Chapter 13: Problem 5
Plot a graph of \(y=2 x^{2}\) and hence solve the equations: (a) \(2 x^{2}-8=0\) and (b) \(2 x^{2}-x-3=0\)
Short Answer
Expert verified
Solutions: (a) \(x = 2, -2\); (b) \(x = 1.5, -1\).
Step by step solution
01
Understand the Function
The given function is \(y = 2x^2\), which is a quadratic function. It represents a parabola that opens upwards because the coefficient of \(x^2\) is positive.
02
Plot the Graph
To plot \(y = 2x^2\), choose a set of \(x\) values. Calculate the corresponding \(y\) values using the function. For example, if \(x=-2\), then \(y=2(-2)^2 = 8\). Repeat this for several values of \(x\) (e.g., -3 to 3). Plot these points on a graph and draw a smooth curve through them to form a parabola.
03
Solve Equation (a) \(2x^2 - 8 = 0\)
To solve \(2x^2 - 8 = 0\), add 8 to both sides to obtain \(2x^2 = 8\). Divide both sides by 2 to get \(x^2 = 4\). Take the square root of both sides to find \(x = \pm 2\). Therefore, the solutions are \(x = 2\) and \(x = -2\).
04
Verify Solutions of (a) on Graph
On the graph of \(y = 2x^2\), the points \((2, 8)\) and \((-2, 8)\) should be on the horizontal line \(y = 8\), confirming that \(x = 2\) and \(x = -2\) satisfy the equation when \(y = 8\).
05
Solve Equation (b) \(2x^2 - x - 3 = 0\)
This is another quadratic equation in standard form. Use the quadratic formula, \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 2\), \(b = -1\), and \(c = -3\). Calculate the discriminant: \((-1)^2 - 4(2)(-3) = 1 + 24 = 25\). Substitute into the formula to find \(x = \frac{1 \pm 5}{4}\), giving solutions \(x = \frac{6}{4} = 1.5\) and \(x = \frac{-4}{4} = -1\).
06
Verify Solutions of (b) on Graph
Plot \((1.5, 0)\) and \((-1, 0)\) on the graph of \(y = 2x^2 - x - 3\). These points are where the graph intersects the x-axis, confirming the solutions are correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Function
A quadratic function is a type of polynomial function that involves an expression of the form \(y = ax^2 + bx + c\). In these functions, the highest exponent of the variable \(x\) is 2, which is why they are commonly known as second-degree polynomials. The general form \(ax^2 + bx + c\) often describes the curvature of various paths, such as the trajectory of a thrown ball.
In our case, the exercise focuses on the function \(y = 2x^2\). This function is simpler as it lacks the linear component \(bx\) and constant \(c\). This simplicity makes it an excellent starting point for understanding quadratic functions. It shows a clear example of a parabola that opens upward due to the positive coefficient of \(x^2\).
In our case, the exercise focuses on the function \(y = 2x^2\). This function is simpler as it lacks the linear component \(bx\) and constant \(c\). This simplicity makes it an excellent starting point for understanding quadratic functions. It shows a clear example of a parabola that opens upward due to the positive coefficient of \(x^2\).
- **Coefficient \(a\):** Determines the direction of the opening. Positive \(a\) means upwards.
- **Vertex:** The lowest point on the parabola for this quadratic, at the origin (0,0).
- **Axis of Symmetry:** A vertical line passing through the vertex, here it coincides with the y-axis.
Graph Plotting
Plotting a quadratic function like \(y = 2x^2\) involves creating a set of points and connecting them to show the curve. This step is essential as visual representation strengthens understanding and helps solve related equations. Here's how to effectively plot a quadratic function:
Start by selecting several x-values, typically a mix around the vertex (e.g., -3 to 3 for \(y = 2x^2\)). For each x-value, compute the corresponding y-value using the function (e.g., \(x = -2\) gives \(y = 2(-2)^2 = 8\)).
Start by selecting several x-values, typically a mix around the vertex (e.g., -3 to 3 for \(y = 2x^2\)). For each x-value, compute the corresponding y-value using the function (e.g., \(x = -2\) gives \(y = 2(-2)^2 = 8\)).
- **Choosing Points:** Ensure to select sufficient points around the vertex to capture the parabola's shape.
- **Calculating y-values:** Substituting x-values into the equation determines y-values.
- **Plotting Points:** Plot each point on a graph and connect the dots smoothly.
Parabola
A parabola, in mathematics, is the curve of a quadratic function. The distinct shape is defined by the equation of the function, like \(y = 2x^2\), and possesses unique features: vertex, axis of symmetry, and direction of opening.
A key aspect of a parabola is its **vertex**, the point where the curve turns. For functions like \(y = 2x^2\), the vertex is at the origin (0,0), representing its lowest point. The **axis of symmetry** is a vertical line through the vertex, making the parabola symmetrical relative to this line.
The parabola's direction, upward or downward, is determined by the sign of the leading coefficient \(a\). A positive \(a\), as seen in \(y = 2x^2\), results in an upward opening, while a negative \(a\) flips the parabola downward.
A key aspect of a parabola is its **vertex**, the point where the curve turns. For functions like \(y = 2x^2\), the vertex is at the origin (0,0), representing its lowest point. The **axis of symmetry** is a vertical line through the vertex, making the parabola symmetrical relative to this line.
The parabola's direction, upward or downward, is determined by the sign of the leading coefficient \(a\). A positive \(a\), as seen in \(y = 2x^2\), results in an upward opening, while a negative \(a\) flips the parabola downward.
- **Vertex form:** Often used for transformations, looks like \(y = a(x - h)^2 + k\).
- **Standard form:** Provides a straightforward method for plotting and analyzing, as in \(y = ax^2 + bx + c\).
- **Graphical use:** Helps in solving quadratic equations by observing x-intercepts.