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How would the value of the acceleration due to gravity for Earth, which is \(9.8 \mathrm{m} / \mathrm{s}^{2},\) differ if Earth's radius were larger but its mass were the same? Why?

Short Answer

Expert verified
The acceleration due to gravity would decrease because the radius squared \( R^2 \) increases, reducing \( g \).

Step by step solution

01

Understanding Gravity Formula

The acceleration due to gravity on the surface of a planet is given by the formula \( g = \frac{G M}{R^2} \), where \( G \) is the gravitational constant, \( M \) is the mass of the planet, and \( R \) is the radius of the planet.
02

Identifying Variables

In this scenario, the mass \( M \) remains constant, as does the gravitational constant \( G \). The variable that changes is the radius \( R \).
03

Effect of Increasing Radius

If the radius \( R \) increases while the mass \( M \) stays the same, substituting into the formula \( g = \frac{G M}{R^2} \), the denominator \( R^2 \) increases. This results in a decrease in the value of \( g \), the acceleration due to gravity, because the denominator grows larger.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Constant
The gravitational constant, symbolized as \( G \), is a fundamental value used in physics to measure the force of gravity between two bodies. Its value is approximately \( 6.67430 \times 10^{-11} \, \text{m}^3 \, \text{kg}^{-1} \, \text{s}^{-2} \). This constant is essential when calculating gravitational force. It allows us to compute how two masses will attract each other, regardless of their distance apart. Without \( G \), we wouldn't be able to understand how planets, stars, and other celestial objects interact. Understanding \( G \) helps us make sense of not just planetary motion, but also how satellites orbit the Earth and how objects behave in space.

When it comes to determining the acceleration due to gravity on a planet, \( G \) remains constant. This means the gravitational pull doesn't vary with changes in distance as long as the gravitational constant remains unchanged. Remember, it's a universal constant, meaning it has the same value everywhere in the universe.
Planetary Radius
The planetary radius is the distance from the center of the planet to its surface. It is a crucial factor in determining the gravity experienced on a planet. In the formula \( g = \frac{G M}{R^2} \), the radius \( R \) is squared and appears in the denominator. This means that as the radius increases, the value of \( R^2 \) becomes larger, causing \( g \), the gravitational acceleration, to decrease.

This relationship highlights that gravity is not just about mass, but also about how far you are from the mass. An increased radius means you're further from the center of the mass, which decreases the gravitational pull. For instance, if Earth were to expand while its mass remained fixed, the gravitational pull would lessen due to the larger radius.
  • Radius determines the spread of gravitational force.
  • Larger radius equates to weaker surface gravity, assuming mass remains constant.
  • Despite changes in radius, the mass and gravitational constant remain key in calculations.
Remember, only changes in radius affect the squared term, dramatically influencing the gravity level experienced on the surface.
Mass of the Planet
The mass of a planet, represented by \( M \), is crucial in calculating gravitational acceleration. It refers to the total amount of matter contained within the planet. In the gravitational formula \( g = \frac{G M}{R^2} \), \( M \) directly influences the strength of gravity. More mass results in a stronger force of gravity since there is more matter to exert a pull.

Maintaining the same mass while altering the radius, as highlighted in the original step-by-step solution, alters gravitational acceleration due solely to the radius change. However, the mass remains a pivotal element because it is what \( G \) acts upon in the equation. Increasing the mass while keeping the radius fixed increases \( g \) because you have more matter attracting towards the center.
  • The mass determines how much gravitational pull can be exerted.
  • A larger mass increases gravity; a smaller mass has the opposite effect.
  • While mass is constant in some scenarios, its value underpins the entire gravitational equation.
Understanding how mass interacts in this equation helps clarify why different planets have varying gravitational forces. The mass is central to why Jupiter, with its immense mass, has a much stronger gravitational pull than Earth.

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Most popular questions from this chapter

Asteroid A has a mass of \(2 \times 10^{20}\) kilograms (kg), and asteroid B has a mass of \(4 \times 10^{18} \mathrm{kg} .\) Assuming that the same force was applied to both (a shock wave from a supernova, for example), what would be the ratio of A's acceleration to B's acceleration?

Which of the following characteristics was/were included in Ptolemy's model of the Universe? Choose all that apply a. Earth rotates on its own axis. b. The celestial sphere is perfect and unchanging. c. Planets move in circles on top of circles called epicycles. d. All the planets, as well as both the Sun and the Moon, revolve around Earth. e. The nested set of crystalline, celestial spheres is maintained as proposed by Aristotle.

Which of the following describes Kepler's approach and contributions to astronomy? a. He constrained his models of planetary motion with the positional data from Tycho Brahe. b. He maintained the use of epicycles in planetary motion. c. He correctly showed that planetary orbits were based on geometric shapes called platonic solids. d. He ignored all the work of important astronomers who preceded him. e. He understood that planetary motions resulted from mutually attractive gravitational force.

Given two objects, if the mass of one increases while the distance between them increases, how does the magnitude of the gravitational force change? a. It always increases. b. It always decreases. c. It always remains the same. d. It depends on the specific values of the mass and distance changes. e. It depends on the local value of \(G\)

A spinning figure skater spins faster as he brings his outstretched arms inward. This is an illustration of the physical principle underlying a. Kepler's first law. b. Kepler's second law. c. Kepler's third law. d. the law of gravity. e. none of the above

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