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A particle executes simple harmonic motion. The amplitude of vibration of particle is \(2 \mathrm{~cm}\). The displacement of particle in one time period is : (a) \(1 \mathrm{~cm}\) (b) \(2 \mathrm{~cm}\) (c) \(4 \mathrm{~cm}\) (d) zero

Short Answer

Expert verified
The displacement in one time period is zero.

Step by step solution

01

Understanding Simple Harmonic Motion

In simple harmonic motion (SHM), a particle moves back and forth along a straight line, following a periodic path. The displacement in one period is the net change in position after a complete cycle.
02

Recognize the Role of Amplitude

Amplitude is the maximum extent of a vibration or oscillation, measured from the position of equilibrium. For this problem, the amplitude is given as 2 cm.
03

Analyze the Motion Over One Period

In one complete period, the particle starts at a point, moves to the maximum positive amplitude, returns to the equilibrium, moves to the maximum negative amplitude, and comes back to the starting point.
04

Calculating Displacement in One Period

Displacement refers to the change in position from the initial point. Since the particle returns to the starting point after one period, the net displacement is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amplitude
Amplitude represents the maximum distance a particle moves from its equilibrium position during simple harmonic motion (SHM). It is a crucial parameter in describing SHM because it determines the extent of the particle's oscillation.

In the context of the given exercise, the amplitude is stated as 2 cm. This means that during its motion, the particle moves 2 cm away from its central equilibrium position at its furthest points, both on the positive and negative sides.
  • The equilibrium position is where the particle would naturally come to rest if no forces were acting on it.
  • A higher amplitude indicates that the particle travels further from equilibrium, while a lower amplitude means it moves a shorter distance.
Understanding amplitude helps us predict the range within which the particle oscillates back and forth.
Displacement
Displacement in simple harmonic motion (SHM) refers to the overall change in position of the particle during its motion. Unlike distance, which is the total length of the path traveled, displacement is concerned with the net change from the starting to the ending point.

In the exercise, displacement in one period of SHM equals zero because the particle starts and ends at the same point after completing a full cycle. This can be a little confusing at first, because the particle has definitely moved! However, since it returns to its original position at the end of one period, the net displacement is zero.
  • Displacement answers the question: "How far is the particle now compared to where it started?"
  • Even if the particle travels a significant distance during its motion, its displacement can still end up being zero at the end of a full cycle.
Visualizing the motion helps in understanding this concept, where the particle swings back and forth along its path.
Periodic Motion
Periodic motion refers to any motion that repeats at regular time intervals, known as periods. In the context of simple harmonic motion (SHM), it specifically describes the repetitive oscillation of the particle.

Each complete cycle of SHM is characterized by a period during which the particle:
  • Starts at a certain point within its path.

  • Moves to its maximum positive position, reflective of the positive amplitude.

  • Returns through its equilibrium to reach the maximum negative position.

  • Finally returns back to the starting position.
This repetition is what makes the motion periodic, and it is a fundamental aspect of SHM. The consistency in the cycle helps in predicting future states of the particle.

Understanding periodic motion aids in grasping the continuous nature of SHM and how forces bring the particle back toward its equilibrium position, maintaining the rhythmic oscillation.

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