/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 The leading edge on a turbine no... [FREE SOLUTION] | 91Ó°ÊÓ

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The leading edge on a turbine nozzle is to be internally cooled using an impingement cooling technique, as shown. The leading-edge diameter is \(8 \mathrm{~mm}\). Calculate the heat transfer coefficient \(h_{\mathrm{g}}\) at the leading edge, assuming an augmentation factor \(a=1.5\) due to a high-intensity turbulent flow in the turbine (use Equation \(10.81\) for a cylinder in cross- flow). $$ \begin{aligned} &M_{g}=0.5 \\ &\gamma_{g}=1.33 \\ &c_{p g}=1156 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K} \\ &k_{g}=0.082 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K} \\ &T_{\mathrm{g}}=1500 \mathrm{~K} \\ &p_{g}=1.0 \mathrm{MPa} \\ &\operatorname{Pr}_{g}=0.70 \\ &\mu_{g}=4.9 \times 10^{-5} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s} \end{aligned} $$

Short Answer

Expert verified
To calculate the heat transfer coefficient \(h_g\), we first compute the Reynolds number using the formula and given values. Then we use this Reynolds number in equation 10.81 to calculate the Nusselt number. With this number, we can then compute \(h_g\) by applying the formula with the augmentation factor and the given properties.

Step by step solution

01

Calculating Reynolds number

The Reynolds number (Re) is first calculated using the formula: \[ Re = \frac{M_g c_{pg} T_g}{\mu_g} \] where, \( M_g = 0.5 \) is the Mach number, \( c_{pg} = 1156 J/kg \cdot K \) is the specific heat capacity, \( T_g = 1500 K \) is the gas temperature and \( \mu_g = 4.9 \times 10^{-5} kg/m \cdot s \) is the dynamic viscosity.
02

Substituting values into the Reynolds formula

Substitute these values into the formula for Reynolds number: \[ Re = \frac{0.5 \times 1156 \times 1500}{4.9 \times 10^{-5}} \]
03

Computing Reynolds number

Calculate the above equation to get the Reynolds number (Re).
04

Calculating Nu using equation 10.81

With the Reynolds number computed, Now we calculate the Nusselt number using equation 10.81: \[ Nu_g = 0.3 + \frac{0.62 Re^{0.5} Pr^{1/3}}{[1 + (0.4/Pr)^{2/3}]^{1/4}} \left[ 1 + \left( \frac{Re}{282000} \right)^{5/8} \right]^{4/5} \] Here, \( Pr = 0.70 \) is the Prandtl number.
05

Substituting values into the Nu formula

Substitute the corresponding values into the formula for Nusselt number.
06

Computing Nusselt number

Calculate the above equation to get the Nusselt number (Nu).
07

Calculating the value of \(h_g\)

Finally, the heat transfer coefficient \(h_g\) can be found from the Nusselt number by using the formula: \[ h_g = a \times Nu \times \frac{k_g}{D} \] where, \( a = 1.5 \) is the augmentation factor, \( k_g = 0.082 W/m \cdot K \) is the thermal conductivity and \( D = 8mm = 0.008m \) is the diameter.
08

Substituting values into the \(h_g\) formula

Substitute the obtained Nu and given values into the formula for \(h_g\).
09

Computing heat transfer coefficient

Calculate the formula to find the value of \(h_g\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Heat Transfer Coefficient
The heat transfer coefficient, denoted as h, is a crucial parameter in understanding how effectively heat is transferred between a fluid and a surface. In the context of impingement cooling techniques, the coefficient indicates the rate at which heat is absorbed by the coolant (fluid) from the surface of the turbine nozzle's leading edge.

Higher values of the heat transfer coefficient indicate more efficient cooling, which is important for preventing thermal damage in high-temperature environments of turbine operations. The coefficient itself is influenced by various factors including fluid velocity, viscosity, and thermal conductivity, as well as surface characteristics like shape and roughness.

The equation used to calculate the heat transfer coefficient combines the Nusselt number (\textbf{Nu}), the thermal conductivity of the gas (\textbf{k_g}), the augmentation factor (\textbf{a}) due to intense turbulent flow, and the characteristic length of the object being cooled—in this case, the diameter of the turbine's leading edge (D). The formula is expressed as:
\[ h_g = a \times Nu \times \frac{k_g}{D} \]
The augmentation factor used in the formula accounts for the increased efficiency of heat transfer due to high-intensity turbulence, which is common in the demanding operational conditions of turbines.
Reynolds Number and Its Role in Cooling
The Reynolds number, often abbreviated as Re, is a dimensionless value that describes the flow characteristics of a fluid. It helps in characterizing the type of flow—whether it's laminar or turbulent. This number is critical when determining the heat transfer properties for an impingement cooling technique.

Laminar flow, which occurs at low Reynolds numbers, involves smooth, consistent motion of the fluid, where viscous forces are dominant. Turbulent flow, on the other hand, occurs at high Reynolds numbers, and is characterized by chaotic fluid motion dominated by inertial forces, leading to enhanced mixing and potentially higher heat transfer rates.

The formula for calculating the Reynolds number involves the fluid's velocity (\textbf{M_g}), its specific heat capacity at constant pressure (\textbf{c_pg}), the temperature (\textbf{T_g}), and its dynamic viscosity (\textbf{\textmu_g}), as shown:
\[ Re = \frac{M_g c_{pg} T_g}{\textmu_g} \]
Understanding the Reynolds number is crucial for engineers to ensure efficient heat transfer by optimizing flow conditions for the best cooling performance.
Significance of the Nusselt Number in Heat Transfer
The Nusselt number (Nu) is another dimensionless value that is integral to the study of heat transfer. It relates the convective heat transfer to the conductive heat transfer at a surface. A higher Nusselt number indicates that convection is more efficient compared to conduction, leading to more effective cooling.

