/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 A bus moves over a straight leve... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A bus moves over a straight level road with a constant acceleration \(a\). A boy in the bus drops a ball out side. The acceleration of the ball with respect to the bus and the earth are respectively: (a) \(a\) and \(g\) (b) \(a+g\) and \(g-a\) (c) \(\sqrt{a^{2}+g^{2}}\) and \(g\) (d) \(\sqrt{a^{2}+g^{2}}\) and \(a\)

Short Answer

Expert verified
(a) \(a\) and \(g\).

Step by step solution

01

Understanding the Concepts

The problem requires us to find the acceleration of the ball relative to two different reference frames: the bus and the Earth. We know the ball is subject only to gravitational acceleration \(g\) with respect to the Earth.
02

Acceleration with Respect to Earth

Since the only force acting on the ball in the Earth frame is gravity, the acceleration of the ball with respect to the earth is \(g\).
03

Acceleration with Respect to the Bus

To find the acceleration of the ball with respect to the bus, consider the fact that the bus is accelerating with an acceleration \(a\). The relative acceleration of the ball with respect to the bus is the difference in their accelerations. Since the ball does not have an acceleration component along the direction of the bus's acceleration, the relative acceleration is \(a\).
04

Selecting the Correct Option

Based on the above analysis, the correct option for the accelerations with respect to the bus and the Earth is \(a\) and \(g\), respectively. This matches option (a).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration
Acceleration is a measure of how quickly an object's velocity changes. It's a fundamental concept in physics and can be observed in various scenarios. For the bus and the ball in our problem, the understanding of acceleration helps explain how these objects move relative to each other and Earth.

When the bus accelerates, it does so at a rate of \(a\). This means the bus is constantly changing its speed in the forward direction. Now, when the boy drops the ball, the ball is no longer connected to the bus's motion. Its motion relative to the Earth is only affected by gravitational acceleration, \(g\).

However, relative to the bus, we need to consider the bus's constant acceleration. Since the ball is not affected by the bus's acceleration once it's in the air, its acceleration relative to the bus is indeed \(a\). This is because, in the bus's frame, the ball seems to lag behind at the rate the bus is moving forward. Thus, understanding how these motions interrelate gives us the acceleration of \(a\) relative to the bus.
Reference Frames
Reference frames are a view point from which we observe and measure motion. In physics, they serve as the backdrop that determines how we perceive the motion of objects.

In this exercise, two reference frames help us understand the ball's motion: one attached to the bus and the other to the Earth. Changes in motion will appear differently depending on which frame you are observing from.

  • From the Earth's reference frame, the ball experiences gravitational acceleration \(g\). This represents a natural fall towards the ground due to Earth's gravity.
  • In the bus's reference frame, since the bus moves with acceleration \(a\), the ball appears to move backward once released, as it does not continue with the same forward acceleration as the bus.
Each reference frame provides unique insights. The movement of the ball makes perfect sense once we identify the reference frame from which we are analyzing it.
Gravitational Force
Gravitational force is a natural phenomenon by which all things with mass attract each other. On Earth, it gives weight to physical objects and causes them to fall toward the ground when dropped.

The force of gravity, usually denoted as \(g\), is approximately \(9.8 \text{ m/s}^2\). It acts downwards towards the center of the Earth. This universal force influences the ball in our problem once it's dropped, becoming the primary force acting on it relative to the Earth.

When discussing relative motion, recognizing the gravitational force handy. It simplifies understanding different outcomes in scenarios where multiple forces or accelerations could influence an object. Even when considering motion from different frames, gravitational force remains a constant actor, always pulling objects towards Earth with the same official measure of acceleration \(g\).

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