Chapter 24: Problem 4
Suppose that \(3 \%\) of bolts made by a machine are defective, the defectives occurring at random during production. If the bolts are packaged 50 per box. what is the Poisson approximation of the probability that a given box will contain \(x=0,1, \cdots, 5\) defectives?
Short Answer
Expert verified
The probabilities for 0 to 5 defectives are approximately 0.2231, 0.3346, 0.2510, 0.1255, 0.0471, and 0.0141.
Step by step solution
01
Identify the problem type
This problem involves finding the probability of a number of defectives in a Poisson distribution, which is often used to approximate a binomial distribution when the number of trials is large, and the probability of success is small.
02
Calculate expected number of defectives
Given that each bolt has a 3% chance of being defective out of 50 bolts, we calculate the expected number of defectives, known as the mean (\( \lambda \)), for the Poisson distribution: \( \lambda = 50 \times 0.03 = 1.5 \).
03
Write the Poisson probability formula
The Poisson probability of exactly \( x \) defects is given by the formula: \( P(X = x) = \frac{e^{-\lambda} \lambda^x}{x!} \), where \( e \approx 2.71828 \).
04
Calculate \( P(X = 0) \)
Find the probability of 0 defectives using \( \lambda = 1.5 \): \( P(X=0) = \frac{e^{-1.5} 1.5^0}{0!} = e^{-1.5} \approx 0.2231 \).
05
Calculate \( P(X = 1) \)
Find the probability of 1 defective: \( P(X=1) = \frac{e^{-1.5} 1.5^1}{1!} = 1.5 e^{-1.5} \approx 0.3346 \).
06
Calculate \( P(X = 2) \)
Find the probability of 2 defectives: \( P(X=2) = \frac{e^{-1.5} 1.5^2}{2!} = 1.125 e^{-1.5} \approx 0.2510 \).
07
Calculate \( P(X = 3) \)
Find the probability of 3 defectives: \( P(X=3) = \frac{e^{-1.5} 1.5^3}{3!} = 0.5625 e^{-1.5} \approx 0.1255 \).
08
Calculate \( P(X = 4) \)
Find the probability of 4 defectives: \( P(X=4) = \frac{e^{-1.5} 1.5^4}{4!} = 0.2109375 e^{-1.5} \approx 0.0471 \).
09
Calculate \( P(X = 5) \)
Find the probability of 5 defectives: \( P(X=5) = \frac{e^{-1.5} 1.5^5}{5!} = 0.06328125 e^{-1.5} \approx 0.0141 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial distribution
The binomial distribution is a fundamental concept in probability and statistics. It describes the likelihood of a specific number of successes in a fixed number of trials, where each trial has only two possible outcomes: success or failure. In other words, it's like flipping a coin a certain number of times and counting how many times you get heads.
Here, a 'success' could mean many things. For instance, when considering the defect of bolts, a 'success' might mean a bolt is defective. The binomial distribution is characterized by two parameters:
Here, a 'success' could mean many things. For instance, when considering the defect of bolts, a 'success' might mean a bolt is defective. The binomial distribution is characterized by two parameters:
- \( n \): The number of trials or experiments (in this case, 50 bolts in a box)
- \( p \): The probability of success on a single trial (here, a 3% chance for a bolt to be defective)
Probability of defectives
The probability of defectives refers to calculating the likelihood of finding defective items in a batch. In our example with bolts, this indicates predicting how many out of 50 bolts could be defective. Assessing this gives manufacturers insights into quality control and aids in making data-driven decisions.
To calculate such probability, we look into scenarios like:
To calculate such probability, we look into scenarios like:
- Exactly zero defectives
- Exactly one defective
- Up to 5 defectives
Poisson approximation
The Poisson approximation is a useful method when dealing with binomial distribution scenarios that involve a large number of trials (\( n \)) and a small probability of success (\( p \)). By converting the binomial problem to a Poisson problem, calculations become simpler and easier to manage.
Here's why Poisson is easier:
Here's why Poisson is easier:
- Instead of calculating probabilities for each outcome as in binomial, you have a single parameter \( \lambda \) (lambda), which is the average rate of success across trials and is calculated as \( \lambda = n \times p \).
- The Poisson probability formula is \( P(X = x) = \frac{e^{-\lambda} \lambda^x}{x!} \), which requires fewer computations.