Chapter 23: Problem 5
Find the percent of a sample of \({ }_{55}^{124} \mathrm{Cs}\) that will decay in the next \(10.0 \mathrm{~s}\). Its half life is \(30.8 \mathrm{~s}\).
Short Answer
Expert verified
About 20% of the sample will decay in the next 10 seconds.
Step by step solution
01
Understand the Problem
We need to find out what percent of the sample of \({ }_{55}^{124} \mathrm{Cs}\) will decay in 10.0 seconds given its half-life is 30.8 seconds.
02
Recall the Exponential Decay Formula
Exponential decay can be represented by the formula: \[ N(t) = N_0 \times e^{-\lambda t} \] where \(N(t)\) is the remaining quantity at time \(t\), \(N_0\) is the initial quantity, \(\lambda\) is the decay constant, and \(t\) is time.
03
Find the Decay Constant
The decay constant \(\lambda\) can be found using the relation \( \lambda = \frac{\ln 2}{t_{1/2}} \), where \(t_{1/2}\) is the half-life.Thus, \( \lambda = \frac{\ln 2}{30.8} \approx 0.0225 \, \text{s}^{-1} \).
04
Calculate Remaining Quantity After 10 Seconds
Using the decay formula: \[ N(10) = N_0 \times e^{-0.0225 \times 10} \]This simplifies to \[ N(10) = N_0 \times e^{-0.225} \].
05
Calculate the Decayed Quantity
The decayed quantity in 10 seconds is \( N_0 - N(10) = N_0 - N_0 \times e^{-0.225} \)Simplifying gives \( N_0 \times (1 - e^{-0.225}) \).
06
Find the Percent Decayed
The percent that decayed is given by \[ \left( 1 - e^{-0.225} \right) \times 100\% \] Calculating gives approximately 20\%.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Life Calculation
The concept of half-life is essential to understanding how substances decay over time. It is defined as the time it takes for half of a sample of a radioactive substance to decay.
This is a crucial property of radioactive materials like { }_{55}^{124} ext{Cs} .
In our exercise, the half-life is given as 30.8 seconds, meaning it takes this duration for half of the cesium sample to decay. The half-life helps us estimate how quickly a radioactive sample transforms. It is a reliable measure because it's constant for given isotopes under identical conditions, regardless of the initial quantity.
This is a crucial property of radioactive materials like { }_{55}^{124} ext{Cs} .
In our exercise, the half-life is given as 30.8 seconds, meaning it takes this duration for half of the cesium sample to decay. The half-life helps us estimate how quickly a radioactive sample transforms. It is a reliable measure because it's constant for given isotopes under identical conditions, regardless of the initial quantity.
- To determine decay over another time period, simply repeat using the half-life.
- Each subsequent half-life period results in half of the remaining material decaying.
Exponential Decay Formula
The exponential decay formula is a mathematical representation of how radioactive substances decrease over time. This formula is N(t) = N_0 \times e^{-\lambda t}, where:
- N(t) represents the quantity remaining at time t.
- N_0 is the initial quantity.
- \lambda is the decay constant.
- Determine the decay constant \(\lambda\).
- Input desired time t.
- Compute using the formula steps, simplifying to find N(t).
Decay Constant
The decay constant, denoted as \(\lambda\), is a critical factor in calculating radioactive decay, embodying a unique rate for each substance. It provides a measure of how rapidly a sample decays.
This constant is derived by the formula \[ \lambda = \frac{\ln 2}{t_{1/2}} \]where \(t_{1/2}\) is the half-life. It essentially connects the half-life to the decay process.Calculating \(\lambda\) allows you to normalize the decay equation for any scenario:
Understanding this constant is vital, as it quantifies the specific rate at which radioactive decay occurs, serving as a baseline to predict how much remains after any given time.
This constant is derived by the formula \[ \lambda = \frac{\ln 2}{t_{1/2}} \]where \(t_{1/2}\) is the half-life. It essentially connects the half-life to the decay process.Calculating \(\lambda\) allows you to normalize the decay equation for any scenario:
- It shows how the decay rate changes depending on the material.
- Smaller \(\lambda\) values indicate slower decay.
- Larger \(\lambda\) values correlate with faster decay.
Understanding this constant is vital, as it quantifies the specific rate at which radioactive decay occurs, serving as a baseline to predict how much remains after any given time.