Chapter 29: Problem 2
The perfect formula used for calculating induced emf in a rod moving in a uniform magnetic field is: (a) \(e=\overrightarrow{\mathbf{B}} \cdot(\overrightarrow{\overrightarrow{1}} \times \overrightarrow{\mathbf{v}})\) (b) \(c=\overrightarrow{\mathrm{B}} \cdot(\overrightarrow{1} \cdot \overrightarrow{\mathrm{v}})\) (c) \(e-\overrightarrow{\mathrm{B}} \times(\overrightarrow{1} \cdot \overrightarrow{\mathrm{v}})\) (d) \(e=\overrightarrow{\mathrm{B}} \times(\overrightarrow{1} \times \overrightarrow{\mathrm{v}})\)
Short Answer
Step by step solution
Understanding the Problem
Recall the Right-hand Rule for Lorentz Force
Formula Structure Review
Analyzing Each Option
Selecting the Correct Answer
Verification of the Chosen Formula
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Lorentz force
The force is described by the equation:
\[\overrightarrow{F} = q (\overrightarrow{E} + \overrightarrow{v} \times \overrightarrow{B})\]Here, \(\overrightarrow{F}\) is the Lorentz force, \(q\) is the charge of the particle, \(\overrightarrow{E}\) is the electric field, \(\overrightarrow{v}\) is the velocity of the particle, and \(\overrightarrow{B}\) is the magnetic field.
- The term \(\overrightarrow{v} \times \overrightarrow{B}\) is the cross product, which results in a vector that is perpendicular to both \(\overrightarrow{v}\) and \(\overrightarrow{B}\).
- This perpendicular force is critical in inducing emf as it explains the directional interaction between the movement (velocity) of the rod and the magnetic field (\(\overrightarrow{B}\)).
- The induced emf creates a potential difference across the rod, allowing current to flow if an external circuit connects the ends of the rod.
cross product
The cross product of two vectors \(\overrightarrow{A}\) and \(\overrightarrow{B}\) is denoted as \(\overrightarrow{A} \times \overrightarrow{B}\) and is defined by the following details:
- The magnitude of the cross product is calculated as \(|\overrightarrow{A}||\overrightarrow{B}|\sin\theta\), where \(\theta\) is the angle between the vectors \(\overrightarrow{A}\) and \(\overrightarrow{B}\).
- The direction of the resulting vector is given by the right-hand rule, making it orthogonal to both \(\overrightarrow{A}\) and \(\overrightarrow{B}\).
- First, calculate the intermediate vector \(\overrightarrow{1} \times \overrightarrow{v}\).
- Subsequently, compute the final cross product with the magnetic field \(\overrightarrow{B}\).
- This method ensures that the resulting emf vector aligns correctly to the physics principles and is normal to both interacting fields of motion and magnetic influence.
right-hand rule
- Extend your right hand with your fingers pointing in the direction of the first vector \(\overrightarrow{A}\).
- Rotate your palm so that you can curl your fingers toward the direction of the second vector \(\overrightarrow{B}\).
- Your thumb, when extended, will indicate the direction of the resultant vector (cross product).
- Place your thumb in the direction of the velocity \(\overrightarrow{v}\) of the rod.
- Let your fingers align with the magnetic field direction \(\overrightarrow{B}\).
- Your palm then points in the direction of the force on the positive charge, illustrating the direction of the induced current.