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A \(50 \mathrm{~kg}\) woman jumps straight into the air, rising \(0.8 \mathrm{~m}\) from the ground. What impulse does she receive from the ground to attain this height?

Short Answer

Expert verified
The impulse she receives from the ground is 198 kgâ‹…m/s.

Step by step solution

01

Understand Impulse and its Formula

Impulse is defined as the change in momentum of an object when a force is applied over time. It can be calculated using the formula: \( J = \Delta p = m \Delta v \), where \( J \) is the impulse, \( m \) is the mass, and \( \Delta v \) is the change in velocity.
02

Determine Final Velocity at Maximum Height

At the maximum height of her jump, the woman's velocity is 0. We need to use the kinematic equation \( v^2 = u^2 + 2as \) where \( v \) is the final velocity (0 m/s at the top), \( u \) is the initial velocity, \( a \) is the acceleration (-9.8 m/s² due to gravity), and \( s \) is the height (0.8 m). Solving this for initial velocity, we get: \( 0 = u^2 - 2(9.8)(0.8) \), which gives \( u^2 = 15.68 \) and \( u \approx 3.96 \text{ m/s} \).
03

Calculate Initial Momentum

The initial momentum (just as she leaves the ground) can be calculated using her mass and the initial velocity we found earlier. \( p_{initial} = m \cdot u = 50 \cdot 3.96 = 198 \text{ kg m/s} \).
04

Calculate Impulse from the Ground

Since she starts from rest, her initial momentum is 0 (just before the jump). The impulse can be found using the formula: \( J = \Delta p = p_{final} - p_{initial} \). So, \( J = 198 \text{ kg m/s} - 0 = 198 \text{ kg m/s} \).
05

Conclusion

The impulse provided by the ground to the woman in order for her to reach a height of 0.8 m is 198 kgâ‹…m/s. This impulse corresponds to the change in her momentum from rest to that at takeoff.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
Momentum is a fundamental concept in mechanics that describes the quantity of motion an object possesses. It is a vector quantity, meaning it has both magnitude and direction, and is calculated as the product of an object's mass and its velocity. The formula is given by:
  • Momentum, \( p = m imes v \)
  • where \( p \) is momentum, \( m \) is mass in kilograms, and \( v \) is velocity in meters per second.
Momentum helps in understanding how difficult it is to stop a moving object. The greater the momentum, the more exertion required to bring the object to a halt. For instance, in the original exercise, the woman has an initial velocity of approximately 3.96 m/s as she leaves the ground. Therefore, her initial momentum can be calculated based on her mass and velocity.

Since impulse involves change in momentum, it’s crucial to grasp that momentum at any point is directly tied to how an object was accelerated or decelerated before that exact moment.
Kinematic Equations
Kinematic equations are invaluable tools in mechanics that describe the motion of objects under constant acceleration without considering the forces causing the motion. They allow us to predict various aspects of an object's motion such as velocity and displacement over time. In scenarios where acceleration is constant, like free-falling objects under gravity, these equations are extremely useful.
  • One of the basic kinematic equations used in the given exercise is: \( v^2 = u^2 + 2as \)
  • where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration, and \( s \) is the displacement (height).
This particular equation helps determine the initial velocity required for an object to reach a certain height. By setting the final velocity as zero at the highest point of a jump, the equation allows for solving the initial velocity, which is crucial in calculating impulse. Thus, using the kinematic equation connects the initial velocity with the height achieved by the woman in the exercise.
Gravity
Gravity is a force that attracts two bodies towards each other, and it plays a significant role in everyday motion on Earth. It is responsible for giving weight to physical objects and causes them to fall towards the center of the Earth when dropped. The acceleration due to gravity is approximately \( 9.8 \text{ m/s}^2 \) (meters per second squared), and this value is essential in calculating the effects of gravity on objects in free fall.

In the context of the exercise, gravity is the force acting against the woman's jump. As she ascends, gravity slows her down until she reaches her peak height where her speed is zero, before pulling her back down. The kinematic equations utilize this constant acceleration value to determine the initial velocity and consequentially the impulse.
  • The force of gravity provides the negative acceleration \( a = -9.8 \text{ m/s}^2 \) in the kinematic equation.
  • This constant pull of gravity opposes the upward motion, and hence becomes a key factor in calculating her energy needs to overcome it and reach the height of 0.8 m.
Understanding gravity's role allows for an accurate analysis of motion characteristics and energy transitions in events such as jumping.

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