The calculation of the Nusselt number involves the Reynolds number, the Prandtl number (Pr), and incorporates both the properties of the fluid and the flow conditions. The formula for a cylinder in cross-flow, which is used in the impingement cooling technique, can be quite complex, as shown:
\[ Nu_g = 0.3 + \frac{0.62 Re^{0.5} Pr^{1/3}}{[1 + (0.4/Pr)^{2/3}]^{1/4}} \left[ 1 + \left( \frac{Re}{282000} \right)^{5/8} \right]^{4/5} \]
The optimization of the Nusselt number, through the manipulation of flow conditions and surface properties, allows for improved cooling efficiency in applications like turbine blade cooling. Ultimately, understanding the Nusselt number's role helps in achieving better thermal management in various engineering systems.

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Most popular questions from this chapter

Consider the flow of high-temperature, high Mach number gas over a flat wall, \(\left(M_{\mathrm{g}}=1.0, \gamma_{\mathrm{g}}=1.33, c_{p g}=\right.\) \(1156 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, T_{g}=1420 \mathrm{~K}, p_{g}=12 \mathrm{kPa}, \operatorname{Pr}_{g}=0.70\) ). We intend to internally cool the wall to achieve a wall temperature of \(T_{\mathrm{wg}}=1200 \mathrm{~K}\). Assuming the gas-side Stanton number is \(\mathrm{St}_{g}=0.005\), calculate (a) the gas stagnation temperature \(T_{\mathrm{tg}} \mathrm{K}\) (b) the adiabatic wall temperature \(T_{\mathrm{aw}} \mathrm{K}\) for a turbulent boundary layer (c) the gas-side film coefficient \(h_{\mathrm{g}} \mathrm{W} / \mathrm{m}^{2} \mathrm{~K}\) (d) the heat flux to the wall \(q_{\mathrm{w}} \mathrm{kW} / \mathrm{m}^{2}\) For a wall thickness of \(t_{w}=3 \mathrm{~mm}\), and a thermal conductivity, \(k_{\mathrm{w}}=14.9 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), calculate (e) the wall temperature on the coolant side \(T_{\mathrm{wc}} \mathrm{K}\)

The Stanton number is in general a function of Prandtl and Reynolds numbers, among other nondimensional parameters such as Mach number, roughness, curvature, freestream turbulence intensity, etc. Eckert-Livingood model for a flat plate with constant wall temperature, excluding all other effects except Prandtl number and the Reynolds number, is $$ \mathrm{St}_{\mathrm{g}}=0.0296 \operatorname{Pr}_{\mathrm{g}}^{-2 / 3} \mathrm{Re}_{x}^{-1 / 5} $$ for a turbulent boundary layer. The Prandtl number for the gas is \(0.704\) and remains constant along the plate. Make a spreadsheet calculation of Stanton number \(\mathrm{St}_{\mathrm{g}}\) with respect to Reynolds number in the range of \(200,000 \leq \operatorname{Re}_{x} \leq 500,000\). Graph the Stanton number versus Reynolds number. Also, calculate the wall-averaged Stanton number.

The free-stream gas temperature is \(T_{\infty}=1600 \mathrm{~K}\) and the free- stream gas speed is \(V_{\infty}=850 \mathrm{~m} / \mathrm{s}\). The gas properties are \(\gamma_{1}=1.30, c_{p e}=1244 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) and Prandtl number \(\operatorname{Pr}=0.73\). Consider the flow of this gas over a flat plate at a high Reynolds number corresponding to turbulent flow. Calculate (a) the gas total temperature \(T_{\text {tos }}\) in \(\mathrm{K}\) in the freestream (b) the adiabatic wall temperature \(T_{a w}\) in \(\mathrm{K}\) (c) percent error if we assume adiabatic wall temperature is the same as total temperature of the gas

The inlet flow condition to a turbine nozzle is characterized by \(T_{\mathrm{t} 1}=1800 \mathrm{~K}\) and \(p_{\mathrm{t} 1}=2.4 \mathrm{MPa}, M_{1}=0.5, \alpha=5^{\circ}\), with \(\gamma_{t}=1.30\) and \(c_{p t}=1244 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). Assuming the nozzle is designed for constant axial velocity, i.e., \(C_{2}=\) constant, calculate the nozzle exit flow angle \(\alpha_{2}\) that will produce the exit Mach number of \(M_{2}=1.1\).

An axial-flow turbine stage, at its pitchline radius, is shown. The rotor exit is swirl free, i.e., \(C_{\theta 3}=0\). The axial velocity is constant throughout the stage and is equal to \(C_{2}=\) \(300 \mathrm{~m} / \mathrm{s}\). The flow to the turbine stage is purely axial, i.e., \(C_{1}=C_{21}\) and the gas total temperature is \(T_{\mathrm{t} 1}=1500 \mathrm{~K}\) with \(\gamma_{1}=1.33\) and \(c_{p t}=1,156 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). Assume that the turbine is uncooled and the stage degree of reaction is \(20 \%\). Calculate (a) the nozzle exit flow angle, \(\alpha_{2}\), in degrees (b) the stage specific work in \(\mathrm{kJ} / \mathrm{kg}\) (c) total temperature relative to the rotor, \(T_{12, r}\), in \(\mathrm{K}\) (d) absolute Mach number at nozzle exit, \(M_{2}\) (e) speed of sound, \(a_{3}\), in \(\mathrm{m} / \mathrm{s}\) (f) relative rotor exit Mach number, \(M_{3}\)

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