/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 A turbojet engine has the follow... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A turbojet engine has the following design-point parameters: $$ \begin{aligned} M_{0} &=0, p_{0}=101.33 \mathrm{kPa}, T_{0}=15.2^{\circ} \mathrm{C} \\ \pi_{\mathrm{d}} &=0.98 \\ \pi_{\mathrm{c}} &=25, e_{\mathrm{c}}=0.90 \\ M_{4} &=1.0 \\ Q_{\mathrm{R}} &=42,800 \mathrm{~kJ} / \mathrm{kg}, \pi_{\mathrm{b}}=0.95, \eta_{\mathrm{b}}=0.98, \tau_{\lambda}=6.0 \\ e_{\mathrm{t}} &=0.85, \eta_{\mathrm{m}}=0.98 \\ \pi_{\mathrm{n}} &=0.97, p_{9}=p_{0} \\ \dot{m}_{\mathrm{c} 2} &=80 \mathrm{~kg} / \mathrm{s}, M_{z 2}=0.50 \end{aligned} $$ Calculate (a) fuel-to-air ratio \(f\) (b) turbine total temperature ratio \(\tau_{\mathrm{t}}\) For the following off-design operation $$ \begin{aligned} M_{0} &=0.85, p_{0}=20 \mathrm{kPa}, T_{0}=-15^{\circ} \mathrm{C} \\ \tau_{\lambda} &=6.5 \\ e_{\mathrm{t}} &=0.80, \eta_{\mathrm{m}}=0.98, \pi_{\mathrm{n}}=0.97, p_{9}=p_{0} \end{aligned} $$ Assume a calorically perfect gas with \(\gamma=1.4\) and \(c_{p}=1004\) \(\mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K}\) constant throughout the engine, and calculate (c) \(\pi_{\mathrm{c}-\mathrm{off} \text {-design }}\) (d) the ratio of corrected shaft speeds \(N_{\mathrm{c} 2, \mathrm{O}-\mathrm{D}} / N_{\mathrm{c} 2, \mathrm{D}}\) (e) the corrected mass flow rate at off-design (kg/s) (f) the axial Mach number at the engine face, \(M_{z 2}\), atoff-design (g) thrust-specific fuel consumption at design and offdesign in \(\mathrm{mg} / \mathrm{s} / \mathrm{N}\)

Short Answer

Expert verified
The solution will be obtained following the steps. Each part of the problem might require multiple computational steps dependent on required parameters for the calculations. The problem requires a detailed understanding of aero engine performance and the ability to apply specific relationships and equations to solve the problem.

Step by step solution

01

Calculations for Fuel-to-air Ratio

Firstly, the fuel-to-air ratio (f) can be calculated using the energy balance equation of the combustor. The energy given to the air by the burning fuel is \(fQ_{R}\) and the energy obtained by the air is \(c_{p}T_{4}(\tau_{\lambda}-1)\). Equating energy given and obtained provides the fuel-to-air ratio.
02

Calculation for Turbine Total Temperature Ratio

For the turbine total temperature ratio \(\tau_{t}\), we make use of the relationship derived from the energy balance at the turbine. The energy that the turbine extracts from the air is \(\tau_{t}=\tau_{\lambda}/\tau_{r}\) where \(\tau_{r}=(1+f)\pi_{r}\) with \(\pi_{r}\) for the ram compression ratio derived from the isentropic flow relations.
03

Calculation for Corrected Shaft Speed Ratio

For corrected shaft speed ratio, we can make use of the equation \(\frac{N_{C2, O-D}}{N_{C2, D}}=\sqrt{\frac{T_{0, O-D}}{T_{0, D}}}\times \frac{p_{0, D}}{p_{0, O-D}}\) by substituting the given temperature and pressure at off-design operation.
04

Calculation for Corrected Mass Flow Rate

The corrected mass flow rate can be obtained using the ratio \(\frac{\dot{m}_{C2, O-D}}{\dot{m}_{C2, D}}=\frac{T_{0, O-D}}{T_{0, D}}\sqrt{\frac{p_{0, D}}{p_{0, O-D}}}\) where we substitute the given temperature and pressure at off-design operation.
05

