/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 A wave of angular frequency \(\o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A wave of angular frequency \(\omega\) propagates so that a certain phase of oscillation moves along \(x\) -axis, \(y\) -axis and \(z\) -axis with speeds \(c_{1}, c_{2}\) and \(c_{3}\) respectively. The propagation constant \(k\) is: (a) \(\frac{\omega}{\sqrt{c_{1}^{2}+c_{2}^{2}+c_{3}^{2}}}(\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}})\) (b) \(\frac{\omega}{c_{1}} \hat{i}+\frac{\omega}{c_{2}} \hat{\hat{j}}+\frac{\omega}{c_{3}} \hat{\mathbf{k}}\) (c) \((\omega \hat{\mathbf{1}}+\omega \hat{\mathrm{j}}+\omega \hat{\mathbf{k}}) \frac{1}{c}\) (d) none of the above

Short Answer

Expert verified
Option (b) is the correct answer.

Step by step solution

01

Understand the relationship between wave parameters

The phase velocity of a wave when it propagates in space is given as \( v_p = \frac{\omega}{k} \), where \( \omega \) is the angular frequency and \( k \) is the wave vector or propagation constant. For a wave propagating in different directions (along \( x \), \( y \), and \( z \) axes), the velocity components are \( c_1 \), \( c_2 \), and \( c_3 \) respectively for each direction.
02

Relate velocity components to wave vector

For a wave moving along the x-direction, the wave vector is \( k_x = \frac{\omega}{c_1} \). Similarly, for the y-direction and z-direction, we have: \( k_y = \frac{\omega}{c_2} \) and \( k_z = \frac{\omega}{c_3} \).
03

Combine components to get the total wave vector

The total wave vector, \( \mathbf{k} \), is a vector sum of its components: \( \mathbf{k} = k_x \hat{\mathbf{i}} + k_y \hat{\mathbf{j}} + k_z \hat{\mathbf{k}} \). Substituting the values of \( k_x \), \( k_y \), and \( k_z \) gives us: \( \mathbf{k} = \frac{\omega}{c_1} \hat{\mathbf{i}} + \frac{\omega}{c_2} \hat{\mathbf{j}} + \frac{\omega}{c_3} \hat{\mathbf{k}} \).
04

Match the expression with given options

Looking at the expression for \( \mathbf{k} \) from Step 3, we find that option (b), \( \frac{\omega}{c_1} \hat{i} + \frac{\omega}{c_2} \hat{\mathbf{j}} + \frac{\omega}{c_3} \hat{\mathbf{k}} \), matches our result for the wave vector.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Vector
The wave vector, often denoted as \( \mathbf{k} \), is a fundamental concept in wave mechanics. It plays a crucial role in describing the propagation properties of waves in space. The wave vector represents the direction of wave travel and is inversely proportional to the wavelength. Its magnitude is calculated as \( k = \frac{2\pi}{\lambda} \), where \( \lambda \) is the wavelength of the wave. The direction of the wave vector points in the direction of energy propagation.

When a wave propagates through space, it can move along different axes, such as the x, y, and z axes. The wave vector can then be expressed as a combination of its components in these directions. For example, if we know the wave's angular frequency \( \omega \) and its phase velocities \( c_1, c_2, \) and \( c_3 \) along the x, y, and z axes respectively, we can find each component of the wave vector as follows:
  • \( k_x = \frac{\omega}{c_1} \)
  • \( k_y = \frac{\omega}{c_2} \)
  • \( k_z = \frac{\omega}{c_3} \)
The total wave vector \( \mathbf{k} \) is then the vector sum \( \mathbf{k} = k_x \hat{\mathbf{i}} + k_y \hat{\mathbf{j}} + k_z \hat{\mathbf{k}} \). This expression helps in determining how the wave behaves as it travels in different directions.
Phase Velocity
Phase velocity, denoted by \( v_p \), describes the speed at which any given phase of the wave, such as a crest, travels through space. It is determined by the wave's angular frequency \( \omega \) and its wave vector \( k \) using the formula \( v_p = \frac{\omega}{k} \).

