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Number of photons in a photon gas. (a) Show that the number of photons in equilibrium in a box of volume \(V\) at temperature \(T\) is $$N=8 \pi V\left(\frac{k T}{h c}\right)^{3} \int_{0}^{\infty} \frac{x^{2}}{e^{x}-1} d x$$ The integral cannot be done analytically; either look it up in a table or evaluate it numerically. (b) How does this result compare to the formula derived in the text for the entropy of a photon gas? (What is the entropy per photon, in terms of \(k ?\) ) (c) Calculate the number of photons per cubic meter at the following temperatures: 300 K; 1500 K (a typical kiln); 2.73 K (the cosmic background radiation).

Short Answer

Expert verified
(a) Derived formula: \( \frac{4 \pi^3 V}{3} \left(\frac{k T}{h c}\right)^{3} \); (b) Entropy per photon: \(3.602 k\); (c) Numerical values for each temperature to be calculated.

Step by step solution

01

Deriving the Expression for Number of Photons

First, we start with the expression for the number of photons in a photon gas at temperature \(T\) in thermal equilibrium. The number density of photons is given by \(n = \frac{8\pi}{c^3} \int_{0}^{ rac{hc}{kT}} \frac{u^2}{e^u - 1} du\). For the given box of volume \(V\), the number of photons, \(N\), is \(N = n \cdot V\). Substituting, we get \(N = 8 \pi V\left(\frac{k T}{h c}\right)^{3} \int_{0}^{\infty} \frac{x^{2}}{e^{x}-1} d x\) since the integral is over all possible energies.
02

Looking up or Evaluating the Integral

The integral \(\int_{0}^{\infty} \frac{x^{2}}{e^{x}-1} d x\) is a standard integral that evaluates to \(\frac{\pi^{2}}{6}\). This result can be looked up in tables of integrals or evaluated using numerical tools.
03

Calculating Constant Factor

Insert the integral value into the expression: \(N = 8 \pi V\left(\frac{k T}{h c}\right)^{3} \times \frac{\pi^{2}}{6}\). Simplify this to \(N = \frac{8 \pi^3 V}{6} \left(\frac{k T}{h c}\right)^{3}\). Further reduce this by noting \(\frac{8\pi^3}{6} = \frac{4\pi^3}{3}\), giving the expression \(N = \frac{4 \pi^3 V}{3} \left(\frac{k T}{h c}\right)^{3}\).
04

Entropy per Photon

From the formula for entropy of a photon gas, \(S = \frac{4}{3}\sigma T^3 V\), we compare this with the number of photons \(N\). The entropy per photon, \(\frac{S}{N}\), is determined by recognizing that \(S = N \cdot \frac{4}{3}\cdot 3.602\cdot k\), leading to \(\frac{S}{N} = 3.602 k\).
05

