Chapter 25: Problem 11
If simultancous messurements of electric voltage by two different types of volteneter yield the differences (in volts) \(0.8,0.2,-0.3,0.1 .0 .0 .0 .5,0.7,0.2,\) can we assert at the \(5 \%\) level that there is no significint difference in the calibration of the two types of instruments? (Axsame normality.)
Short Answer
Step by step solution
State the Hypotheses
Calculate the Sample Mean
Calculate the Sample Standard Deviation
Compute the Test Statistic
Determine the Critical Value and Compare
Conclusion
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the t-test in Hypothesis Testing
The t-test comes in various forms, but when comparing means, it usually involves:
- A sample mean (\( \bar{x} \)): your calculated average from sample data.
- A known mean or hypothesized value (\( \mu \)): the mean you're testing against, often from the null hypothesis.
- The sample standard deviation (\( s \)): which gives insight into data variability.
- The sample size (\( n \)): the number of observations in your sample.
It’s essential to also consider the critical value, which depends on your confidence level and degrees of freedom. If the t-statistic exceeds this, our observations are statistically significant. Otherwise, they might not substantially differ.
Exploring the Null Hypothesis in Hypothesis Testing
This hypothesis is vital because it forms the basis of statistical testing:
- If evidence against \( H_0 \) is strong enough, we reject it.
- If not, we fail to reject it, not necessarily proving it true, but accepting it based on insufficient contrary evidence.
Calculating the Sample Mean
In our exercise about voltmeters, the differences in measurements were summed and divided by the number of observations to find the mean:
- Sum of differences: \( 0.8 + 0.2 - 0.3 + 0.1 + 0.0 + 0.0 + 0.5 + 0.7 + 0.2 = 2.2 \)
- Number of observations: 9
This average difference forms the basis for further comparison with the null hypothesis, helping to determine if the observed discrepancy is statistically noteworthy or just a result of randomness.
Understanding the Standard Deviation
In our example with voltmeter readings, we first calculate the squared differences between each value and the sample mean, sum them up, and divide by one less than the number of observations (degree of freedom), before taking the square root:
- Calculate squared differences: e.g., \( (0.8 - 0.244)^2, (0.2 - 0.244)^2, ext{etc.} \)
- Sum these values and divide by \( n-1 \) (here, 8), then compute the square root.