Chapter 8: Problem 28
What kind of conic section (or pair of straight lines) is given by the quadratic form? Transform it to principal axes Express \(x^{\top}-\left[x_{1} \quad x_{2}\right]\) in terms of the new coordinate vector \(\mathbf{y}^{T}=\left[\begin{array}{ll}y_{1} & y_{2}\end{array}\right],\) as in Example 6. $$6.5 x_{1}^{2}+5.0 x_{1} x_{2}+6.5 x_{2}^{2}-36$$
Short Answer
Step by step solution
Write the Quadratic Form in Matrix Representation
Find the Eigenvalues and Eigenvectors of Matrix A
Compute the Eigenvectors
Formulate the Transformation Matrix
Transform to Principal Axes and Identify the Conic
Express \( \mathbf{x}^{\top} \) in Terms of the New Coordinates
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conic Sections
An ellipse is a conic section formed when the intersecting plane cuts through a cone at an angle to its base, creating a symmetrical, oval shape. The standard form of an ellipse is:
- Horizontal: \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \)
- Vertical: \( \frac{y^2}{a^2} + \frac{x^2}{b^2} = 1 \)
This transformation from the quadratic form into a conic section supports identifying the geometric shape's nature and its relative dimensions and orientation.
Eigenvectors and Eigenvalues
- Eigenvalues: These are scalar values \( \lambda \) that satisfy the equation \( A\mathbf{v} = \lambda \mathbf{v} \), where \( A \) is a matrix, \( \mathbf{v} \) is a non-zero vector (the eigenvector), and \( I \) is the identity matrix. To find the eigenvalues, solve the characteristic polynomial \( \det(A - \lambda I) = 0 \).
- Eigenvectors: After determining the eigenvalues, the eigenvectors are found by solving \((A - \lambda I)\mathbf{v} = 0\). Each eigenvector corresponds to a specific eigenvalue and provides a direction that remains unchanged when a linear transformation is applied.
Matrix Diagonalization
Diagonalization involves expressing a matrix \( A \) as \( PDP^{-1} \), where \( D \) is a diagonal matrix and \( P \) contains the eigenvectors of \( A \) as its columns.
- Steps for Diagonalization:
- Find eigenvalues by solving \( \det(A - \lambda I) = 0 \).
- Find eigenvectors for each eigenvalue.
- Construct matrix \( P \) using the eigenvectors.
- Calculate \( D = P^{-1}AP \).