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A man is sitting in a moving train, then : (a) his momentum must not be zero (b) his kinetic energy is zero (c) his kinetic energy is not zero (d) his kinetic energy may be zero

Short Answer

Expert verified
Option (c): his kinetic energy is not zero.

Step by step solution

01

Understand Kinetic Energy

Kinetic energy is the energy that an object possesses due to its motion. It is given by the formula \( KE = \frac{1}{2} mv^2 \), where \( m \) is the mass of the object and \( v \) is its velocity. An object will have non-zero kinetic energy if it is moving with respect to another reference point.
02

Consider the Reference Point

When considering kinetic energy or momentum, it's important to specify the reference frame. If the man is sitting in a moving train, relative to an observer outside the train, he does have velocity, and so he must have kinetic energy. If the observer is also in the train, he perceives the man as stationary.
03

Determine Momentum

Momentum is calculated as \( p = mv \), where \( m \) is mass and \( v \) is velocity. Like kinetic energy, momentum also depends on the reference frame, but it won’t be zero as long as the train is moving relative to the observer.
04

Analyze Each Option

(a) True - His momentum must not be zero relative to an outside observer. (b) False - His kinetic energy is not zero relative to an outside observer. (c) True - His kinetic energy is not zero relative to an outside observer. (d) False - His kinetic energy is zero relative to an observer inside the train.
05

Conclude the Correct Answer

Considering the points above on reference frames and motion relative to an outside observer, the correct answer is: (c) his kinetic energy is not zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reference Frames
In physics, a reference frame is a perspective from which we observe and measure the motion of an object. This concept is crucial when discussing kinetic energy and momentum. Without specifying a reference frame, descriptions of these properties can be misleading.

Imagine you're on a train: this is your reference frame. You see the man sitting quietly next to you. To you, he appears stationary, meaning his velocity is zero in your reference frame.
  • Anyone inside the train shares this perspective and sees zero motion.
  • In this frame, his kinetic energy can be considered zero because there is no relative motion perceived.
However, to an observer outside the train, moving along the tracks, things look different. The man is traveling at the same speed as the train. This alters his kinetic energy and momentum from the outsider's viewpoint.

Different reference frames can lead to different results in calculations of kinetic energy and momentum, highlighting the importance of specifying the frame in any physical analysis.
Momentum
Momentum is another key concept when understanding the behavior of objects in motion. It is defined as the product of an object's mass and velocity, given by the equation \( p = mv \). Like kinetic energy, momentum is also relative to the observer's reference frame.

When considering momentum:
  • An observer on the train perceives the man sitting down as having zero momentum because he sees no movement.
  • However, a person outside the train sees the man moving along with the train, meaning his momentum is not zero from this other viewpoint.
Momentum conservation is a fundamental principle in physics. It remains the same in isolated systems, even when objects interact. Yet, whether we see this momentum as zero or not depends entirely on our frame of reference.

It’s essential to clearly indicate the observer's frame when discussing momentum, as this determines how it's measured and perceived.
Relative Motion
Relative motion describes how the position of an object changes in relation to another. This concept is crucial when considering kinetic energy and momentum, as any movement is always relative to something else.

Let's see how relative motion affects our scenario:
  • For someone on the train, the man seems to have no motion at all; they both move together, so there is no relative motion between them.
  • For someone outside—perhaps at a crossing or another train going in a different direction—the man is in motion, exhibiting clear relative motion with respect to the outside world.
Understanding relative motion helps us grasp why kinetic energy and momentum appear different in varying scenarios. In physics, acknowledging motion is relative leads to more accurate descriptions and models.

By embracing the notion of relative motion, students can better comprehend how two observers can perceive the same event differently, offering deeper insights into both kinetic energy and momentum.

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Most popular questions from this chapter

Mark correct option or options: (a) The kinetic energy of a system may be changed without changing momentum (b) The momentum of a system may be changed without changing kinetic energy (c) If momentum of a system is zero, kinetic energy of system must be zero (d) If different bodies have same momentum, kinetic energy of lightest body will be maximum

Two observers are situated in different inertial reference frames. Then: (a) the momentum of a body by both observers may be same (b) the momentum of a body measured by both observers must be same (c) the kinetic energy measured by both observers must be same (d) none of the above

If kinetic energy of a body remains constant, then momentum mass graph is:

The motion of the centre of mass of a system of two particles is unaffected by their internal forces: (a) irrespective of the actual directions of the internal forces (b) only if they are along the line joining the particles (c) only if they are at right angles to the line joining particles (d) only if they are obliquely inclined to the line joining the particles

Two negatively charged particles having charges \(e_{1}\) and \(e_{2}\) and masses \(m_{1}\) and \(m_{2}\) respectively are projected one after another into a region with equal initial velocities. The electric field \(E\) is along the \(y\) -axis, while the direction of projection makes an angle \(\alpha\) with the \(y\) -axis. If the ranges of the two particles along the \(x\) -axis are equal then one can conclude that : (a) \(e_{1}=e_{2}\) and \(m_{1}=m_{2}\) (b) \(e_{1}-e_{2}\) only (c) \(m_{1}=m_{2}\) only (d) \(e_{1} m_{1}=e_{2} m_{2}\)

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