Chapter 4: Problem 22
Force \(F\) newtons is given by the formula \(F=\frac{G m_{1} m_{2}}{d^{2}}\), where \(m_{1}\) and \(m_{2}\) are masses, \(d\) their distance apart and \(G\) is a constant. Find the value of the force given that \(G=6.67 \times 10^{-11}, m_{1}=7.36, m_{2}=15.5\) and \(d=22.6\). Express the answer in standard form, correct to 3 significant figures.
Short Answer
Step by step solution
Identify the given values
Write down the formula
Substitute the known values
Calculate \( d^2 \)
Calculate \( G m_1 m_2 \)
Divide \( G m_1 m_2 \) by \( d^2 \)
Calculate the force
Round to three significant figures
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Newton's law of universal gravitation
- \( F \) is the gravitational force between two objects
- \( G \) is the gravitational constant, approximately \( 6.67 \times 10^{-11} \; \text{Nm}^2/\text{kg}^2 \)
- \( m_1 \) and \( m_2 \) are the masses of the objects
- \( d \) is the distance between the centers of the two masses
Significant figures
- The first digit is the most significant, not being a zero
- The final digit represents the precision of the measurement, informed by the calculation
- Include zeros that are sandwiched between significant digits
Standard form
- The coefficient \( 6.67 \) is a number between 1 and 10
- The exponent \( -11 \) indicates how many places the decimal has been moved to the right