Chapter 8: Problem 4
Find the eigenvalues and eigenvectors of the following matrices. (Use the given \(\lambda\) or factars.) $$\left[\begin{array}{ll} 0 & 0 \\ 0 & 0 \end{array}\right]$$
Short Answer
Expert verified
Eigenvalue: 0; Eigenvectors: any vector [x y].
Step by step solution
01
Understanding the Matrix Structure
We have a matrix \( A \) given by \( \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix} \), which is a 2x2 zero matrix. This means all elements are zero.
02
Determine the Eigenvalue Equation
To find the eigenvalues, we solve the characteristic equation \( \det(A - \lambda I) = 0 \), where \( I \) is the identity matrix. For our matrix, \( A - \lambda I = \begin{bmatrix} -\lambda & 0 \ 0 & -\lambda \end{bmatrix} \).
03
Calculate the Determinant
The determinant of \( A - \lambda I \) is: \( \det(\begin{bmatrix} -\lambda & 0 \ 0 & -\lambda \end{bmatrix}) = (-\lambda)(-\lambda) - (0)(0) = \lambda^2 \).
04
Solve for Eigenvalues
Set the determinant \( \lambda^2 \) equal to 0 to find the eigenvalues: \( \lambda^2 = 0 \). Solving this gives \( \lambda = 0 \). The eigenvalue is \( 0 \) with algebraic multiplicity of 2.
05
Find the Eigenvectors
For each eigenvalue, solve \( (A - \lambda I)\mathbf{v} = 0 \). Here, \( A - 0I = \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix} \). A vector \( \mathbf{v} = \begin{bmatrix} x \ y \end{bmatrix} \) satisfies:\[ \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix} \begin{bmatrix} x \ y \end{bmatrix} = \begin{bmatrix} 0 \ 0 \end{bmatrix} \]Any vector \( \mathbf{v} = \begin{bmatrix} x \ y \end{bmatrix} \) is a solution, indicating that the eigenspace is spanned by \( \begin{bmatrix} 1 \ 0 \end{bmatrix} \) and \( \begin{bmatrix} 0 \ 1 \end{bmatrix} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Zero Matrix
A zero matrix is a matrix in which all the elements are zero. It's often denoted as a matrix filled entirely with zeros, such as \[ \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix}\]for a simple 2x2 case. Zero matrices can vary in size but their defining characteristic remains the same, all entries are zero.
- In linear algebra, a zero matrix acts as an additive identity. Adding it to another matrix does not change the other matrix.
- When involved in matrix multiplication with another matrix of appropriate size, the result is always a zero matrix.
Characteristic Equation
The characteristic equation is key to finding the eigenvalues of a matrix. It is derived from the expression \[ \det(A - \lambda I) = 0\]Here, \( A \) is the matrix for which we want to find the eigenvalues, \( \lambda \) represents the eigenvalue we are solving for, and \( I \) is the identity matrix of the same dimension as \( A \).To break it down further:
- The identity matrix \( I \) has 1s on its diagonal and 0s elsewhere - it's crucial in isolating the impact of \( \lambda \) when subtracting from \( A \).
- Subtracting \( \lambda I \) from \( A \) results in another matrix, where \( \lambda \) modifies each diagonal element of \( A \).
- The determinant operation then converts this matrix equation into a polynomial equation in terms of \( \lambda \).
Eigenvalue Multiplicity
Eigenvalue multiplicity deals with how often a particular eigenvalue appears as a root of the characteristic polynomial. It is important to distinguish between **algebraic multiplicity** and **geometric multiplicity**:
- **Algebraic Multiplicity (AM):** This is the number of times an eigenvalue is repeated as a root in the characteristic equation. In our example with the zero matrix, the eigenvalue 0 has an algebraic multiplicity of 2.
- **Geometric Multiplicity (GM):** This refers to the number of linearly independent eigenvectors associated with a given eigenvalue. For the zero matrix, the GM is 2 as well, since any vector can serve as an eigenvector.