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The perfect formula used for calculating induced emf in a rod moving in a uniform magnetic field is: (a) \(e=\overrightarrow{\mathbf{B}} \cdot(\overrightarrow{\overrightarrow{1}} \times \overrightarrow{\mathbf{v}})\) (b) \(c=\overrightarrow{\mathrm{B}} \cdot(\overrightarrow{1} \cdot \overrightarrow{\mathrm{v}})\) (c) \(e-\overrightarrow{\mathrm{B}} \times(\overrightarrow{1} \cdot \overrightarrow{\mathrm{v}})\) (d) \(e=\overrightarrow{\mathrm{B}} \times(\overrightarrow{1} \times \overrightarrow{\mathrm{v}})\)

Short Answer

Expert verified
The correct formula is option (d): \(e=\overrightarrow{\mathrm{B}} \times(\overrightarrow{1} \times \overrightarrow{\mathrm{v}})\).

Step by step solution

01

Understanding the Problem

We need to determine the correct formula for calculating the induced electromotive force (emf) in a rod moving in a uniform magnetic field. The emf is related to the magnetic field, length, and velocity of movement of the rod.
02

Recall the Right-hand Rule for Lorentz Force

According to electromagnetic theory, the induced emf in a moving rod is due to the Lorentz force. The correct formulation uses the cross product of the magnetic field (\(\overrightarrow{\mathrm{B}}\)) and the velocity vector (\(\overrightarrow{\mathrm{v}}\)), multiplied by the length vector (\(\overrightarrow{\mathbf{1}}\)).The right-hand rule is used to determine the direction of the force, which affects how these vectors are ordered in the cross product.
03

Formula Structure Review

In physics, the expression for induced emf in terms of cross products is traditionally given as \(e = \overrightarrow{\mathrm{B}} \times (\overrightarrow{1} \times \overrightarrow{\mathrm{v}})\). This tells us the emf is perpendicular to both the magnetic field and velocity, calculated using two cross products.
04

Analyzing Each Option

- **Option (a)**: \(e=\overrightarrow{\mathbf{B}} \cdot(\overrightarrow{\overrightarrow{1}} \times \overrightarrow{\mathbf{v}})\) suggests a dot product, which is incorrect for emf.- **Option (b)**: \(c=\overrightarrow{\mathrm{B}} \cdot(\overrightarrow{1} \cdot \overrightarrow{\mathrm{v}})\) uses a dot product, which is not appropriate for magnetic interactions relating to emf.- **Option (c)**: \(e-\overrightarrow{\mathrm{B}} \times(\overrightarrow{1} \cdot \overrightarrow{\mathrm{v}})\) is mentioned oppositely and lacks proper format for emf determination.- **Option (d)**: \(e=\overrightarrow{\mathrm{B}} \times(\overrightarrow{1} \times \overrightarrow{\mathrm{v}})\) correctly represents the cross product.
05

Selecting the Correct Answer

The correct expression for the induced emf considering magnetic field and movement of a rod is a cross product, thus from our analysis, option **(d)** is the correct formula: \(e=\overrightarrow{\mathrm{B}} \times(\overrightarrow{1} \times \overrightarrow{\mathrm{v}})\).
06

Verification of the Chosen Formula

The chosen formula, option (d), adheres to the physics principle where the emf is generated perpendicular to both the movement and magnetic field, accurately applying the triple vector product.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lorentz force
The Lorentz force is a fundamental concept in electromagnetism that explains how electric and magnetic fields interact with charged particles. It is responsible for the motion of charged particles in magnetic fields, which is essential for understanding how electromotive force (emf) is induced.
The force is described by the equation:

