Chapter 6: Problem 6
Showing the details of your work, find \(\mathscr{L}(f)\) if \(f(t)\) equals: $$t^{2} \sin 3 t$$
Short Answer
Expert verified
\( \mathscr{L}(t^2 \sin 3t) = \frac{6}{(s^2 + 9)^3} \)
Step by step solution
01
Understand the Laplace Transform
The Laplace Transform of a function \( f(t) \), denoted as \( \mathscr{L}(f) \), is defined as \( \mathscr{L}(f) = \int_{0}^{\infty} e^{-st} f(t) \, dt \). It transforms a time-domain function into a complex frequency-domain function. Our goal is to apply this definition to \( f(t) = t^2 \sin 3t \).
02
Identify the Formula for Special Cases
For functions in the form \( t^n \sin(at) \), we use the formula for the Laplace Transform: \[ \mathscr{L}(t^n \sin(at)) = \frac{n! \cdot a}{(s^2 + a^2)^{n+1}} \]. Here, \( n = 2 \) and \( a = 3 \).
03
Substitute Known Values into the Formula
Substitute \( n = 2 \) and \( a = 3 \) into the formula: \[ \mathscr{L}(t^2 \sin 3t) = \frac{2! \cdot 3}{(s^2 + 3^2)^{3}} \].
04
Simplify the Expression
Calculate \( 2! = 2 \) and \( 3^2 = 9 \). Substitute these into the expression: \[ \frac{2 \cdot 3}{(s^2 + 9)^{3}} = \frac{6}{(s^2 + 9)^{3}} \].
05
Conclusion: Laplace Transform of the Given Function
The final result is \( \mathscr{L}(t^2 \sin 3t) = \frac{6}{(s^2 + 9)^{3}} \). This is the Laplace Transform of the function \( f(t) = t^2 \sin 3t \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
frequency-domain transformation
The concept of frequency-domain transformation is key to understanding the Laplace Transform. Essentially, the Laplace Transform is a technique used to change functions from the time domain to the frequency domain. This transformation is helpful because it simplifies the analysis and solution of differential equations.
- When we talk about the frequency domain, we are primarily dealing with a complex plane with a real part and an imaginary part.
- This transformation makes the function easier to analyze, especially for engineering and control systems applications.
- The original time-domain function is often difficult to work with due to its complexity or oscillatory nature. Transforming it helps to highlight its frequency characteristics.
time-domain function
A time-domain function is that which is expressed in terms of time, denoted usually by the variable \( t \). In this exercise, we are working with the time-domain function \( f(t) = t^2 \sin 3t \).
- Time-domain functions are typically used to describe how a system evolves over time.
- These functions might show trends such as growth, decay, or periodic oscillations like a sine wave.
- The key challenge with time-domain functions is that their behavior can be complex, which makes them difficult to analyze directly when solving differential equations.
Mathematical functions
Mathematical functions are a broad category in mathematics, and they play a critical role in the application of the Laplace Transform. In this exercise, we specifically dealt with a function combining polynomial and trigonometric elements: \( t^2 \sin 3t \).
- Polynomial functions, like \( t^2 \), involve variables raised to a power. They typically describe scenarios where growth or decay is present.
- Trigonometric functions, such as \( \sin 3t \), describe periodic behaviour, often related to waves or oscillations.
- When combined, these functions can model complex dynamic systems that appear in engineering and physics.