/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Consider a free Fermi gas in two... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider a free Fermi gas in two dimensions, confined to a square \(\operatorname{area} A=L^{2}\) (a) Find the Fermi energy (in terms of \(N\) and \(A\) ), and show that the average energy of the particles is \(\epsilon_{\mathrm{F}} / 2\) (b) Derive a formula for the density of states. You should find that it is a constant, independent of \(\epsilon\) (c) Explain how the chemical potential of this system should behave as a function of temperature, both when \(k T \ll \epsilon_{\mathrm{F}}\) and when \(T\) is much higher. (d) Because \(g(\epsilon)\) is a constant for this system, it is possible to carry out the integral 7.53 for the number of particles analytically. Do so, and solve for \(\mu\) as a function of \(N .\) Show that the resulting formula has the expected qualitative behavior. (e) Show that in the high-temperature limit, \(k T \gg \epsilon_{\mathrm{F}},\) the chemical potential of this system is the same as that of an ordinary ideal gas.

Short Answer

Expert verified
The Fermi energy is \(\epsilon_F = \frac{2\pi\hbar^2 N}{mA}\); \(g(\epsilon)\) is constant. \(\mu\) matches ideal gas at high \(T\).

Step by step solution

01

Understand the Problem

We have a two-dimensional non-interacting Fermi gas confined to an area \(A = L^2\). Our tasks involve finding the Fermi energy, deriving the density of states, interpreting the chemical potential's behavior across temperatures, and analyzing the behavior in the high-temperature limit.
02

Derive the Fermi Energy

In two dimensions, the Fermi wavevector is determined by the condition \(N = g \sum_{k < k_F} 1\), where \(g\) is the degeneracy factor. For a two-dimensional gas, \(k_F = \sqrt{4\pi N/A}\). The Fermi energy is then given by \(\epsilon_F = \frac{\hbar^2 k_F^2}{2m}\). Substituting \(k_F = \sqrt{4\pi N/A}\), we find \(\epsilon_F = \frac{2\pi\hbar^2 N}{mA}\).
03

Calculate the Average Energy

The average energy per particle for a two-dimensional Fermi gas is \(\frac{1}{N} \int_0^{\epsilon_F} \epsilon g(\epsilon) d\epsilon\) with \(g(\epsilon) = \frac{A}{2\pi\hbar^2}m\). Upon integration, you find that the average energy per particle is \(\frac{\epsilon_F}{2}\).
04

Derive the Density of States

The density of states \(g(\epsilon)\) for a two-dimensional system is obtained by differentiating the number of states \(N(\epsilon)\) with respect to energy: \(g(\epsilon) = \frac{d}{d\epsilon}N(\epsilon) = \frac{mA}{2\pi\hbar^2}\), which is indeed constant and independent of \(\epsilon\).
05

Chemical Potential Behavior with Temperature

For low temperatures \(kT \ll \epsilon_F\), the chemical potential is approximately \(\epsilon_F\), as the particles are primarily near the Fermi surface. In high temperatures, \(T\) is much higher, and the chemical potential aligns more with that of a classical ideal gas, dominated by thermal excitations.
06

Solve for Chemical Potential as a Function of N

The integral for the number of particles is \(N = \int_{0}^{\infty} \frac{g(\epsilon)}{e^{(\epsilon - \mu)/(kT)} + 1} d\epsilon\). Since \(g(\epsilon)\) is constant, this integral can be performed analytically to show that \(\mu\) adjusts with \(N\) and retains qualitative features anticipated by quantum statistics.
07

Analyze High-Temperature Limit

In the high-temperature limit \(kT \gg \epsilon_F\), the occupancy approaches that of a classical system, and the chemical potential \(\mu\) needs to be adjusted to match that of an ideal gas, \(-kT \ln(N/A)\), due to heightened thermal energies compared to the Fermi energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fermi Gas
Fermi gas is a theoretical construct used in quantum mechanics to describe a collection of non-interacting fermions, such as electrons, confined in a particular volume. These fermions follow the Pauli exclusion principle, which means that no two particles can occupy the same quantum state simultaneously. In the case of our exercise, the Fermi gas is defined in a two-dimensional space with area \( A = L^2 \).

In two dimensions, the density and behavior of these particles depend on factors like the Fermi energy and temperature. The Fermi energy represents the highest energy level occupied by a fermion at zero temperature. For a Fermi gas, the particles fill up quantum states up to this energy level.

An important aspect of studying a Fermi gas is understanding how these particles are distributed within the system. This is especially critical at zero temperature, where all available states up to the Fermi energy are occupied. Examining this distribution helps clarify various physical properties, such as conductance and heat capacity, which are crucial in materials science and solid-state physics.
Density of States
The density of states (DOS) is a concept in quantum mechanics that characterizes how many quantum states are available for occupation at each energy level within a system. In simpler terms, it tells us how the energy levels are distributed in a material. For a two-dimensional Fermi gas system, the calculation of the DOS is simplified.

