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When the current changes from \(+2 \mathrm{~A}\) to \(-2 \mathrm{~A}\) in \(0.05 \mathrm{~s}\), an emf of \(8 \mathrm{~V}\) is induced in a coil. The coefficient of self-induction of the coil is : (a) \(0.1 \mathrm{H}\) (b) \(0.2 \mathrm{H}\) (c) \(0.4 \mathrm{H}\) (d) \(0.8 \mathrm{H}\)

Short Answer

Expert verified
The coefficient of self-induction is \(0.1 \mathrm{H}\) (option a).

Step by step solution

01

Identify the known values

We are given that the initial current \( I_1 \) is \(+2 \mathrm{~A}\), the final current \( I_2 \) is \(-2 \mathrm{~A}\), and the change occurs over a time period \( \Delta t = 0.05 \mathrm{~s}\). The induced emf (\( \varepsilon \)) given is \(8 \mathrm{~V}\).
02

Understand the formula for the coefficient of self-induction

The formula to calculate the coefficient of self-induction (\( L \)) is derived from the relationship between induced emf, current change, and time, given as \( \varepsilon = -L \frac{\Delta I}{\Delta t} \).
03

Calculate the change in current

Calculate the change in current \( \Delta I \) as: \( \Delta I = I_2 - I_1 = (-2) - (+2) = -4 \mathrm{~A} \).
04

Substitute the values into the formula

Substitute the known values into the formula: \( 8 \mathrm{~V} = -L \frac{-4 \mathrm{~A}}{0.05 \mathrm{~s}} \).
05

Solve for the coefficient of self-induction

Simplify the expression to solve for \( L \): \[ 8 = L \times \frac{4}{0.05} = L \times 80 \]. Rearrange to find \( L \): \( L = \frac{8}{80} = 0.1 \mathrm{H} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Induced EMF
In the world of electromagnetism, electromotive force (or emf) is a key concept. When we talk about the term "induced emf," we're referring to a voltage that is created in a coil when the current in that coil changes. This principle is rooted in Faraday's Law of Electromagnetic Induction.

The idea is simple: a changing magnetic field near a coil induces a voltage across the coil. As a result of this induced voltage, a current may also start to flow if the coil is part of a closed circuit. The induced emf is what we're seeking to determine in this type of physics problem. In our given exercise, the emf is noted to be 8 volts.

Remember:
  • Induced emf is a type of voltage.
  • It is generated due to the change in current flowing through a coil.
  • In our problem, it is a direct consequence of self-induction.
Current Change
When dealing with electrical circuits, current change is a critical aspect. Simply put, current change refers to the variation in the flow of electric charge over time. In our exercise, the current changes from positive 2 Amps to negative 2 Amps. This signals not just a drop but a complete reversal in the direction of the current.

This change occurs over a short interval—specifically, 0.05 seconds. Calculating the magnitude of this change is crucial given by:

\[ \Delta I = I_2 - I_1 = -2 - 2 = -4 \text{ Amps} \]

The negative sign indicates a reversal of direction, which is a significant point when considering the induced emf in the coil.

A few essential points:
  • Change is expressed as \( \Delta I \).
  • Direction matters: Positive to negative indicates reversal.
  • The rate of change over time affects the induced emf.
Coil
A coil in electromagnetic terms is essentially a series of loops made from a conductive material like copper. In our problem, it serves as the medium in which electromagnetic induction takes place. When the current flowing through a coil changes, it results in the creation—or induction—of emf within that same coil.

The coil's characteristics, such as the number of loops and the core material, impact how effectively it can induce emf. In this exercise, we assume a uniform coil whose behavior adheres to the laws of self-induction. This is why the coil can generate an emf of 8 volts when the current changes. Although we don't delve into specifics, know that these elements are pivotal in real-world applications.

Remember about coils:
  • They consist of loops of wire, usually copper.
  • When a current changes, they induce emf within themselves.
  • Properties of the coil affect the efficiency of emf induction.
Inductance Formula
The inductance formula is central to calculating self-induction in a coil. The formula used in the problem is:

\[ \varepsilon = -L \frac{\Delta I}{\Delta t} \]

This equation tells us how the induced emf (\( \varepsilon \)) is related to the inductance (\( L \)), the change in current (\( \Delta I \)), and the time over which this change occurs (\( \Delta t \)). In our exercise:

\[ 8 = -L \frac{-4}{0.05} \]

Simplifying gives us:\
\[ 8 = L \times 80 \]
Thus, \( L = 0.1 \mathrm{~H} \). This is the inductance of the coil, telling us how effectively the coil can induce emf in response to a change in current.

Quick takeaways:
  • Inductance \( L \) measures the coil's efficiency in self-induction.
  • The formula connects emf, current change, and inductance.
  • Solving mathematically gives the value of inductance for the coil involved.

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Most popular questions from this chapter

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