Chapter 28: Problem 9
A magnetic wire of dipole moment \(4 \pi \mathrm{Am}^{2}\) is bent in the form of semicircle. The new magnetic moment is: (a) \(4 \pi \mathrm{Am}^{2}\) (b) \(8 \pi \mathrm{Am}^{2}\) (c) \(4 \mathrm{Am}^{2}\) (d) none of these
Short Answer
Expert verified
The new magnetic moment is \( 2 \pi \mathrm{Am}^{2} \), none of the options match.
Step by step solution
01
Understand the Problem
We have a magnetic wire with a given magnetic dipole moment of \( 4 \pi \mathrm{Am}^{2} \) which is bent into the shape of a semicircle. We need to determine the new magnetic moment of this structure.
02
Recall Magnetic Moment Formula
The magnetic moment \( M \) is given by the product of the current \( I \) and the area \( A \) of the loop, so \( M = I \times A \). Here the magnetic dipole is initially straight and now it's bent into a semicircle.
03
Calculate Initial Area Requirement
The wire initially formed a full circle with a magnetic dipole moment of \( 4 \pi \mathrm{Am}^{2} \). The area of the circle would be \( A = \pi r^2 \) where \( r \) is the radius of the circle.
04
Determine Radius of Circle
Since the dipole moment is \( 4 \pi \mathrm{Am}^{2} \), this must equal \( I \times \pi r^2 \). Therefore, \( I \times \pi r^2 = 4 \pi \). This helps to find the expression for \( I \, r^2 \) in terms of the original dipole moment.
05
Calculate the Area of the Semicircle
When the wire is bent into a semicircle, the area is halved. Thus, the new area \( A \) of the semicircle is \( \frac{1}{2} \pi r^2 \).
06
Compute New Magnetic Moment
The new magnetic moment \( M' \) is \( I \times \frac{1}{2} \pi r^2 \). From Step 4, because \( I \times \pi r^2 = 4 \pi \), \( I \times \frac{1}{2} \pi r^2 = 2 \pi \). Thus, the new magnetic moment is \( 2 \pi \mathrm{Am}^{2} \).
07
Compare with Provided Options
The calculated new magnetic moment for the semicircle wire is \( 2 \pi \mathrm{Am}^{2} \), which does not exactly match any of the given options.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnetic Dipole
A magnetic dipole is a magnetic entity characterized by a pair of equal and opposite magnetic poles, similar to a small bar magnet. Fundamentally, a magnetic dipole moment is a vector quantity that determines the torque a magnetic field would exert on the dipole. This is crucial to understanding the behavior of magnetic objects under magnetic fields.
To picture a dipole, imagine a loop of electric current or a pair of closely spaced magnetic charges. In this scenario, the magnetic dipole moment (\( \mathbf{m} \)) is calculated as the product of the current (\( I \)) flowing through the loop and the area (\( A \)) the loop encloses:
To picture a dipole, imagine a loop of electric current or a pair of closely spaced magnetic charges. In this scenario, the magnetic dipole moment (\( \mathbf{m} \)) is calculated as the product of the current (\( I \)) flowing through the loop and the area (\( A \)) the loop encloses:
- \( \mathbf{m} = I \times A \)
Semicircle
A semicircle is half of a circle and presents an interesting geometric configuration when considering magnetic dipoles. Bending the wire into a semicircle fundamentally reduces the area enclosed by the wire, which directly impacts the magnetic moment, as it is proportional to the area.
Starting with a wire formed as a full circle, the total area is \( \pi r^2 \), where \( r \) is the radius. When shaped into a semicircle, this area is halved, so the new area becomes:
Starting with a wire formed as a full circle, the total area is \( \pi r^2 \), where \( r \) is the radius. When shaped into a semicircle, this area is halved, so the new area becomes:
- \( A_{\text{semi}} = \frac{1}{2} \pi r^2 \)
Current and Area Relationship
The intricate relationship between current and the area of a magnetic setup is crucial to understanding the magnetic moment. The earlier formula \( M = I \times A \) is direct evidence of this relationship. Here, both current (\( I \)) and area (\( A \)) serve as determinants of the magnetic moment of a loop.
When the wire is initially a full circle, its magnetic moment is determined by the full area it encloses. However, as described before, transforming this into a semicircle cuts its magnetic influence by reducing the area. This means the wire, though carrying the same current, exhibits a different magnetic moment due to its reduced effective area.
When the wire is initially a full circle, its magnetic moment is determined by the full area it encloses. However, as described before, transforming this into a semicircle cuts its magnetic influence by reducing the area. This means the wire, though carrying the same current, exhibits a different magnetic moment due to its reduced effective area.
- Original: Full circle \( 4 \pi \mathrm{Am}^{2} \)
- Modified: Semicircle \( 2 \pi \mathrm{Am}^{2} \)