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The free-fall time of a gravitationally collapsing cloud is \(T\). What would be its free-fall time in terms of \(T\) if its density were 3.2 times as high?

Short Answer

Expert verified
The new free-fall time is approximately 0.559 times the original free-fall time, \( T \).

Step by step solution

01

Understanding the Free-Fall Time Formula

The free-fall time of a gravitational cloud is given by the formula: \[ T = \sqrt{\frac{3\pi}{32G \rho}} \]where \( T \) is the free-fall time, \( G \) is the gravitational constant, and \( \rho \) is the density of the cloud. The formula shows that free-fall time \( T \) is inversely proportional to the square root of the density \( \rho \).
02

Relating New Conditions to the Original

Let the new density be \( \rho' = 3.2 \rho \). We need to find the new free-fall time \( T' \) in terms of \( T \) when the density has increased to \( 3.2 \) times the original density. Since \( T = \sqrt{\frac{3\pi}{32G \rho}} \), the new free-fall time would be:\[ T' = \sqrt{\frac{3\pi}{32G \cdot 3.2 \rho}} \]
03

Simplifying the New Free-Fall Formula

We simplify the expression for \( T' \) using the fact that \( T = \sqrt{\frac{3\pi}{32G \rho}} \):\[ T' = \sqrt{\frac{3\pi}{32G \cdot 3.2 \rho}} \]\[ T' = \frac{1}{\sqrt{3.2}} \sqrt{\frac{3\pi}{32G \rho}} \]Since \( T = \sqrt{\frac{3\pi}{32G \rho}} \):\[ T' = \frac{1}{\sqrt{3.2}} T \]
04

Calculating the Final Ratio

We calculate \( \sqrt{3.2} \) to express \( T' \) precisely:\[ \sqrt{3.2} \approx 1.7889 \]Thus:\[ T' = \frac{1}{1.7889} T \approx 0.559 T \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Collapse
Gravitational collapse is a process by which an astronomical object contracts under its own gravity. This phenomenon occurs when the internal pressure of the object's matter is unable to support itself against the gravitational forces pulling everything inward.
This is a critical stage in the life cycle of stars and can lead to various outcomes, such as the formation of black holes, neutron stars, or white dwarfs.
  • During collapse, the object's material becomes denser and the gravitational energy converts into heat.
  • This process accelerates as more mass is drawn inwards, further intensifying the gravitational pull.
A cloud made of gas and dust in space could undergo gravitational collapse if its internal kinetic energy, which tends to disperse the material, becomes too low compared to the gravitational potential energy pulling it together.
In such cases, the objects can either form denser celestial bodies or lead to explosive events if there are additional forces and reactions involved, such as nuclear fusion in stars.
Density
Density plays a pivotal role in the behavior of celestial bodies, particularly in gravitational collapse. It is defined as the amount of mass per unit volume and affects how quickly a cloud of gas or any other object in space might collapse.
Density is a measure of how 'packed' the material in an object is.
It is represented by the symbol \( \rho \) and calculated by the formula:
  • \( \rho = \frac{m}{V} \)
where \( m \) stands for mass and \( V \) stands for volume.
In the case of a gravitational cloud, a higher density means the gravitational attraction between the particles is stronger, leading to a faster collapse.
  • This is because the free-fall time, represented by \( T \), is inversely proportional to the square root of density.
  • When the density \( \rho \) increases, the free-fall time decreases, leading to quicker gravitational collapse.
Thus, understanding density helps in predicting how quickly a cloud will contract under its gravity.
Gravitational Constant
The gravitational constant, usually denoted as \( G \), is a key factor in the laws of gravity, determining the strength of gravitational forces in the universe. It is a constant of proportionality in Newton's law of universal gravitation and serves as a bridge between mass, force, and distance.
The gravitational constant is approximately \( 6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \).
It determines how much gravitational force one object exerts on another; hence, it profoundly affects astronomical calculations.
In the free-fall time formula for a gravitational collapse, \( G \) appears as a part of the denominator:
  • \( T = \sqrt{\frac{3\pi}{32G \rho}} \)
This reflects the role of \( G \) in moderating the gravitational attraction due to the density \( \rho \) of the cloud.
If \( G \) were larger, the gravitational pull between particles would be stronger, impacting how quickly objects collapse under their gravity. Understanding the gravitational constant helps us comprehend not just how objects in the universe move and interact, but also the timescales upon which these processes occur.

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Most popular questions from this chapter

Which of the following is not a typical outcome for material in an accretion disk around a protostar? a. It accretes onto the protostar. b. It becomes part of a planet. c. It gets eroded by photoevaporation. d. It remains in the disk indefinitely. e. It returns to the ISM.

Two protostars have evolved to the point of nuclear fusion. One has a temperature of 12 million \(\mathrm{K}\); the other, a temperature of 17 million K. Which of the following statements is/are true about the stars? Choose all that apply. a. The 17 -million-K star burns nuclear fuel faster. b. The 17 -million-K star may be using the CNO cycle of nuclear fusion. c. The 17 -million-K star will die sooner. d. The 17 -million-K star can be using only the P-P process of nuclear fusion. e. The stars may have identical masses.

Many astronomical objects have dense cores. Which of the following do not? a. stars b. protostars c. molecular clouds d. globular clusters e. coronal gas clouds

An object has a mass that is less than 8 percent of the Sun's mass, and its elemental composition includes carbon, nitrogen, and oxygen. Which of the following is/are true? Choose all that apply a. It could be a planet. b. It could be a brown dwarf. c. It must be on or moving toward the main sequence. d. It must not have reached 16 million \(\mathrm{K}\). e. It must be fusing protons into deuterium.

Describe the differences in the formation of a brown dwarf versus a planet; then describe the differences in the formation of a brown dwarf versus a main-sequence star.

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