Chapter 5: Problem 17
A \(55-\mathrm{kg}\) athlete leaps into the air from a crouching position. Her center of mass rises \(60 \mathrm{~cm}\) as her feet leave the ground and then it continues another \(80 \mathrm{~cm}\) to the top of the leap. What is the average power she develops, assuming the force on the ground is constant?
Short Answer
Step by step solution
Understanding the Problem
Calculate the Total Height Raised
Calculate the Work Done
Assume Time Duration for Leap
Calculate the Average Power Developed
Verification and Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gravitational Potential Energy
- \( W \) is the work done and hence the energy in joules (J).
- \( m \) is the mass of the athlete (55 kg in this case).
- \( g \) is the gravitational constant, approximately \( 9.8 \, \text{m/s}^2 \).
- \( h \) is the total height change, converted into meters (1.4 m here).
Power Calculation
- \( P \) stands for power, measured in watts (W).
- \( W \) is the work done, here calculated as 754.6 J.
- \( t \) is the time taken to perform the work.Typically for jumps, we assume a short time duration like 0.5 s.