Chapter 25: Problem 11
Find a \(99 \%\) confidence interval for the mean of a normal population from the sample: Copper content ( \(\$ 5\) ) of brass 66,66,65,64,66,67,64,65,63,64.
Short Answer
Expert verified
The 99% confidence interval for the mean is [63.47, 66.53].
Step by step solution
01
Organize the Data
First, list out the observed values of the copper content: 66, 66, 65, 64, 66, 67, 64, 65, 63, and 64. The sample size, denoted as \( n \), is 10.
02
Calculate the Sample Mean
Add up the sample values and divide by the number of observations to find the sample mean \( \bar{x} \). Calculation: \( \bar{x} = \frac{66+66+65+64+66+67+64+65+63+64}{10} = 65 \).
03
Calculate the Sample Standard Deviation
Use the formula for sample standard deviation: \( s = \sqrt{\frac{1}{n-1} \sum (x_i - \bar{x})^2} \). With each \( x_i \) being a sample value, compute the deviations, square them, add them, and finally divide by \( n-1 \) (which is 9 for this sample). The calculated \( s \) is approximately 1.4907.
04
Determine the t-Value for 99% Confidence
For a 99% confidence interval and 9 degrees of freedom (\( n-1 \)), consult a t-distribution table or calculator to find \( t \). The critical t-value is approximately 3.249.
05
Calculate the Margin of Error
The margin of error (ME) is calculated using the formula \( ME = t \cdot \frac{s}{\sqrt{n}} \). Substitute the calculated values: \( ME = 3.249 \cdot \frac{1.4907}{\sqrt{10}} \approx 1.53 \).
06
Construct the Confidence Interval
To find the confidence interval, use the formula: \( \bar{x} \pm ME \). Substituting the known values: \( 65 \pm 1.53 \). Therefore, the confidence interval is \([63.47, 66.53]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sample Mean
The concept of the **Sample Mean** is fundamental in statistics. It represents the average value of a sample and is used to estimate the mean of the entire population. Calculating the sample mean involves a straightforward process, especially when you break it down step by step:
It acts as a "balancing point" for the data set, simplifying comparisons among different samples.
- Add all the sample measurements together.
- Divide the total by the number of observations in the sample.
It acts as a "balancing point" for the data set, simplifying comparisons among different samples.
Sample Standard Deviation
Calculating the **Sample Standard Deviation** gives us an understanding of how spread out the data is around the mean. It reflects the variability or dispersion of the sample data.Here's how you can calculate it using a series of steps:
This value indicates a fairly tight clustering of the data around the mean, suggesting that the data points do not deviate much from the average.
- Find the deviation of each sample point from the sample mean.
- Square each deviation to avoid negatives affecting the sum.
- Sum these squared deviations.
- Divide by \( n-1 \), where \( n \) is the number of observations, to find the average squared deviation.
- Take the square root of this result to get the standard deviation.
This value indicates a fairly tight clustering of the data around the mean, suggesting that the data points do not deviate much from the average.
t-Distribution
The **t-Distribution** is used when making inferences about a sample mean and when the sample size is small (usually \( n < 30 \)) or the population standard deviation is unknown. It is a type of probability distribution that is similar to the standard normal distribution but has heavier tails.Here are some of its characteristics:
This value inflates the interval to account for the uncertainty inherent in estimating the population mean with a small sample.
- Symmetrical about the mean.
- Has a mean of zero.
- The tails are heavier compared to standard normal distribution, accounting for more variability.
- Desired confidence level (e.g., 99%).
- Degrees of freedom, which is \( n-1 \) (in our case, 9).
This value inflates the interval to account for the uncertainty inherent in estimating the population mean with a small sample.