Chapter 26: Problem 7
For a Hubble constant of \(70 \mathrm{km} / \mathrm{s} / \mathrm{Mpc}\), the critical density is \(9 \times 10^{-23} \mathrm{kg} / \mathrm{m}^{3}\). (a) How much mass does this correspond to within a volume of 1 cubic astronomical unit? (b) How large a cube would be required to enclose 1 Earth mass of material?
Short Answer
Step by step solution
Convert Cubic Astronomical Unit to Cubic Meters
Calculate Mass within the Volume of 1 AU³
Determine Size of Cube for 1 Earth Mass
Solution Conclusion
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