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Mark correct option or options: (a) In the absence of an electric field, electrons move in straight lines between collisions (b) Relaxation time is of order \(10^{-14}\) second (c) Resistivity is inversely proportional to relaxation time when number of electrons per unit volume of material remains constant (d) All the above

Short Answer

Expert verified
All statements (a), (b), (c), and (d) are correct.

Step by step solution

01

Understanding Electron Movement Without External Influence

In the absence of an electric field, electrons indeed move in straight lines between collisions. This is because there is no force acting on the electrons to change their velocity, except during collisions. Therefore, statement (a) is correct.
02

Considering Relaxation Time Value

Relaxation time refers to the average time between two successive collisions for an electron. In many metals, the relaxation time is indeed of the order of \(10^{-14}\) seconds. Thus, statement (b) is correct.
03

Analyzing the Relation Between Resistivity and Relaxation Time

Resistivity \(\rho\) is given by the formula \(\rho = \frac{m}{n e^2 \tau}\), where \(m\) is the electron mass, \(n\) is the electron number density, \(e\) is the electron charge, and \(\tau\) is the relaxation time. Hence, the resistivity is inversely proportional to the relaxation time when the number of electrons per unit volume remains constant. Therefore, statement (c) is correct.
04

Evaluating the Overall Statement

Since all individual statements (a), (b), and (c) are correct, (d) "All the above" is also a correct choice.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Movement
In materials, particularly in metals, electrons move freely due to their minimal mass and low binding energy. Under normal conditions, without the influence of an external electric field, these electrons undergo random motion. While moving, electrons travel straight paths between collisions with other atoms or impurities present in the material. These collisions are the primary interruptions to their paths, causing changes in direction.
  • The absence of an electric field ensures no net movement of electrons in any particular direction.
  • This randomness without directional bias makes the average velocity zero.
When an electric field is applied, it imposes a force on the electrons, giving them a preferred direction of movement along with the field. It's crucial to understand this concept because it is the basis of how electric current is created and sustained.
Relaxation Time
Relaxation time, denoted usually by the symbol \( \tau \), is an essential concept in understanding the microscopic behavior of electron flow in conductors. It represents the average time interval between successive collisions of an electron with fixed ions in a lattice.
  • Relaxation time affects the conduction properties of materials.
  • It's typically very small, often in the order of \(10^{-14}\) seconds, especially in metals.
Short relaxation times imply more frequent collisions, potentially leading to higher resistivity in a material. Conversely, a longer relaxation time indicates fewer collisions per unit of time, allowing electrons to drift more orderly along the material.
Resistivity
Resistivity is a material property that quantifies how strongly a material opposes the flow of electric current. It is often denoted by the symbol \( \rho \) and can be mathematically expressed by the equation:\[\rho = \frac{m}{n e^2 \tau}\]where:
  • \(m\) is the electron mass,
  • \(n\) is the electron number density,
  • \(e\) is the elementary charge of an electron,
  • \(\tau\) is the relaxation time.
An increase in relaxation time \(\tau\) reduces the resistivity \(\rho\), making the material a better conductor. This inverse relationship points out why materials with a higher relaxation time can conduct electricity more efficiently, given that other factors, like electron density, remain constant. Understanding resistivity helps identify materials suitable for different electrical components, aiding design and usage in practical applications.

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Most popular questions from this chapter

A silver and copper voltameters are connected in parallel to a \(12 \mathrm{~V}\) battery of negligible resistance. At what rate is energy being delivered by the battery, if in 30 minutes, \(1 \mathrm{~g}\) of silver and \(1.8 \mathrm{~g}\) of copper are deposited ? (Assume electrochemical equivalent of silver \(=11.2 \times 10^{-7} \mathrm{~kg} / \mathrm{C}\), electrochemical equivalent of copper \(\left.=6.6 \times 10^{-7} \mathrm{~kg} / \mathrm{C}\right)\) (a) \(42.2 \mathrm{~J} / \mathrm{s}\) (b) \(40.4 \mathrm{~J} / \mathrm{s}\) (c) \(24.1 \mathrm{~J} / \mathrm{s}\) (d) \(20.4 \mathrm{~J} / \mathrm{s}\)

A lamp having tungsten filament consumes \(50 \mathrm{~W}\). Assume the temperature coefficient of resistance for tungsten is \(4.5 \times 10^{-3} /{ }^{\circ} \mathrm{C}\) and the room temperature is \(20^{\circ} \mathrm{C}\). If the lamp burns, the temperature of its filament 13 becomes \(2500^{\circ} \mathrm{C}\), then the power consumed at the moment switch is on, is : (a) \(608 \mathrm{~W}\) (b) \(710 \mathrm{~W}\) (c) \(215 \mathrm{~W}\) (d) \(580 \mathrm{~W}\)

A piece of metal weighing \(200 \mathrm{~g}\) is to be electroplated with \(5 \%\) of its weight in gold. How long it would take to deposite the required amount of gold, if the strength of the available current is \(2 \mathrm{~A} ?\) (Given: Electrochemical equivalent of \(\mathrm{H}=0.1044 \times 10^{-4} \mathrm{~g} / \mathrm{C}\), atomic weight of .gold \(=197.1\) atomic weight of hydrogen \(=1.008\) ) (a) \(7347.9 \mathrm{~s}\) (b) \(7400.5 \mathrm{~s}\) (c) \(7151.7 \mathrm{~s}\) (d) \(70 \mathrm{~s}\)

The \(80 \Omega\) galvanometer deflects full scale for a potential of \(20 \mathrm{mV}\). A voltmeter deflecting full scale of \(5 \mathrm{~V}\) is to made using this galvanometer. We must connect : (a) a resistance of \(19.92 \mathrm{k} \Omega\) parallel to the galvanometer (b) a resistance of \(19.92 \mathrm{k} \Omega\) in series with the galvanometer (c) a resistance of \(20 \mathrm{k} \Omega\) parallel to the galvanometer (d) a resistance of \(20 \mathrm{k} \Omega\) in series with the galvanometer

A wire with a resistance of \(20 \Omega\) is drawn out so that its length becomes thrice its original length. The new resistance is: (a) \(60 \Omega\) (b) \(\frac{2 \theta}{3} \Omega\) (c) \(180 \Omega\) (d) \(18 \Omega\)

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