Chapter 15: Problem 42
How many times faster would a star's orbital velocity be at the Sun's position, compared with that of a star orbiting at 3.7 times the distance from the galactic center, assuming that dark matter is not a factor and that all the mass of the luminous matter can be considered to reside in the galactic center?
Short Answer
Step by step solution
Understand the Role of Luminous Mass in Orbital Velocity
Find Velocities at the Given Radii
Calculate the Ratio of Velocities
Compute the Final Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gravitational Constant
In astronomy, \( G \) allows us to explore the dynamics of celestial bodies, such as stars orbiting a galactic center. It is a crucial element in the formula used to determine a star's orbital velocity: \( v = \sqrt{\frac{G M}{r}} \). Here, \( G \) connects the orbital velocity, the mass of the celestial body being orbited, and the radius of the orbit.
- Value of \( G \): Approximately \( 6.674 \times 10^{-11} \text{ m}^3 \text{kg}^{-1} \text{s}^{-2} \)
- It remains constant throughout the universe.
- Instrumental in calculating gravitational forces in both astronomical and terrestrial contexts.
Luminous Mass
In the context of galaxies, the luminous mass is often considered to be concentrated in the galactic center for simplicity in calculations like those in the exercise. This assumption allows for easier computation of a star's orbital velocity.
- Visible mass includes stars, nebulae, and other light-emitting bodies.
- Often, luminous mass is only a fraction of a galaxy's total mass due to the existence of dark matter.
- Used in calculations under the assumption that dark matter is not influencing the system significantly.
Circular Orbit
In our exercise, the circular orbit is essential for determining the star's velocity using the formula \( v = \sqrt{\frac{G M}{r}} \). The simplicity of a circular orbit means the radius \( r \) doesn't change as the star orbits, making calculations straightforward and reliable.
- In a circular orbit, the force of gravity provides the necessary centripetal force to maintain the orbit.
- Though idealized, circular orbits offer valuable insights into more complex elliptical orbits.
- Understanding them is foundational in orbital mechanics and astrophysics.
Galactic Center
In our scenario, all luminous mass is assumed to reside at the galactic center, an idealization that aids in solving the problem of orbital velocities. This assumption simplifies the gravitational interactions in play, allowing for predictions of how stars orbit relative to this center.
- A prominent feature in the Milky Way and other galaxies.
- Often hosts a supermassive black hole, contributing significantly to the galaxy's gravitational field.
- Understanding its gravitational influence is crucial for mapping and predicting orbital paths of stars.