Chapter 13: Problem 23
If \(y=y_{0} \sin 2 \pi\left[f t-\frac{x}{\lambda}\right)\) is the equation of transverse wave, then for what value of \(\lambda^{\prime}\) the maximum particle velocity is equal to four times the wave velocity? (a) \(y_{0} \pi\) (b) \(\frac{y_{0} \pi}{2}\) (c) \(2 y_{0} \pi\). (d) \(1.5 y_{0} \pi\)
Short Answer
Step by step solution
Understanding the Wave Equation
Finding Maximum Particle Velocity
Setting up Condition for Maximum Particle Velocity
Solving for \(\lambda^{\prime}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Transverse Wave
Transverse wave equations often come in the format of a sinusoidal function, such as \(y = y_0 \sin 2\pi \left(ft - \frac{x}{\lambda}\right)\), where:
- \(y_0\) is the amplitude, representing the maximum displacement of the wave.
- \(f\) is the frequency, indicating how often the wave oscillates per second.
- \(x\) is the position along the direction of the wave.
- \(\lambda\) is the wavelength, the distance between consecutive peaks or troughs.
Particle Velocity
To find particle velocity, we take the time derivative of the wave function. For example, with the wave equation \(y = y_0 \sin 2\pi \left(ft - \frac{x}{\lambda}\right)\), the particle velocity formula \(v_p\) becomes:
- \(v_p = \frac{\partial y}{\partial t} = y_0 \cdot 2\pi f \cdot \cos 2\pi\left(ft - \frac{x}{\lambda}\right)\).
This concept is crucial when comparing particle and wave velocities, such as finding conditions when they align or reach particular ratios.
Wave Velocity
\[ v = f\lambda \]
This formula illustrates that wave velocity depends directly on both frequency and wavelength. When frequency increases, wavelength generally decreases, so the effect on wave velocity can vary depending on the medium and context.
Understanding wave velocity is significant, as it helps in determining how quickly a wave carries energy and information from one location to another. It becomes especially interesting in scenarios where particle velocity is compared with wave velocity, such as determining conditions for maximum particle velocity to be a set multiple of wave velocity.
Wavelength
In the context of transverse waves, the wavelength can be manipulated by adjusting other elements like the frequency, as seen in the wave equation \(y = y_0 \sin 2\pi \left(ft - \frac{x}{\lambda}\right)\). This equation integrates the wavelength in calculating wave speed and other dynamic properties of waves.
Wavelength plays a crucial role in deciphering how waves behave, interact with materials, or how they might be used in applications like telecommunications. Changes in wavelength inevitably influence wave velocity because wave velocity is calculated by multiplying frequency \(f\) with wavelength \(\lambda\), reinforcing how important this parameter is for understanding wave phenomena.