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Two steel rods and copper rod of equal length \(l_{0}\) and equal cross-sections are joined rigidly as shown. All the rods are in a state of zero tension at \(0^{\circ} \mathrm{C}\). The temperature of system increases upto \(30^{\circ} \mathrm{C}\), then : (a) tensile force on either steel plate is half of copper plate (b) the net expansion in copper plate is less than the thermal expansion of the copper plate (c) the expansion in either steel plates is larger than thermal expansion in steel plates (d) all of the above

Short Answer

Expert verified
All options are true. The scenario describes balanced mechanical equilibrium forces in the heated rods.

Step by step solution

01

Understand the Scenario

Consider two steel rods and one copper rod, all of the same length and cross-sectional area. They form a composite rod that is heated from \(0^{\circ} \text{C}\) to \(30^{\circ} \text{C}\). Initially, there is no tension in the system.
02

Identify Properties of Materials

The linear thermal expansion coefficient for steel \( (\alpha_s) \) and copper \( (\alpha_c) \) are different. Typically, \(\alpha_c > \alpha_s\). This means copper will expand more upon heating per degree Celsius compared to steel.
03

Calculate Expected Thermal Expansion

Each material will try to expand according to its coefficient of thermal expansion: \( \Delta L_{steel} = \alpha_s \cdot l_{0} \cdot \Delta T \) and \( \Delta L_{copper} = \alpha_c \cdot l_{0} \cdot \Delta T \) where \(\Delta T\) is the change in temperature, so \(\Delta T = 30^{\circ} \text{C}\).
04

Establish Mechanical Equilibrium

Since these rods are fixed together, they must reach a mechanical equilibrium where the total expansions are equalized in the system. Thus, the tensile forces on each rod must act such that the sum of linear displacements is consistent for the fixed length.
05

Determine the Internal Forces

Because the copper rod wants to expand more due to its higher \(\alpha\), it will face a tensile force trying to compress it. Conversely, the steel rods will experience a tensile force trying to elongate them. Let's analyze the forces.
06

Analyze Force Balance

Let's denote the tensile force in steel as \(F_s\) and in copper as \(F_c\). The rods must satisfy the equilibrium: \(E_s A (\Delta L_{steel} - \Delta L'_{steel}) = F_s\), \(E_c A (\Delta L_{copper} - \Delta L'_{copper}) = -F_c\), where \(\Delta L'\) is the actual change accounting for external forces.
07

Evaluate the Options

Given the symmetrical setup, the force exerted on each steel plate is equal to each other and hence half of the copper plate, confirming statement (a). As copper wants to expand more thermally, mechanical equilibrium forces reduce its net expansion, confirming statement (b). Similarly, since steel experiences a compensating tensile force, its produced expansion is greater than the purely thermal, confirming statement (c). Therefore, all statements are true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Composite Rods
A composite rod is the combination of different materials bonded together to form a single structure. These materials, like the steel and copper rods in this scenario, are structurally combined to function together. The beauty of composite rods lies in utilizing the distinct properties of each material. Here, we have:
  • Two steel rods
  • One copper rod
Each material initially has the same physical dimensions—length and cross-sectional area—but they have different thermal behavior.
Composite rods can be found in many engineering applications where a balance between strength, flexibility, and thermal resistance is needed.
They are essential when we need to manage different materials’ expansion due to temperature changes.
Thermal Stress
When materials in a composite rod have different thermal expansion coefficients, they can experience thermal stress when the temperature changes. Thermal stress in this context refers to the internal forces that develop when the composite material is prevented from expanding or contracting freely.
For instance:
  • Steel wants to expand less due to a smaller thermal expansion coefficient.
  • Copper wants to expand more because it has a higher thermal expansion coefficient.
As these materials are fixed together, they exert forces on each other. Copper, trying to expand more, faces compressive forces, while steel, expanding less, develops tensile forces.
This interplay of forces attempts to prevent each material from moving freely, creating a state of tension—specifically which is referred to as thermal stress. It can significantly affect the durability and reliability of materials used in structures or devices.
Linear Thermal Expansion Coefficient
The linear thermal expansion coefficient (\( \alpha \)) is a property that describes how much a material expands per degree of temperature change. It is crucial for understanding how different materials will behave when subject to temperature changes.
  • For copper, \( \alpha_c \) is relatively high, meaning copper expands significantly with heating.
  • For steel, \( \alpha_s \) is lower, implying less expansion compared to copper.
This coefficient is used in the formula for calculating thermal expansion:\[ \Delta L = \alpha \cdot l_0 \cdot \Delta T \]where \( \Delta L \) is the change in length, \( \alpha \) is the thermal expansion coefficient, \( l_0 \) is the original length, and \( \Delta T \) is the temperature change.
Understanding this property helps predict how much a particular material will expand or contract with temperature changes, vital for designing components that undergo varying thermal environments.
Mechanical Equilibrium
Mechanical equilibrium occurs when all forces within a system are balanced, leading to a stable configuration. In the context of thermal expansion and composite rods:
  • The sum of all expansion forces across the different materials must balance out.
  • No net displacement or change occurs unless the external constraints are altered.
For composite rods:
  • Copper will exhibit a tensile force due to its greater expansion attempt, pushing against its restraints.
  • Steel rods will counteract this expansion by developing their own compensating tensile forces.
Achieving mechanical equilibrium involves ensuring the sum of expansions and contractions in the system results in no net change in the whole structure's length, even if the individual rods experience differential expansions.
This equilibrium state is essential because it validates the reliability of the composite structure under thermal changes—which prevents fractures or failures when exposed to practical applications.