Calculation for Axial Mach Number

The axial mach number at off-design, \(M_z2\) can be obtained by solving mass flow rate per unit area \(A2_{O-D}\) which is \(\dot{m}_{C2, O-D}=\dot{m}_{C2, D}A2_{O-D}M_z2 \sqrt{\frac{\gamma RT_{0, O-D}}{1+\frac{\gamma -1}{2}M_z2^2}}\) for \(M_z2\) where A refers to the choked flow area at station 2.
06

Calculation for Thrust-specific Fuel Consumption

Finally, Thrust-specific fuel consumption can be calculated using \(TSFC=\frac{\dot{m}_f}{F}\) where thrust, F, can be calculated by using the equation \(F=\dot{m}(1+f)V9-A9p9+(A2p2-A9p9)\) for choked flow conditions in outlet plane 9 of the engine.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fuel-to-Air Ratio
The fuel-to-air ratio is crucial in a turbojet engine. It represents the proportion of fuel mass to air mass. This ratio is significant because it determines the energy input to the engine. The equation utilized for calculation is derived from the energy balance within the combustor.

Here, the burning fuel imparts energy, calculated as \(fQ_{R}\), to the air. Conversely, the air gains energy calculated by \(c_{p}T_{4}(\tau_{\lambda}-1)\). By equating these two energy expressions, one finds the fuel-to-air ratio.
  • \(f\) - Fuel-to-air ratio
  • \(Q_{R}\) - Heating value of the fuel
  • \(c_{p}\) - Specific heat at constant pressure
  • \(T_{4}\) - Total temperature at combustor exit
  • \(\tau_{\lambda}\) - Total temperature ratio through combustion
Understanding this balance enables efficient engine operation and performance enhancements.
Turbine Total Temperature Ratio
The turbine total temperature ratio, \(\tau_{t}\), is a key parameter to evaluate the efficiency of energy extraction in a turbine. It relates the temperature before and after the turbine.

In our turbojet analysis, this ratio is informed by the energy balance within the turbine. The total temperature ratio is defined as \(\tau_{t}=\frac{\tau_{\lambda}}{\tau_{r}}\), with \(\tau_{\lambda}\) being the total temperature ratio through combustion and \(\tau_{r}\) a derived ram compression ratio. This ram compression ratio can be found using isentropic flow relations and the fuel-to-air ratio \(f\).
  • Efficient calculation ensures optimal turbine energy extraction.
  • A proper \(\tau_{t}\) reflects balanced combustion and turbine processing.
In summary, knowing \(\tau_{t}\) helps in designing engines with improved efficiency and performance.
Corrected Shaft Speed Ratio
The corrected shaft speed ratio assesses how well the turbojet engine can adapt to off-design conditions. Understanding this ratio is vital for maintaining engine performance under varying atmospheric conditions.

This calculation uses the relation \(\frac{N_{C2, O-D}}{N_{C2, D}}=\sqrt{\frac{T_{0, O-D}}{T_{0, D}}}\times \frac{p_{0, D}}{p_{0, O-D}}\). Here, you'll need the temperature and pressure data both at design and off-design states.
  • \(N_{C2, O-D}\) - Corrected shaft speed off-design
  • \(N_{C2, D}\) - Corrected shaft speed at design
  • Variables \(T\) and \(p\) - Temperature and pressure conditions
Keen insight into this evaluation promotes a better understanding of performance limitations and necessary adjustments.
Corrected Mass Flow Rate
Knowing the corrected mass flow rate at off-design conditions assists engineers in determining how the engine manages airflow variances. This is integral to sustaining performance and efficiency.

