=5 \times 10^{-3} \mathrm{~kg} / \mathrm{s}\). In a performance test the cold stream enters at a pressure of \(1000 \mathrm{~Pa}\) and a temperature of \(50 \mathrm{~K}\), and exits at \(730 \mathrm{~Pa}\) and \(350 \mathrm{~K}\). (i) If the flow cross-sectional area for the cold stream is \(0.019 \mathrm{~m}^{2}\), calculate the inlet and outlet velocities. (ii) If the exchanger can be assumed to be perfectly insulated, determine the rate of heat transfer in the exchanger. For helium, \(c_{p}=5200 \mathrm{~J} / \mathrm{kg} \mathrm{K}\).

Short Answer

Expert verified
Inlet velocity: \(27.34 \text{ m/s}\); Outlet velocity: \(138.16 \text{ m/s}\); Heat transfer rate: \(7800 \text{ W}\).

Step by step solution

01

Calculate the Inlet Velocity

To find the velocity of the helium stream at the inlet, we need to use the formula for volumetric flow rate, which is \( Q = A \cdot v \), where \( A \) is the cross-sectional area and \( v \) is the velocity. Convert pressure flow rate to volumetric flow rate using the ideal gas law: \( \dot{m} = \rho \cdot A \cdot v \), where \( \rho = \frac{P}{R \cdot T} \) is the density (use \( R = 8.314 \div 4 \approx 2.0785 \; \text{J/(mol K)} \) for helium), \( P = 1000 \; \text{Pa} \), and \( T = 50 \; \text{K} \). Hence, \[ v_{\text{in}} = \frac{m \cdot R \cdot T_{\text{in}}}{P_{\text{in}} \cdot A} = \frac{5 \times 10^{-3} \cdot 2.0785 \cdot 50}{1000 \cdot 0.019} \approx 27.34 \; \text{m/s} \].
02

Calculate the Outlet Velocity

Similarly, calculate the outlet velocity using the outlet conditions. Use \( P = 730 \; \text{Pa} \) and \( T = 350 \; \text{K} \). Using the formula \[ v_{\text{out}} = \frac{m \cdot R \cdot T_{\text{out}}}{P_{\text{out}} \cdot A} = \frac{5 \times 10^{-3} \cdot 2.0785 \cdot 350}{730 \cdot 0.019} \approx 138.16 \; \text{m/s} \].
03

Determine the Rate of Heat Transfer

To find the rate of heat transfer, use the formula \( Q = \dot{m} \cdot c_p \cdot (T_{\text{out}} - T_{\text{in}}) \). Substitute the known values: \[ Q = 5 \times 10^{-3} \cdot 5200 \cdot (350 - 50) = 5 \times 10^{-3} \cdot 5200 \cdot 300 = 7800 \; \text{W} \]. The heat transfer rate is 7800 W.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Helium stream
Helium, a noble gas, is often used in various industrial and scientific applications due to its low density and inert nature. In a heat exchanger, a helium stream can be used as a medium to transfer or absorb heat efficiently. Heat exchangers can operate under high or low pressure, and in our example, we are dealing with a low-pressure helium stream. Understanding the behavior of a helium stream in a heat exchanger requires knowledge of various properties including
  • mass flow rate, which is given as 5 x 10-3 kg/s,
  • pressure at different points in the system,
  • temperature at both inlet and outlet.
These parameters help in calculating the velocity and heat transfer, crucial for efficient heat exchanger performance. By analyzing these properties, engineers can ensure the system is running optimally.
Ideal gas law
The ideal gas law is a fundamental equation in thermodynamics represented as \( PV = nRT \), where \( P \) stands for pressure, \( V \) for volume, \( n \) for the number of moles, \( R \) for the universal gas constant, and \( T \) for temperature. For practical purposes, it can also be expressed as \( PV = mRT \), where m represents mass, and R is the specific gas constant.

In our example involving a helium stream, this law helps in determining the density of helium at various points, which affects the overall flow. Using the expression \( \rho = \frac{P}{RT} \) to find density, allows us to rearrange the formula to find any unknown when given pressure, temperature, and cross-sectional area. This is essential for calculating the velocities and volumetric flow rates.
Volumetric flow rate
Volumetric flow rate is an essential concept in fluid dynamics, representing the volume of fluid flowing through a given cross section per unit time. It is denoted as \( Q \) and is calculated by the formula \( Q = A \cdot v \), where \( A \) is the cross-sectional area and \( v \) is the velocity of the fluid.

In cases involving gases like helium, conditions of the fluid can change significantly, hence using the ideal gas law to relate pressure and temperature is crucial. Calculating both the inlet and outlet velocities allows us to determine the volumetric flow rate at these points. For example, given the area and pressures, you can substitute values including mass flow rate and temperature into specific equations to determine velocities, thereby calculating the flow rate accurately.
Specific heat capacity
Specific heat capacity, represented as \( c_p \), is the amount of heat required to change a substance's temperature by one degree Celsius or Kelvin at constant pressure. For helium, the specific heat capacity is provided as 5200 J/(kg K), a value that is critical when calculating heat transfer within a heat exchanger.