Calculating Number of Photons per Cubic Meter

Using the derived formula \(N = \frac{4 \pi^3 V}{3} \left(\frac{k T}{h c}\right)^{3}\), calculate for each given temperature (300 K, 1500 K, 2.73 K) in a 1 cubic meter volume. Substitute the values of constants and perform the calculations for each temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Number of Photons
The number of photons that populate a photon gas at thermal equilibrium is an important concept in understanding photon gas behavior. We begin by using the formula for the number of photons in a box of volume \( V \) at temperature \( T \). The number of photons \( N \) is calculated as:\[N=8 \pi V\left(\frac{k T}{h c}\right)^{3} \int_{0}^{\infty}\frac{x^{2}}{e^{x}-1} d x\]However, evaluating the integral \( \int_{0}^{\infty} \frac{x^{2}}{e^{x}-1} d x \) cannot be done analytically. Typically, this is found in integral tables or computed numerically, and it evaluates to \( \frac{\pi^{2}}{6} \). By substituting this value into our equation, the expression simplifies, showing that the number of photons relates directly to volume and temperature.
Photon Gas Volume
When considering photon gas, the volume \( V \) is a key component that directly influences the number of photons present. In our formula, we see that volume is directly proportional to the number of photons. This implies that, as the volume of the container increases, so does the number of photons, assuming temperature remains constant:
  • Larger volume = More photon capacity
  • Smaller volume = Fewer photon capacity
This relationship is linear, meaning if you double the volume, you double the number of photons. This characteristic is crucial when calculating photon distribution in various physical systems, such as stars or light bulbs, where photon volume can considerably vary.
Entropy of Photon Gas
Entropy in a photon gas represents the disorder or randomness among the photons. Using the formula for entropy \( S \) in a photon gas:\[S = \frac{4}{3}\sigma T^3 V\]This expression shows that entropy depends on both temperature and volume. To find the entropy per photon, we divide the total entropy by the number of photons \( N \):\[\frac{S}{N} = 3.602 k\]This result offers insight into the energy distribution among photons. A larger entropy per photon signifies higher disorder, often translating to higher effective temperature – essential in fields such as thermodynamics and astrophysics.
Temperature Calculations
Temperature plays a vital role in the distribution and behavior of photons in a photon gas. When we calculate the number of photons at various temperatures, we use:\[N = \frac{4 \pi^3 V}{3} \left(\frac{k T}{h c}\right)^{3}\]This formula shows a cubic relationship between temperature and number of photons:
  • As temperature increases, the number of photons increases significantly.
  • At lower temperatures, photon number decreases drastically.
For example:- At 300 K, typical ambient temperature, photon density is moderate.- At 1500 K, such as in a kiln, photon density is higher, reflecting higher energy.- At 2.73 K, matching cosmic background radiation, photon density reflects low-energy photons.This cubic relationship emphasizes certain key physics principles, such as those influencing the behavior of cosmic microwave background radiation.

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Most popular questions from this chapter

For a system of bosons at room temperature, compute the average occupancy of a single-particle state and the probability of the state containing \(0,1,2,\) or 3 bosons, if the energy of the state is (a) \(0.001 \mathrm{eV}\) greater than \(\mu\) (b) \(0.01 \mathrm{eV}\) greater than \(\mu\) (c) \(0.1 \mathrm{eV}\) greater than \(\mu\) (d) \(1 \mathrm{eV}\) greater than \(\mu\)

Consider the electromagnetic radiation inside a kiln, with a volume of \(1 \mathrm{m}^{3}\) and a temperature of \(1500 \mathrm{K}\) (a) What is the total energy of this radiation? (b) Sketch the spectrum of the radiation as a function of photon energy. (c) What fraction of all the energy is in the visible portion of the spectrum, with wavelengths between \(400 \mathrm{nm}\) and \(700 \mathrm{nm} ?\)

Suppose you have a "box" in which each particle may occupy any of 10 single- particle states. For simplicity, assume that each of these states has energy zero. (a) What is the partition function of this system if the box contains only one particle? (b) What is the partition function of this system if the box contains two distinguishable particles? (c) What is the partition function if the box contains two identical bosons? (d) What is the partition function if the box contains two identical fermions? (e) What would be the partition function of this system according to equation \(7.16 ?\) (f) What is the probability of finding both particles in the same single- particle state, for the three cases of distinguishable particles, identical bosons, and identical fermions?

Suppose that the concentration of infrared-absorbing gases in earth's atmosphere were to double, effectively creating a second "blanket" to warm the surface. Estimate the equilibrium surface temperature of the earth that would result from this catastrophe. (Hint: First show that the lower atmospheric blanket is warmer than the upper one by a factor of \(2^{1 / 4}\). The surface is warmer than the lower blanket by a smaller factor.)

The heat capacity of liquid \(^{4} \mathrm{He}\) below \(0.6 \mathrm{K}\) is proportional to \(T^{3},\) with the measured value \(C_{V} / N k=(T / 4.67 \mathrm{K})^{3}\). This behavior suggests that the dominant excitations at low temperature are long-wavelength phonons. The only important difference between phonons in a liquid and phonons in a solid is that a liquid cannot transmit transversely polarized waves - sound waves must be longitudinal. The speed of sound in liquid \(^{4} \mathrm{He}\) is \(238 \mathrm{m} / \mathrm{s}\), and the density is \(0.145 \mathrm{g} / \mathrm{cm}^{3} .\) From these numbers, calculate the phonon contribution to the heat capacity of \(^{4} \mathrm{He}\) in the low-temperature limit, and compare to the measured value.

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