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Most popular questions from this chapter

An equilateral triangle \(A B C\) is formed by joining three rods of equal length and \(D\) is the mid-point of \(A B\). The coefficient of linear expansion for \(A B\) is \(\alpha_{1}\) and for \(A C\) and \(B C\) is \(\alpha_{2}\). Find the relation between \(\alpha_{1}\) and \(\alpha_{2}\), if distance \(D C\) remains constant for small changes in temperature (a) \(\alpha_{1}=\alpha_{2}\) (b) \(\alpha_{1}=4 \alpha_{2}\) (c) \(\alpha_{2}=4 \alpha_{1}\) (d) \(\alpha_{1}=\frac{1}{2} \alpha_{2}\)

If in \(1.1 \mathrm{~kg}\) of water which is contained in a calorimeter of water equivalent \(0.02 \mathrm{~kg}\) at \(15^{\circ} \mathrm{C}\), steam at \(100^{\circ} \mathrm{C}\) is passed, till the temperature of calorimeter and its contents rises to \(80^{\circ} \mathrm{C}\). The mass of steam condensed in kilogram is: (a) \(0.131\) (b) \(0.065\) (c) \(0.260\) (d) \(0.135\)

Using the following, data, at what temperature will the wood just sink in benzene? Density of wood at \(0^{\circ} \mathrm{C}=8.8 \times 10^{2} \mathrm{~kg} / \mathrm{m}^{3}\) Density of benzene at \(0^{\circ} \mathrm{C}=9 \times 10^{2} \mathrm{~kg} / \mathrm{m}^{3}\) Cubical expansivity of wood \(=1.5 \times 10^{-4} \mathrm{~K}^{-1}\) Cubical expansivity of benzene \(=1.2 \times 10^{-3} \mathrm{~K}^{-1}\) (a) \(27^{\circ} \mathrm{C}\) (b) \(21.7^{\circ} \mathrm{C}\) (c) \(31^{\circ} \mathrm{C}\) (d) \(31.7^{\circ} \mathrm{C}\)

If same amount of heat is supplied to two identical spheres (one is hollow and other is solid), then: (a) the expansion in hollow is greater than the solid (b) the expansion in hollow is same as that in solid (c) the expansion in hollow is lesser than the solid (d) the temperature of both must be same to each other.

At a temperature \(t^{\circ} \mathrm{C}\), a liquid is completely filled in a spherical shell of copper. If \(\Delta T\) increases temperature of the liquid and the shell, then the outward pressure \(d P\) on the shell resulted from increase in temperature is given by: (Given, \(K=\) Bulk modulus of the liquids, \(\gamma=\) coefficient of volume expansion, \(\alpha=\) coefficient of linear expansion of the material of the shell) (a) \(\frac{K}{2}(\gamma-3 \alpha) \Delta T\) (b) \(K(3 \alpha-\gamma) \Delta T\) (c) \(3 \alpha(K-\gamma) \Delta T\) (d) \(\gamma(3 \alpha-K) \Delta T\)

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