The relationship used is \(\frac{\dot{m}_{C2, O-D}}{\dot{m}_{C2, D}}=\frac{T_{0, O-D}}{T_{0, D}}\sqrt{\frac{p_{0, D}}{p_{0, O-D}}}\). This formula relies on temperatures and pressures during different operational states.
  • \(\dot{m}_{C2, O-D}\) - Off-design mass flow rate
  • \(\dot{m}_{C2, D}\) - Design mass flow rate
  • Inputs include environmental temperature and pressure readings.
Adjustments based on these calculations can significantly enhance engine reliability.
Thrust-Specific Fuel Consumption
Thrust-specific fuel consumption (TSFC) is used to measure the fuel efficiency of a turbojet engine. It indicates how much fuel is needed to produce a specific amount of thrust.

Calculated using \(TSFC=\frac{\dot{m}_f}{F}\), where \(\dot{m}_f\) is the fuel mass flow rate and \(F\) is the engine thrust. TSFC helps compare how different engines or settings affect performance.
  • A lower TSFC indicates a more efficient engine.
  • This can inform decisions on enhancements to reduce fuel consumption.
By reviewing TSFC across design and off-design conditions, engineers can fine-tune the engine for optimal efficiency.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A turbojet engine has a design corrected mass flow rate of \(\dot{m}_{c 2}=100 \mathrm{~kg} / \mathrm{s}\) at the standard sea level static condition. The design axial Mach number at the engine face is \(\mathrm{M}_{22}=0.5\). Calculate the engine face flow area, \(\mathrm{A}_{2}\), in \(\mathrm{m}^{2}\left(\gamma=1.4, \mathrm{R}=287 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \mathrm{p}_{\mathrm{SL}}=101 \mathrm{kPa}\right.\) and \(\mathrm{T}_{\mathrm{SL}}=\) \(288 \mathrm{~K})\).

In aturbojet engine, the compressor face total pressure and temperature are \(112 \mathrm{kPa}\) and \(268 \mathrm{~K}\), respectively. The shaft speed is \(6400 \mathrm{rpm}\). The air mass flow rate is \(125 \mathrm{~kg} / \mathrm{s}\) and the fuel mass flow rate is \(2.5 \mathrm{~kg} / \mathrm{s}\). The fuel heating value is \(42,000 \mathrm{~kJ} / \mathrm{kg}\) and the engine produces \(145 \mathrm{kN}\) of thrust. Express the following engine corrected parameters: (a) the corrected (air) mass flow rate \(\dot{m}_{\mathrm{c} 2}\) in \(\mathrm{kg} / \mathrm{s}\) assuming \(p_{\mathrm{t} 2}=0.99 p_{\mathrm{t} 0}\) (b) the corrected shaft speed \(N_{\mathrm{c} 2}\) in rpm (c) the corrected fuel flow rate, \(\dot{m}_{\mathrm{fc}}\), in \(\mathrm{kg} / \mathrm{s}\) (d) the corrected thrust \(F_{\mathrm{c}}\) in \(\mathrm{kN}\) (e) the corrected thrust-specific fuel consumption \(\mathrm{TSFC}_{\mathrm{c}}\) in \(\mathrm{mg} / \mathrm{s} / \mathrm{N}\).

A high-pressure ratio compressor performance map is shown. The nominal operating line corresponds to \(T_{\mathrm{t} 4} / T_{\mathrm{t} 2}=\) 6.5. Assuming a constant turbine adiabatic efficiency of \(\eta_{\mathrm{t}}=\) \(0.88\) at on- and off-designs, calculate and plot the pumping characteristics of the gas generator similar to Example 11.1. The design corrected mass flow rate is \(180 \mathrm{~kg} / \mathrm{s}\), with \(\pi_{\mathrm{c} \text {, design }}\) \(=27.5\). Assume $$ \begin{aligned} \gamma_{\mathrm{c}} &=1.4, c_{p \mathrm{c}}=1004 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K} \\ \gamma_{\mathrm{t}} &=1.4, c_{p \mathrm{t}}=1156 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K} \\ f & \approx 0.03 \\ \eta_{\mathrm{m}} &=0.995 \\ \pi_{\mathrm{b}} &=0.95 \end{aligned} $$

The corrected mass flow rate at the engine face is \(\dot{m}_{\mathrm{c} 2}=180 \mathrm{~kg} / \mathrm{s}\). Calculate the axial Mach number \(M_{z 2}\) at the engine face for \(A_{2}=1 \mathrm{~m}^{2}\). Also calculate the capture area \(A_{0}\) for a flight Mach number of \(M_{0}=0.85\) and assume an inlet total pressure recovery \(\pi_{\mathrm{d}}=0.995 .\) Assume \(\gamma_{\mathrm{c}}=1.4 . R_{\mathrm{c}}=\) \(287 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, p_{0}=30 \mathrm{kPa}\) and \(T_{0}=250 \mathrm{~K}\).

