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A plane mirror is placed along positive \(x\) -axis facing along positive \(y\) -axis. The equation of a linear object is \(x=y\). The equation of its image is: (a) \(x=y\) (b) \(x+y=0\) (c) \(2 x+y=0\) (d) none of these

Short Answer

Expert verified
(b) \(x+y=0\)

Step by step solution

01

Understanding the Problem

We have a plane mirror placed along the positive x-axis, meaning it is parallel to the y-axis and reflects objects across the x-axis. The object is a line given by the equation \(x = y\). We need to find the equation of the image of this line after reflection.
02

Determine the Reflection Axis

As the mirror is placed along the positive x-axis, the reflection will be across the x-axis. Reflections across a line parallel to the y-axis like the x-axis involve flipping the y-coordinates.
03

Reflect the Line Equation

The original line equation is \(x = y\). To find the image, we reflect across the x-axis by changing the sign of the y-coefficient in the equation. The transformed equation becomes \(x = -y\).
04

Rearrange the Equation

The equation \(x = -y\) can be rearranged to \(x + y = 0\), which represents the line after reflection.
05

Compare with Given Options

Compare the obtained equation \(x + y = 0\) with the options provided. Option (b) matches our result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reflection Across X-Axis
When an object, such as a line, is reflected across the x-axis, the reflection process involves a simple yet crucial change. Imagine flipping a pancake; it's still the same pancake, just turned upside down. This is exactly how the reflection across the x-axis works. You take the position along the y-axis and flip its direction.

Consider the original line represented by the equation \( x = y \). To reflect this line across the x-axis, you essentially flip the y-values. This means changing the signs of the y-coordinates. As a result, for every point \( (x, y) \), its reflected counterpart will be \( (x, -y) \). This transforms the line equation into \( x = -y \).

Remember that in these reflections:
  • The x-coordinate remains the same.
  • The sign of the y-coordinate flips.
Understanding this basic transformation helps in intuitively solving problems involving reflections across axes.
Transformation of Line Equation
Transforming the equation of a line when dealing with reflections is all about understanding how each point on the line changes its location.

Normally, a line equation like \( x = y \) describes all the points that satisfy this condition. These are the points where the x-coordinate and y-coordinate are equal. However, upon reflecting across the x-axis, the roles these coordinates play change slightly, introducing a negative sign to the y-coordinate.

The reflection effectively turns \( y \) into \( -y \), which leads to the new equation: \( x = -y \). But to compare it with typical line equations, where we often want it in a standard form, you might rearrange this to: \( x + y = 0 \).

Here’s a quick tip:
  • For reflections across x-axis: Flip the y-coefficients.
  • Rearrange to standard form if needed for clearer comparison.
Understanding these steps helps to process transformations and reflections efficiently.
Image Formation by Mirrors
In the world of mirror reflections, image formation is not just about what we see, but about how images are mathematically described.

A plane mirror, being flat, isn't like a funhouse mirror. It does not distort shapes; it simply flips them over the axis it lies on. Imagine standing in front of a plane mirror — what you see is a reflection that looks like you are flipped from left to right or, in mathematical terms, across an axis.

When an object like a line is reflected in a plane mirror, the entire line shifts its direction while maintaining its overall length and proportions in relation to that axis. This is a symmetric transformation, meaning that the distance between each point on the line and the mirror is preserved.

Key Concepts to Remember:
  • Image in a plane mirror is reversed over the axis of the mirror.
  • The orientation changes, but size and shape remain constant.
These principles underpin many geometric transformations you encounter in both physics and geometry.
Geometry of Reflections
Reflections in geometry are akin to turning objects inside out over a line — in the case of our current discussion, over the x-axis. You might think of this as creating a mirror image of each point on the line.

Geometrically speaking, reflecting a line like \( x = y \) across the x-axis means that every single point is inverted in a vertically symmetrical manner. This means each point retains its distance from the mirror line, but its orientation along the y-axis changes.

The fundamental geometric properties that govern such transformations include:
  • Symmetry: The reflected line is symmetric about the axis of the mirror.
  • Equidistance: Each point and its image are equidistant from the axis.
  • Invariant: The x-coordinate remains unchanged during the reflection.
Understanding these principles ensures clarity in how reflections alter spatial configurations, making it a crucial building block in both theoretical and practical applications of geometry.

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Most popular questions from this chapter

Two plane mirrors are combined to each other as such one is in \(y-z\) plane and other is in \(x-z\) plane. A ray of light along vector \(\hat{i}+\hat{j}+k\) is incident on the first mirror. The unit vector in the direction of emergence ray after successive reflections through the mirror is: (a) \(-\frac{1}{\sqrt{3}} \hat{i}-\frac{1}{\sqrt{3}} \hat{j}+\frac{1}{\sqrt{3}}\) (w) \(-\frac{1}{\sqrt{3}} \hat{i}-\frac{1}{\sqrt{3}} \hat{j}-\frac{1}{\sqrt{3}}\) (c) \(-\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}\) (d) none of these

An observer is sitting \(20 \mathrm{~cm}\) away from a circular convex mirror, with his eyes on the axis of the mirror. The mirror has diameter of \(6 \mathrm{~cm}\) and focal length \(30 \mathrm{~cm}\) is fixed with its principal axis horizontal. The image is formed at distance \(12 \mathrm{~cm}\) from the mirror and the distance of mid-point of diameter from the pole is \(0.75 \mathrm{~cm}\). The angular field of view in the horizontal plane seen in the mirror by the observer is : (a) \(\tan \theta=0.5672\) (b) \(\tan =0.3014\) (c) \(\tan \theta=0.5279\) (d) \(\tan \theta=0.2516\)

On a plane mirror, a ray of light is incident at an angle of \(30^{\circ}\) with horizontal. To make the reflected ray 'vertical, at what angle with horizontal must a plane mirror be placed? (a) \(30^{\circ}\) (b) \(60^{\circ}\) (c) \(45^{\circ}\) (d) \(54^{\circ}\)

A cubical room is formed with 6 plane mirrors. An insect moves along diagonal of the floor with uniform speed. The velocity of its image in two adjacent walls are \(20 \sqrt{2} \mathrm{~cm} / \mathrm{s}\). Then the velocity of image formed by the roof is : (a) \(20 \mathrm{~cm} / \mathrm{s}\) (b) \(40 \mathrm{~cm} / \mathrm{s}\) (c) \(20 \sqrt{2} \mathrm{~cm} / \mathrm{s}\) (d) \(10 \sqrt{2} \mathrm{~cm} / \mathrm{s}\)

Two objects ' \(A^{\prime}\) and ' \(B\) ' when placed in turns infront of a concave mirror, give images of equal size. The focal length of the concave mirror is \(7.5 \mathrm{~cm}\) and size of object \(A\) is three times the size of object \(B\). The distance of \(B\) from the mirror, if \(A\) is placed \(30 \mathrm{~cm}\) from the mirror, is : (a) \(18 \mathrm{~cm}\) (b) \(15 \mathrm{~cm}\) (c) \(20 \mathrm{~cm}\) (d) \(25 \mathrm{~cm}\)

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