To calculate the rate of heat transfer, we use the equation \( Q = \dot{m} \cdot c_p \cdot (T_{\text{out}} - T_{\text{in}}) \). In this scenario, it's important to note the difference in temperature between entry and exit points, which are 350 K and 50 K, respectively. This difference, multiplied by the specific heat capacity and mass flow rate, gives us an understanding of how much energy is transferred within the system, in units of Watts (W). Understand this parameter helps in effectively managing thermal systems.

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Most popular questions from this chapter

A \(2.5 \mathrm{~m}\)-diameter, \(3.5 \mathrm{~m}\)-high milk storage tank is located in a dairy factory in Onehunga, New Zealand, where the ambient temperature is \(30^{\circ} \mathrm{C}\). The tank has walls of stainless steel \(2 \mathrm{~mm}\) thick and is insulated with a \(7.5 \mathrm{~cm}\)-thick layer of polyurethane foam. The tank is filled with milk at \(4^{\circ} \mathrm{C}\) and is continuously stirred by an impeller driven by an electric motor that consumes \(400 \mathrm{~W}\) of power. What will the milk temperature be after 24 hours? For the milk, take \(\rho=1034 \mathrm{~kg} / \mathrm{m}^{3}\). \(c=3894 \mathrm{~J} / \mathrm{kg} \mathrm{K} ;\) for the insulation, \(k=0.026 \mathrm{~W} / \mathrm{m} \mathrm{K} ;\) and for the outside heat transfer coefficient, \(h=5 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\). The impeller motor efficiency can be taken as \(0.75\).

An alloy cylinder \(3 \mathrm{~cm}\) in diameter and \(2 \mathrm{~m}\) high is removed from an oven at \(200^{\circ} \mathrm{C}\) and stood on its end to cool in air at \(20^{\circ} \mathrm{C}\). Give an estimate of the time for the cylinder to cool to \(100^{\circ} \mathrm{C}\) if the convective heat transfer coefficient is \(80 \mathrm{~W} / \mathrm{m}^{2}\) \(\mathrm{K}\). For the alloy, take \(\rho=8600 \mathrm{~kg} / \mathrm{m}^{3}, c=340 \mathrm{~J} / \mathrm{kg} \mathrm{K}\), and \(k=110 \mathrm{~W} / \mathrm{m} \mathrm{K}\).

A kitchen oven has a maximum operating temperature of \(280^{\circ} \mathrm{C}\). Determine the thickness of fiberglass insulation required to ensure that the outside surfaces do not exceed \(40^{\circ} \mathrm{C}\) when the kitchen air temperature is \(25^{\circ} \mathrm{C}\). The inside and outside heat transfer coefficients can be taken as \(40 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\) and \(15 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\), respectively, and the conductivity of the fiberglass insulation as \(0.07 \mathrm{~W} / \mathrm{m} \mathrm{K}\).

A carbon steel butane tank weighs \(4.0 \mathrm{~kg}\) (empty) and has a surface area of \(0.22\) \(\mathrm{m}^{2}\). When full it contains \(2 \mathrm{~kg}\) of liquified gas. Butane gas is drawn off to a burner at a rate of \(0.05 \mathrm{~kg} / \mathrm{h}\) through a pressure-reducing valve. If the ambient temperature is \(55^{\circ} \mathrm{C}\), estimate the steady temperature of the tank and the time taken for \(80 \%\) of the temperature drop to occur. Take the sum of the convective and radiative heat transfer coefficients from the tank to the surroundings as 5 \(\mathrm{W} / \mathrm{m}^{2} \mathrm{~K}\). Property values for butane are \(c=2390 \mathrm{~J} / \mathrm{kg} \mathrm{K}\) and \(h_{f g}=3.86 \times 10^{5}\) \(\mathrm{J} / \mathrm{kg}\); for the steel \(c=434 \mathrm{~J} / \mathrm{kg} \mathrm{K}\).

A thermometer is used to check the temperature in a freezer that is set to operate at \(-5^{\circ} \mathrm{C}\). If the thermometer initially reads \(25^{\circ} \mathrm{C}\), how long will it take for the reading to be within \(1^{\circ} \mathrm{C}\) of the true temperature? Model the thermometer bulb as a \(4 \mathrm{~mm}\)-diameter mercury sphere surrounded by a \(2 \mathrm{~mm}\)-thick shell of glass. For mercury, take \(\rho=13,530 \mathrm{~kg} / \mathrm{m}^{3}, c=140 \mathrm{~J} / \mathrm{kg} \mathrm{K}\); and for glass \(\rho=2640 \mathrm{~kg} / \mathrm{m}^{3}, c=800 \mathrm{~J} / \mathrm{kg} \mathrm{K}\). Use a heat transfer coefficient of \(15 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\).

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