Chapter 2: Problem 29
The position vector of a moving particle at time \(t\) is \(\overrightarrow{\mathrm{r}}=3 \hat{\mathrm{i}}+4 t^{2} \hat{\mathrm{j}}-t^{3} \mathrm{k}\). Its displacement during the time interval \(t=1 \mathrm{~s}\) to \(t=3 \mathrm{~s}\) is : (a) \(\hat{j}-\hat{k}\) (b) \(3 \hat{i}+4 \hat{j}-\hat{k}\) (c) \(9 \hat{\uparrow}+36 \hat{\jmath}-27 \hat{k}\) (d) \(32 \hat{j}-26 \hat{\mathbf{k}}\)
Short Answer
Step by step solution
Understand the Position Vector
Find Initial and Final Vectors
Calculate Displacement Vector
Select the Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Position Vector
- \( \hat{\mathrm{i}} \): along the x-axis
- \( \hat{\mathrm{j}} \): along the y-axis
- \( \hat{\mathrm{k}} \): along the z-axis
Components of Vectors
Let's break down the given position vector:
- The \( i \)-component is constant and remains \( 3 \hat{\mathrm{i}} \), meaning there's no change along the x-axis over time.
- The \( j \)-component, \( 4t^2 \hat{\mathrm{j}} \), increases with the square of time, indicating acceleration in the y-direction.
- The \( k \)-component, \( -t^3 \hat{\mathrm{k}} \), decreases with the cube of time, exhibiting an increasing negative movement along the z-axis.
Displacement Calculation
This case involves a time interval from \( t=1 \mathrm{~s} \) to \( t=3 \mathrm{~s} \).
Substituting time values:
- Initial position: \( \overrightarrow{\mathrm{r}}(1) = 3\hat{\mathrm{i}} + 4\hat{\mathrm{j}} - \hat{\mathrm{k}} \)
- Final position: \( \overrightarrow{\mathrm{r}}(3) = 3\hat{\mathrm{i}} + 36\hat{\mathrm{j}} - 27\hat{\mathrm{k}} \)
\[\overrightarrow{\mathrm{d}} = \overrightarrow{\mathrm{r}}(3) - \overrightarrow{\mathrm{r}}(1) = (3\hat{\mathrm{i}} + 36\hat{\mathrm{j}} - 27\hat{\mathrm{k}}) - (3\hat{\mathrm{i}} + 4\hat{\mathrm{j}} - \hat{\mathrm{k}})\]
Simplified, the displacement is \( 0\hat{\mathrm{i}} + 32\hat{\mathrm{j}} - 26\hat{\mathrm{k}} \). This indicates the shift in the particle's position over the specified time interval.
Time Interval in Physics
For this problem, the time interval analyzed is from \( t=1 \) second to \( t=3 \) seconds. Understanding time intervals allows physicists to calculate changes and predict future states of objects in motion.
Key aspects of time intervals in motion calculations:
- Time intervals help determine how much an object's position or velocity has changed.
- In combination with position vectors, they are used to find displacement, which highlights how far and in what direction an object has moved.
- They also play a role in calculating average velocities and accelerations, aiding in comprehending an object's dynamics more thoroughly.