Chapter 21: Problem 37
The first diffraction minimum due to single slit diffraction is \(\theta\), for a light of wavelength \(5000 \AA\). If the width of the slit is \(1 \times 10^{-4} \mathrm{~cm}\), then the value of \({ }^{\prime} \theta^{\prime}\) is: (a) \(30^{\circ}\) (b) \(45^{\circ}\) (c) \(60^{\circ}\) (d) \(15^{\circ}\)
Short Answer
Step by step solution
Understanding the Problem
Convert Wavelength Units
Apply Single Slit Diffraction Formula
Calculate \(\sin \theta\)
Determine \(\theta\)
Choose the Correct Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Wavelength Conversion
- \(5000 \text{Ã…} = 5000 \times 10^{-8} \text{cm}\)
Diffraction Minimum
- \(a\) is the slit width
- \(\lambda\) is the wavelength of the light
- \(m\) is the order of the minimum, starting from 1 for the first minimum
Sinusoidal Calculations
- \(\sin \theta = 0.5\)
Optics Calculations
- Estimating angles where light energy is negligible (dark bands)
- Ensuring accurate specification of optical instrument parameters Using reliable formulas enables us to make accurate predictions in simulations, experiments, and real-world applications. This foundational skill is pivotal in the broader field of optical science and technology.