An afterburner on- or off-mode should not affect the turbine back pressure. This requirement is often met by a variable throat convergent-divergent exhaust nozzle. The "dry" mode is characterized by a lower total pressure loss and an adiabatic flow: $$ \begin{aligned} \pi_{\mathrm{AB}-\mathrm{dry}} &=0.96, \tau_{\mathrm{AB}-\mathrm{dry}}=T_{\mathrm{t} 7} / T_{\mathrm{t} 5}=1.0, \\ \gamma_{\mathrm{AB}-\mathrm{dry}} &=1.33, c_{p \mathrm{AB}-\mathrm{dry}}=1156 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K} \end{aligned} $$ The "wet" mode is characterized by a higher total pressure loss and chemical energy release $$ \begin{aligned} \pi_{\mathrm{AB}-\mathrm{wet}} &=0.90, \tau_{\mathrm{AB}-\mathrm{wet}}=T_{\mathrm{t} 7} / T_{\mathrm{t} 5}=2.0 \\ \gamma_{\mathrm{AB}-\mathrm{wet}} &=1.30, c_{p \mathrm{AB}-\mathrm{wet}}=1243 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K} \\ Q_{\mathrm{R}, \mathrm{AB}} &=42,000 \mathrm{~kJ} / \mathrm{kg}, \eta_{\mathrm{AB}}=0.95 \end{aligned} $$ The turbine entry temperature (TET) is \(T_{\mathrm{t} 4}=1760 \mathrm{~K}\) and \(p_{\mathrm{t} 4}=2.0 \mathrm{MPa}\) (in both dry and wet modes) and the turbine expansion parameter \(\tau_{\mathrm{t}}=0.80\) and \(\eta_{\mathrm{t}}=0.85\). The gas properties in the turbine are \(\gamma_{\mathrm{t}}=1.33\) and \(c_{p \mathrm{t}}=1156 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). The corrected mass flow rate at turbine entry is \(\dot{m}_{\mathrm{c} 4}=80 \mathrm{~kg} / \mathrm{s}\) and turbine nozzle is choked, \(M_{4}=1.0\).\ The exhaust nozzle in dry and wet modes is choked, i.e., \(M_{8}=1.0\). The total pressure ratio in the convergent (part of the) nozzle is \(p_{\mathrm{t} 8} / p_{\mathrm{t} 7}=0.98\) for dry and \(0.95\) for wet mode. The nozzle divergent section has a total pressure ratio of \(p_{19} / p_{\mathrm{t} 8}=\) \(0.99\) for dry and \(0.95\) for wet operation. Calculate (a) \(A_{4}\left(\mathrm{~m}^{2}\right)\) (b) \(A_{5}\left(\mathrm{~m}^{2}\right)\) for \(M_{5}=0.5\) (c) \(f_{\mathrm{AB}}\) (d) \(A_{\mathrm{g}}\left(\mathrm{m}^{2}\right)\) "dry" (e) \(A_{\mathrm{g}}\left(\mathrm{m}^{2}\right)\) "wet" (f) \(A_{9} / A_{8}\) "dry" for \(p_{9}=p_{0}=100 \mathrm{kPa}\) (g) \(A_{9} / A_{8}\) "wet" for \(p_{9}=p_{0}=100 \mathrm{kPa}\) (h) nozzle gross thrust ( \(\mathrm{kN}\) ) "dry" (i) nozzle gross thrust \((\mathrm{kN})\) "wet"

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.