Chapter 8: Problem 84
A uniform rod \(A B\) of mass \(m\) and length \(l\) is at rest on a smooth horizontal surface. An impulse \(p\) is applied to the end \(B\). The time taken by the rod to turn through a right angle is : (a) \(2 \pi \frac{m l}{p}\) (b) \(2 \pi \frac{p}{m l}\) (i) \(\frac{\pi m l}{12 p}\) (d) \(\frac{\pi p}{m !}\)
Short Answer
Step by step solution
Understand the Concept
Calculate Angular Momentum
Calculate Moment of Inertia
Determine Angular Velocity
Find Angular Displacement
Recognize Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Impulse and Momentum
- Linear Momentum: Retains its classic form, \( \Delta p = m \cdot v \).
- Angular Momentum: Introduced when force is applied at a point displaced from the center of rotation.
Angular Motion
- Angular Displacement: Measures how far the object rotates about an axis, represented by \( \theta \).
- Angular Velocity: The rate of rotation, denoted by \( \omega \), is key in calculating the time taken by the rod to turn at a given angle.
- Angular Acceleration: Under constant conditions, this would be zero in our exercise, given an impulse is applied momentarily.
Moment of Inertia
- Dependence on Distance from Axis: Moment of inertia increases with the square of the distance from the axis of rotation. In our case, the impulse applied causes rotation about the rod's center.
- Influence on Angular Momentum: Directly tied to angular motion—the greater the moment of inertia, the slower the object accelerates angularly under an impulse.
Rotational Dynamics
- Application of Torques: Impulse at a distance from the pivot generates torque, causing the rod to rotate.
- Relating Torque to Angular Motion: Using rotational analogues of Newton's laws, torque \( \tau \) is related to angular acceleration \( \alpha \): \[ \tau = I \cdot \alpha \].