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Consider a system of five particles, inside a container where the allowed energy levels are nondegenerate and evenly spaced. For instance, the particles could be trapped in a one-dimensional harmonic oscillator potential. In this problem you will consider the allowed states for this system, depending on whether the particles are identical fermions, identical bosons, or distinguishable particles.

(a) Describe the ground state of this system, for each of these three cases.

(b) Suppose that the system has one unit of energy (above the ground state). Describe the allowed states of the system, for each of the three cases. How many possible system states are there in each case?

(c) Repeat part (b) for two units of energy and for three units of energy.

(d) Suppose that the temperature of this system is low, so that the total energy is low (though not necessarily zero). In what way will the behavior of the bosonic system differ from that of the system of distinguishable particles? Discuss.

Short Answer

Expert verified

(a) The ground state of this system is.

(b) The are five possible system states in each case.

(c) For two-unit of energy the graph is

and for three-unit of energy is

.

(d) The way that the behavior of the bosonic system differs from that of the system of distinguishable particles is discussed below.

Step by step solution

01

Part (a) Step 1: Given Information

We have to describe the ground state of the system, for each of these three cases.

02

Part (a) Step 2: Simplify

As bosons do not follow the Pauli exclusion principle, particles in the ground state on the same level are distinguishable, but if they are fermions, each one will occupy a level starting from the lowest level, resulting in something like this:

03

Part (b) Step 1: Given Information

We have to describe the allowed states of the system, for each of the three cases and find the possible system states in each case.

04

Part (b) Step 2: Simplify

Consider a particle that has been promoted to the second lowest level, one energy unit above the ground state. There is only one way to do this for identifiable particles or bosons, which is to promote one particle from the lowest level to the second lowest level. There are five ways to promote indistinguishable particles or fermions, and the particle is promoted from the fifth level to the sixth level, as represented graphically:

05

Part (c) Step 1: Given Information

We have to repeat part (b) for two units of energy and for three units of energy.

06

Part (c) Step 2: Simplify

Consider a particle promoted to the second lowest level with two energy units above the ground state. We can promote one particle up to two energy levels, leaving four particles in the first level, or we can promote two particles to the second lowest level. There is only one way to do this for either, which is to promote one particle from the lowest level to the second lowest level. There are ten ways to do the first arrangement (where the two particles are promoted to the second and third lowest levels above the last filled level) and five ways to do the second arrangement (where the last particle is promoted to the third level above the last filled level) for indistinguishable particles or fermions, as shown graphically:

Consider a particle promoted to the second lowest level with three energy units above the ground state. We can promote one particle up to three energy levels for distinguishable particles or bosons, leaving four particles in the first level, or promote one particle to the second lowest level and one to the third lowest level, or promote three particles to the second lowest level, but there is only one way to do this for each. There are ten ways to make the first arrangement, twenty ways to do the second arrangement, and five ways to do the third arrangement for indistinguishable particles or fermions, and these arrangements are depicted graphically as:

07

Part (d) Step 1: Given Information

We have to find the behavior of the bosonic system differ from that of the system of distinguishable particles.

08

Part (d) Step 2: Simplify

The Boltzmann factor is proportional to the likelihood that a system with a temperature of T, i.e.

Pe-E/kT

The energy of any system is the same, therefore this factor is the same, but when we factor in degeneracy (from the previous section, the degeneracy of the bosons is 3 and the degeneracy of the fermions is 35), we can see that at low temperatures, the fermions are more likely to be found than the bosons. The bosons are also likely to be discovered in the ground state.

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Most popular questions from this chapter

Consider a free Fermi gas in two dimensions, confined to a square area A=L2

(a) Find the Fermi energy (in terms of Nand A), and show that the average energy of the particles is F2.

(b) Derive a formula for the density of states. You should find that it is a constant, independent of .

(c) Explain how the chemical potential of this system should behave as a function of temperature, both when role="math" localid="1650186338941" kTFand when Tis much higher.

(d) Because gis a constant for this system, it is possible to carry out the integral 7.53 for the number of particles analytically. Do so, and solve for as a function of N. Show that the resulting formula has the expected qualitative behavior.

(e) Show that in the high-temperature limit, kTF, the chemical potential of this system is the same as that of an ordinary ideal gas.

When the attractive forces of the ions in a crystal are taken into account, the allowed electron energies are no longer given by the simple formula 7.36; instead, the allowed energies are grouped into bands, separated by gaps where there are no allowed energies. In a conductor the Fermi energy lies within one of the bands; in this section we have treated the electrons in this band as "free" particles confined to a fixed volume. In an insulator, on the other hand, the Fermi energy lies within a gap, so that at T = 0 the band below the gap is completely occupied while the band above the gap is unoccupied. Because there are no empty states close in energy to those that are occupied, the electrons are "stuck in place" and the material does not conduct electricity. A semiconductor is an insulator in which the gap is narrow enough for a few electrons to jump across it at room temperature. Figure 7 .17 shows the density of states in the vicinity of the Fermi energy for an idealized semiconductor, and defines some terminology and notation to be used in this problem.

(a) As a first approximation, let us model the density of states near the bottom of the conduction band using the same function as for a free Fermi gas, with an appropriate zero-point: g()=g0-c, where go is the same constant as in equation 7.51. Let us also model the density of states near the top

Figure 7.17. The periodic potential of a crystal lattice results in a densityof-states function consisting of "bands" (with many states) and "gaps" (with no states). For an insulator or a semiconductor, the Fermi energy lies in the middle of a gap so that at T = 0, the "valence band" is completely full while the-"conduction band" is completely empty. of the valence band as a mirror image of this function. Explain why, in this approximation, the chemical potential must always lie precisely in the middle of the gap, regardless of temperature.

(b) Normally the width of the gap is much greater than kT. Working in this limit, derive an expression for the number of conduction electrons per unit volume, in terms of the temperature and the width of the gap.

(c) For silicon near room temperature, the gap between the valence and conduction bands is approximately 1.11 eV. Roughly how many conduction electrons are there in a cubic centimeter of silicon at room temperature? How does this compare to the number of conduction electrons in a similar amount of copper?

( d) Explain why a semiconductor conducts electricity much better at higher temperatures. Back up your explanation with some numbers. (Ordinary conductors like copper, on the other hand, conduct better at low temperatures.) (e) Very roughly, how wide would the gap between the valence and conduction bands have to be in order to consider a material an insulator rather than a semiconductor?

Prove that the peak of the Planck spectrum is at x = 2.82.

(a) Estimate (roughly) the total power radiated by your body, neglecting any energy that is returned by your clothes and environment. (Whatever the color of your skin, its emissivity at infrared wavelengths is quite close to 1; almost any nonmetal is a near-perfect blackbody at these wavelengths.)

(b) Compare the total energy radiated by your body in one day (expressed in kilocalories) to the energy in the food you cat. Why is there such a large discrepancy?

(c) The sun has a mass of 21030kgand radiates energy at a rate of 3.91026watts. Which puts out more power per units mass-the sun or your body?

Suppose that the concentration of infrared-absorbing gases in earth's atmosphere were to double, effectively creating a second "blanket" to warm the surface. Estimate the equilibrium surface temperature of the earth that would result from this catastrophe. (Hint: First show that the lower atmospheric blanket is warmer than the upper one by a factor of 21/4. The surface is warmer than the lower blanket by a smaller factor.)

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