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The angular relationship between the vectors \(\vec{A}\) and \(\vec{B}\) is: $$ \overrightarrow{\mathbf{A}}=3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}, \quad \overrightarrow{\mathbf{B}}=2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}} $$ (a) \(180^{\circ}\) (b) \(90^{\circ}\) (c) \(0^{\circ}\) (d) \(240^{\circ}\)

Short Answer

Expert verified
The angle between \(\vec{A}\) and \(\vec{B}\) is \(90^{\circ}\).

Step by step solution

01

Calculate the Dot Product

To find the angular relationship (angle) between two vectors, we first need to calculate their dot product. The dot product is given by:\[ \vec{A} \cdot \vec{B} = A_xB_x + A_yB_y + A_zB_z \]Substitute the values:\[ \vec{A} \cdot \vec{B} = (3)(2) + (2)(1) + (4)(-2) \]\[ = 6 + 2 - 8 \]\[ = 0 \]
02

Determine If Vectors Are Perpendicular

The dot product of two vectors is zero if and only if the vectors are perpendicular to each other. Since the dot product calculated in Step 1 is zero, the vectors \(\vec{A}\) and \(\vec{B}\) are perpendicular.
03

Conclude the Angular Relationship

Since the vectors \(\vec{A}\) and \(\vec{B}\) are perpendicular, the angle between them is \(90^{\circ}\). Hence, the correct answer is option \(b\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
The dot product is a fundamental concept in vector math. It can help determine the relationship between two vectors. The dot product of two vectors \(\vec{A}\) and \(\vec{B}\) is calculated as the sum of the products of their corresponding components:\[ \vec{A} \cdot \vec{B} = A_xB_x + A_yB_y + A_zB_z \]For example, using given vectors \(\vec{A}=3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}\) and \(\vec{B}=2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}\), the dot product would be:
  • Multiply the \(i\) components: \(3 \cdot 2 = 6\)
  • Multiply the \(j\) components: \(2 \cdot 1 = 2\)
  • Multiply the \(k\) components: \(4 \cdot (-2) = -8\)
  • Sum these products: \(6 + 2 - 8 = 0\)
A result of zero is significant and will be discussed in the next section.
Understanding the dot product is crucial for analyzing vector behaviors and interactions in space.
Angular Relationship
Once you've calculated the dot product, you can determine the "angular relationship" between vectors. This term describes the angle formed by two vectors. The relationship is linked to the value of their dot product.If the dot product is \(0\), this indicates that the angle between the vectors is \(90^{\circ}\). These vectors form a right angle and are known as perpendicular vectors (more on that later). When the dot product is not zero, the cosine of the angle can be found using:\[ \cos(\theta) = \frac{\vec{A} \cdot \vec{B}}{\| \vec{A} \| \| \vec{B} \|} \]Where:
  • \(\vec{A} \cdot \vec{B}\) is the dot product
  • \(\| \vec{A} \|\) and \(\| \vec{B} \|\) are the magnitudes of vectors \(\vec{A}\) and \(\vec{B}\), respectively
However, in our specific example, because the dot product is zero, we instantly know the angle is \(90^{\circ}\) without further calculations.
Perpendicular Vectors
Perpendicular vectors have a special relationship. They intersect at a right angle (\(90^{\circ}\)). This is identified when their dot product is zero.Vectors are often used to model physical phenomena like forces, velocities, and displacements. Recognizing perpendicularity becomes useful in scenarios like ensuring two forces do not impact each other.In our exercise, we've determined that vectors \(\vec{A}\) and \(\vec{B}\) are perpendicular because their dot product is zero. This concept is important, not just mathematically, but also practically in physics and engineering contexts.
To sum up, a zero dot product is a clear indicator of perpendicular vectors and their \(90^{\circ}\) angular relationship.

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Most popular questions from this chapter

For what value of \(x\), will the two vectors \(\overrightarrow{\mathrm{A}}=2 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}-x \hat{\mathrm{k}}\) and \(\overrightarrow{\mathrm{B}}=2 \hat{1}-\hat{\mathrm{j}}-3 \hat{k}\) are perpendicular to each other? (a) \(x=-2 / 3\) (b) \(x=3 / 2\) (c) \(x=-4 / 3\) (d) \(x=2 / 3\)

Magnetic force on a moving positive charge is defined by \(\overrightarrow{\mathbf{r}}=q \overrightarrow{\mathbf{v}} \times \overrightarrow{\mathbf{B}}\) Here, \(\vec{v}=\) velocity of the body \(\overrightarrow{\mathrm{B}}=\) magnetic field If velocity of charged particle is directed vertically upward and magnetic force is directed towards west, the direction of magnetic field is: (a) north (b) east (c) west (d) south

The angle between \(\overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}}\) and \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}\) is : (a) \(90^{\circ}\) (b) \(180^{\circ}\) (c) \(60^{\circ}\) (d) none of these

If three vectors \(x \overrightarrow{\mathbf{a}}-2 \overrightarrow{\mathbf{b}}+3 \vec{c},-2 \overrightarrow{\mathbf{a}}+y \overrightarrow{\mathbf{b}}-4 \overrightarrow{\mathbf{c}}\) and \(-z \vec{b}+2 \vec{c}\) are coplanar, where \(\vec{a} \cdot \vec{b} \cdot \vec{c}\) are unit (or any) vectors, then (a) \(x y+3 z x-3 z=4\) (b) \(2 x y-2 z x-3 z-4=0\) (c) \(4 x y-3 z x+3 z=4\) (d) \(x y-2 z x+3 z-4=0\)

The resultant of two vectors \(\mathbf{P}\) and \(\mathrm{Q}\) is \(\mathbf{R}\). If the vector \(\overrightarrow{\mathrm{Q}}\) is reversed, then the resultant becomes \(\overrightarrow{\mathbf{S}}\), then choose the correct option (a) \(R^{2}+S^{2}=2\left(P^{2}-Q^{2}\right)\) (b) \(R^{2}+S^{2}=2\left(P^{2}+Q^{2}\right)\) (c) \(R^{2}+S^{2}=\left(P^{2}-Q^{2}\right)\) (d) \(R^{2}-S^{2}=2\left(P^{2}+Q^{2}\right)\)

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