/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 1.37 In a Diesel engine, atmospheric ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In a Diesel engine, atmospheric air is quickly compressed to about 1/20 of its original volume. Estimate the temperature of the air after compression, and explain why a Diesel engine does not require spark plugs.

Short Answer

Expert verified

The temperature of air compression is 971.14 K.

Compressed temp is much above the auto ignition temp of diesel so diesel engines don't need any spark plugs.

Step by step solution

01

Given information

Atmospheric air is quickly compressed to about 1/20 of its original volume.

02

Explanation

The expression below explains the relationship between V and T as

VTfR2=Constant..............................(1)

Where V = volume and T = Temp

Consider the air molecules are diatomic, so its degree of freedom is

f=5( 3 translation + 2 rotational).

Write the equation for final and initial conditions and equate them to find final temp as below

ViTif2=VfTff2Tff2=ViVfTif2...................................(2)Tf=ViVf2fTi.....................................(3)

Substitute values and calculate to get final temp

Tf=VoVo2025293KTf=971.14K

We know that the auto ignition temperature for diesel is 210oC

So the fuel will automatically ignite when the air is compressed as temp is much above the auto ignition temp.

For this reason diesel engines don't need any spark plugs.


Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Uranium has two common isotopes, with atomic masses of 238 and 235. one way to separate these isotopes is to combine the uranium with fluorine to make uranium hexafluoride gas, UF6, then exploit the difference in the average thermal speeds of molecules containing the different isotopes. Calculate the rms speed of each molecule at room temperature, and compare them.

Imagine some helium in a cylinder with an initial volume of 1litreand an initial pressure of 1atm.Somehow the helium is made to expand to a final volume of 3litres,in such a way that its pressure rises in direct proportion to its volume.

(a) Sketch a graph of pressure vs. volume for this process.

(b) Calculate the work done on the gas during this process, assuming that there are no "other" types of work being done.

(c) Calculate the change in the helium's energy content during this process.

(d) Calculate the amount of heat added to or removed from the helium during this process.

(e) Describe what you might do to cause the pressure to rise as the helium expands.

Estimate how long it should take to bring a cup of water to boiling temperature in a typical 600 -watt microwave oven, assuming that all the energy ends up in the water. (Assume any reasonable initial temperature for the water.) Explain why no heat is involved in this process.

The Fahrenheit temperature scale is defined so that ice melts at 320 F and water boils at 2120 F.

(a) Derive the formula for converting from Fahrenheit to Celsius and back

(b) What is absolute zero on the Fahrenheit scale?

A battery is connected in series to a resistor, which is immersed in water (to prepare a nice hot cup of tea). Would you classify the flow of energy from the battery to the resistor as "heat" or "work"? What about the flow of energy from the resistor to the water?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.