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What is the property of two vectors \(P\) and \(Q\) i \(\vec{P}+\vec{Q}=\vec{P}-\vec{Q} ?\) (a) \(P\) is null vector (b) \(Q\) is null vector (c) \(P\) is proper vector (d) \(Q\) is proper vector

Short Answer

Expert verified
The property of the vectors is that \( Q \) is a null vector.

Step by step solution

01

Understanding the Vector Equation

We start by examining the given equation \( \vec{P} + \vec{Q} = \vec{P} - \vec{Q} \). This equation states that the resultant of adding vectors \( \vec{P} \) and \( \vec{Q} \) is the same as subtracting \( \vec{Q} \) from \( \vec{P} \).
02

Simplifying the Equation

Subtract \( \vec{P} \) from both sides of the equation to eliminate it from one side: \( \vec{Q} = -\vec{Q} \). This simplifies to the situation where the vectors \( \vec{Q} \) and \(-\vec{Q} \) are equal.
03

Solving the Simplified Equation

The equation \( \vec{Q} = -\vec{Q} \) implies that vector \( \vec{Q} \) must have a magnitude of zero so that it equals its negative. Therefore, \( \vec{Q} \) is a null vector.
04

Concluding the Solution

Based on the steps above, we have shown that \( \vec{Q} \) is a null vector since only a null vector can equal its own negative. This satisfies the condition of the original equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Null Vector
In vector mathematics, the concept of a null vector is crucial. A null vector, also known as a zero vector, is a vector with all its components equal to zero. Hence, its magnitude is zero as well. When a vector \( \vec{Q} \) has the property that \( \vec{Q} = -\vec{Q} \), this indicates that both its direction and magnitude must be exactly zero. This is because for any non-zero vector, its negative would have the opposite direction but equal magnitude. However, a null vector has no distinctive direction, and its effect during any operation like addition or subtraction is neutral, making it an essential concept in vector algebra.
If we consider the original equation, \( \vec{P} + \vec{Q} = \vec{P} - \vec{Q} \), and find that \( \vec{Q} \) must be a null vector, this is consistent with the idea that only a vector with zero magnitude can satisfy \( \vec{Q} = -\vec{Q} \).
Introduction to Vector Addition
Vector addition is a vital operation when handling vectors. It involves creating a resultant vector from two or more vectors. This is done by adding corresponding components of the vectors together. Let's say we have two vectors, \( \vec{A} \) and \( \vec{B} \). The vector addition operation results in a new vector, \( \vec{C} = \vec{A} + \vec{B} \), where the components of \( \vec{C} \) are the sums of the corresponding components of \( \vec{A} \) and \( \vec{B} \).
  • Commutative Property: \( \vec{A} + \vec{B} = \vec{B} + \vec{A} \)
  • Associative Property: \( (\vec{A} + \vec{B}) + \vec{C} = \vec{A} + (\vec{B} + \vec{C}) \)
According to the original problem, when two vectors can be added, such as \( \vec{P} + \vec{Q} \), the resultant vector should have been affected; yet the addition and subtraction leading to the same outcome suggested something unique about \( \vec{Q} \). This was identified as the null vector, indicating its magnitude was zero, making its presence or absence during calculation inconsequential.
Exploring Vector Subtraction
Vector subtraction is akin to its cousin vector addition, except it involves taking one vector away from another. This is typically handled by reversing the direction of the vector being subtracted and then performing vector addition. For instance, for vectors \( \vec{A} \) and \( \vec{B} \), \( \vec{C} = \vec{A} - \vec{B} \) is the same as \( \vec{C} = \vec{A} + (-\vec{B}) \), where \(-\vec{B}\) is the vector with the same magnitude as \( \vec{B} \) but pointing in the opposite direction. Vector subtraction is particularly useful when calculating the difference in position, velocity, or other vector quantities.
In the problem at hand, the subtraction \( \vec{P} - \vec{Q} \) occurring and giving the same result as \( \vec{P} + \vec{Q} \) immediately alerted us to the potential that the presence of a null vector was neutralizing the effect of vector subtraction, thus reinforcing \( \vec{Q} \) as a null vector. This ensured it was indeed influencing the outcome, or lack thereof, during both vector operations.

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