\[\overrightarrow{F} = q (\overrightarrow{E} + \overrightarrow{v} \times \overrightarrow{B})\]Here, \(\overrightarrow{F}\) is the Lorentz force, \(q\) is the charge of the particle, \(\overrightarrow{E}\) is the electric field, \(\overrightarrow{v}\) is the velocity of the particle, and \(\overrightarrow{B}\) is the magnetic field.
  • The term \(\overrightarrow{v} \times \overrightarrow{B}\) is the cross product, which results in a vector that is perpendicular to both \(\overrightarrow{v}\) and \(\overrightarrow{B}\).
  • This perpendicular force is critical in inducing emf as it explains the directional interaction between the movement (velocity) of the rod and the magnetic field (\(\overrightarrow{B}\)).
  • The induced emf creates a potential difference across the rod, allowing current to flow if an external circuit connects the ends of the rod.
By understanding Lorentz force, students can grasp how movement through a magnetic field generates electrical energy in conductors, bridging the gap between mechanical motion and electrical signals.
cross product
In the world of physics and vector mathematics, a cross product is a crucial operation used to determine a vector that is perpendicular to two given vectors. When discussing induced emf, the cross product comes into play because it helps in calculating the force direction on the moving rod.
The cross product of two vectors \(\overrightarrow{A}\) and \(\overrightarrow{B}\) is denoted as \(\overrightarrow{A} \times \overrightarrow{B}\) and is defined by the following details:
  • The magnitude of the cross product is calculated as \(|\overrightarrow{A}||\overrightarrow{B}|\sin\theta\), where \(\theta\) is the angle between the vectors \(\overrightarrow{A}\) and \(\overrightarrow{B}\).
  • The direction of the resulting vector is given by the right-hand rule, making it orthogonal to both \(\overrightarrow{A}\) and \(\overrightarrow{B}\).
In the scenario of a moving rod in a magnetic field, the essential cross product is \(\overrightarrow{B} \times (\overrightarrow{1} \times \overrightarrow{v})\). This product determines the direction of the induced emf by evaluating the sequence of interactions:
  • First, calculate the intermediate vector \(\overrightarrow{1} \times \overrightarrow{v}\).
  • Subsequently, compute the final cross product with the magnetic field \(\overrightarrow{B}\).
  • This method ensures that the resulting emf vector aligns correctly to the physics principles and is normal to both interacting fields of motion and magnetic influence.
Understanding the cross product offers an insightful view of vector interactions, enabling students to apply these principles in practical situations involving electromagnetism.
right-hand rule
The right-hand rule is an intuitive method for determining the direction of vectors resulting from certain operations, most notably the cross product, such as in generating induced emf in a moving rod. By teaching students how to use their hands as a tool for prediction, the right-hand rule helps in visualizing vector directions.Here's how to apply the right-hand rule for the cross product \(\overrightarrow{A} \times \overrightarrow{B}\):

  • Extend your right hand with your fingers pointing in the direction of the first vector \(\overrightarrow{A}\).
  • Rotate your palm so that you can curl your fingers toward the direction of the second vector \(\overrightarrow{B}\).
  • Your thumb, when extended, will indicate the direction of the resultant vector (cross product).
Applying this to magnetic forces, when a rod moves through a magnetic field, you use the right-hand rule to find the direction of the induced emf:
  • Place your thumb in the direction of the velocity \(\overrightarrow{v}\) of the rod.
  • Let your fingers align with the magnetic field direction \(\overrightarrow{B}\).
  • Your palm then points in the direction of the force on the positive charge, illustrating the direction of the induced current.
This simple mnemonic technique is invaluable for visual learners and aids greatly in understanding three-dimensional vector problems. By mastering the right-hand rule, students can confidently predict and verify the direction of the electromagnetic interactions.

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Most popular questions from this chapter

Two straight super-conducting rails form an angle \(\theta\) where their ends are joined a conducting bar having \(R_{0}\) resistance per unit length in contact with the rails and forming an isosceles triangle with them. The bar starts at the vertex at time \(t=0\) and moves with constant velocity \(v\) to right. A magnetic field \(B\) is present into the region (shown in figure). Find the force exerted by external agent to maintain constant velocity to the rod: (a) \(\frac{2 B^{2} v^{2} t}{R_{0}} \tan \frac{\theta}{2}\) (b) \(\frac{B^{2} v^{2} t}{R_{0}} \tan \frac{\theta}{2}\) (c) \(\frac{B^{2} v^{2} t}{R_{0}}\) (d) none of these

Two flat horizontal coils are mounted as shown. Which one of the following actions will not cause the sensitive galvanometer \(G\) to deflect? (a) Coils stationary and coil 1 moves upwards with \(K_{1}\) and \(K_{2}\) closed (b) Both coils stationary, \(K_{2}\) closed and \(K_{1}\) switched on or off (c) With \(K_{1}\) and \(K_{2}\) closed, a variable resistance \(R\) is increased and decreased rapidly (d) Both coils stationary, \(K_{1}\) closed and \(K_{2}\) switched on or off

A small circular loop of radius \(r\) is placed inside a circular loop of radius \(R(R \gg r)\). The loops are coplanar and their centres coincide. The mutual inductance of the system is proportional to: (a) \(r / R\) (b) \(r^{2} / R\) (c) \(r / R^{2}\) (d) \(r^{2} / R^{2}\)

A closed circuit consists of a source of \(\operatorname{emf} E\) and an inductor coil of inductance \(L\), connected in series. The active resistance of whole circuit is \(R\). At the moment \(t=0\), inductance of coil abruptly decreased to \(L / n\). Then current in the circuit immediately after, is : (a) zero (b) \(E / R\) (c) \(\frac{n E}{R}\) (d) \(\frac{E}{n R}\)

An Indian ship with a vertical conducting mass navigates the Indian ocean in the latitude of magnetic equator. To induce the greatest emf in the mast, the ship should proceed : (a) northward (b) southward (c) eastward (d) none of these

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