In the context of our exercise, the DOS for a two-dimensional Fermi gas is given by \( g(\epsilon) = \frac{mA}{2\pi\hbar^2} \). As derived in the solution, this expression is constant and does not depend on the energy \( \epsilon \).

  • This constancy is a special characteristic of two-dimensional systems.
  • It implies that each energy level up to the Fermi energy has the same weight in terms of available states for occupation.
  • The overall physical properties, such as the electrical conductivity, of the system can depend heavily on the form of the DOS.
The form of DOS impacts other properties and calculations, making it a fundamental quantity in understanding how particles behave within quantum systems.
Chemical Potential
The chemical potential \( \mu \) represents the change in the energy of a system when an additional particle is introduced, keeping temperature and volume constant. In simpler terms, it's like an energy cost for adding more particles to the system, and it plays a crucial role in determining how particles distribute themselves at various temperatures.

At very low temperatures, where \( kT \ll \epsilon_F \), the chemical potential approaches the Fermi energy \( \epsilon_F \). This is because at low temperatures, additional particles tend to occupy states near this energy level.

As the temperature increases and becomes much higher than the Fermi energy, \( kT \gg \epsilon_F \), the system behaves more like a classical ideal gas. Here, the chemical potential is adjusted due to thermal excitations, often aligning with \( \mu = -kT \ln(N/A) \), similar to an ideal gas law description.

Understanding chemical potential in different regimes helps in characterizing the thermodynamic properties of a system, providing insights into how temperature affects particle behavior, phase transitions, and more.
Fermi Energy
Fermi energy \( \epsilon_F \) is a concept from quantum mechanics that defines the highest energy level occupied by fermions at absolute zero temperature. It's a crucial parameter in understanding the quantum state distribution of particles, such as electrons in metals or semiconductors.

In the context of a two-dimensional gas, the Fermi energy is defined by the expression \( \epsilon_F = \frac{2\pi\hbar^2 N}{mA} \). This equation shows us that the Fermi energy depends on the number of particles \( N \), the mass \( m \), and the area \( A \) in which the gas is confined.

  • Higher Fermi energy signifies that particles can occupy higher energy states.
  • It's a key determinant of the electrical and thermal properties of the material.
  • \( \epsilon_F \) helps in predicting outcomes, such as in electron energy loss or decay processes in weak interactions.
Fermi energy is not just a theoretical parameter but a value that can be measured and used to compare with predictions from other more complex systems, providing a foundational understanding of quantum statistics in condensed matter physics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider a system of five particles, inside a container where the allowed energy levels are nondegenerate and evenly spaced. For instance, the particles could be trapped in a one-dimensional harmonic oscillator potential. In this problem you will consider the allowed states for this system, depending on whether the particles are identical fermions, identical bosons, or distinguishable particles. (a) Describe the ground state of this system, for each of these three cases. (b) Suppose that the system has one unit of energy (above the ground state). Describe the allowed states of the system, for each of the three cases. How many possible system states are there in each case? (c) Repeat part (b) for two units of energy and for three units of energy. (d) Suppose that the temperature of this system is low, so that the total energy is low (though not necessarily zero). In what way will the behavior of the bosonic system differ from that of the system of distinguishable particles? Discuss.

Consider two single-particle states, \(A\) and \(B,\) in a system of fermions, where \(\epsilon_{A}=\mu-x\) and \(\epsilon_{B}=\mu+x ;\) that is, level \(A\) lies below \(\mu\) by the same amount that level \(B\) lies above \(\mu\). Prove that the probability of level \(B\) being occupied is the same as the probability of level \(A\) being unoccupied. In other words, the Fermi-Dirac distribution is "symmetrical" about the point where \(\epsilon=\mu\).

Suppose you have a "box" in which each particle may occupy any of 10 single- particle states. For simplicity, assume that each of these states has energy zero. (a) What is the partition function of this system if the box contains only one particle? (b) What is the partition function of this system if the box contains two distinguishable particles? (c) What is the partition function if the box contains two identical bosons? (d) What is the partition function if the box contains two identical fermions? (e) What would be the partition function of this system according to equation \(7.16 ?\) (f) What is the probability of finding both particles in the same single- particle state, for the three cases of distinguishable particles, identical bosons, and identical fermions?

For a system of fermions at room temperature, compute the probability of a single-particle state being occupied if its energy is (a) \(1 \mathrm{eV}\) less than \(\mu\) (b) \(0.01 \mathrm{eV}\) less than \(\mu\) (c) equal to \(\mu\) (d) \(0.01 \mathrm{eV}\) greater than \(\mu\) (e) \(1 \mathrm{eV}\) greater than \(\mu\)

An atomic nucleus can be crudely modeled as a gas of nucleons with a number density of \(0.18 \mathrm{fm}^{-3}\) (where \(1 \mathrm{fm}=10^{-15} \mathrm{m}\) ). Because nucleons come in two different types (protons and neutrons), each with spin \(1 / 2,\) each spatial wavefunction can hold four nucleons. Calculate the Fermi energy of this system, in MeV. Also calculate the Fermi temperature, and comment on the result.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.