The phase velocity is an important concept because it indicates how quickly the wave's phase propagates. In scenarios where a wave moves along multiple axes, like the x, y, and z axes, each axis will have its specific phase velocity, named as \( c_1, c_2, \) and \( c_3 \), respectively. The relation between phase velocity and the wave vector components becomes:
  • \( c_1 = \frac{\omega}{k_x} \)
  • \( c_2 = \frac{\omega}{k_y} \)
  • \( c_3 = \frac{\omega}{k_z} \)
These equations show that phase velocity along each direction depends on how the angular frequency \( \omega \) compares to the relevant component of the wave vector. Each component essentially describes how fast the wave phase moves in that particular direction.
Angular Frequency
Angular frequency, symbolized by \( \omega \), is a fundamental parameter of waves. It specifies how quickly a wave oscillates in time. Angular frequency is defined as \( \omega = 2\pi f \), where \( f \) is the frequency in Hertz (cycles per second).

In the context of wave mechanics, angular frequency links closely with the wave's propagation. It plays a key role in determining both the phase velocity and the behavior of the wave vector. For instance, when deriving the components of the wave vector along different axes, we use angular frequency to express how the wave moves through space:
  • It forms the numerator in expressions for wave vector components, as \( k_x = \frac{\omega}{c_1} \), \( k_y = \frac{\omega}{c_2} \), and \( k_z = \frac{\omega}{c_3} \).
  • It relates to the phase velocity through the formula \( v_p = \frac{\omega}{k} \).
Understanding angular frequency is crucial because it's involved in describing both the temporal oscillations and the spatial characteristics of waves. This relationship helps predict how a wave develops over both time and space.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For a wave $$ y=0.0002 \sin \left[2 \pi\left(110 t-\frac{x}{3}\right)+\frac{\pi}{3}\right] $$ is travelling in a medium. The energy per unit volume being transfered by wave if density of medium is \(1.5 \mathrm{~kg} / \mathrm{m}^{3}\), is : (a) \(14 \times 10^{-4} \mathrm{~J} / \mathrm{m}^{3}\) (b) \(143.2 \times 10^{-4} \mathrm{~J} / \mathrm{m}^{3}\) (c) \(14.3 \times 10^{-4} \mathrm{~J} / \mathrm{m}^{3}\) (d) \(1.43 \times 10^{-4} \mathrm{~J} / \mathrm{m}^{3}\)

A sinusoidal wave travelling in the same direction have amplitudes of \(3 \mathrm{~cm}\) and \(4 \mathrm{~cm}\) and difference in phase by \(\pi / 2 .\) The resultant amplitude of the superimposed wave is : (a) \(7 \mathrm{~cm}\) (b) \(5 \mathrm{~cm}\) (c) \(2 \mathrm{~cm}\) (d) \(0.5 \mathrm{~cm}\)

An elastic string of length \(2 \mathrm{~m}\) is fixed at its end. The string starts to vibrate in third overtone with a frequency \(1200 \mathrm{~Hz}\). The ratio of frequency of lower overtone and fundamental is: (a) 1 (b) 2 (c) 3 (d) 4

Two simple harmonic motions are represented by the equations $$ y_{1}=10 \sin \left(3 \pi t+\frac{\pi}{4}\right) $$ and $$ y_{2}=5(3 \sin 3 \pi t+\sqrt{3} \cos 3 \pi t) $$ Their amplitudes are in the ratio of : (a) \(\sqrt{3}\) (b) \(1 / \sqrt{3}\) (c). 2 (d) \(1 / 6\)

The equation of the standing wave in a string clamped at both ends, vibrating in its third harmonic is given by $$ y=0.4 \sin (0.314 x) \cos (600 \pi t) $$ where \(x\) and \(y\) are in \(\mathrm{cm}\) and \(t\) is in sec: (a). The frequency of vibration is \(300 \mathrm{~Hz}\) (b) The length of the string is \(30 \mathrm{~cm}\) (c) The nodes are located at \(x=0,10 \mathrm{~cm}, 30 \mathrm{~cm}\) (d) All of the above

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.