Chapter 2: Problem 20
Solve the initial value problem. State which rules you are using, Show each step of your calculation in detail? $$\begin{aligned} &y^{\prime \prime}+2 y^{\prime}+10 y-17 \sin x-37 \sin 3 x\\\ &y(0)=6.6, \quad y^{\prime}(0)=-2.2 \end{aligned}$$
Short Answer
Expert verified
The solution is \( y = e^{-x}(2.9 \cos 3x + 3.5 \sin 3x) - 2\sin x + 3.7\sin 3x \).
Step by step solution
01
Identify the Differential Equation
The differential equation given is \( y'' + 2y' + 10y = 17\sin x + 37\sin 3x \). This is a second-order linear non-homogeneous differential equation.
02
Solve the Homogeneous Equation
To solve the homogeneous part, \( y'' + 2y' + 10y = 0 \), assume a solution of the form \( y_h = e^{rx} \). The characteristic equation is \( r^2 + 2r + 10 = 0 \). Solve it using the quadratic formula: \( r = \frac{-2 \pm \sqrt{2^2 - 4 \cdot 1 \cdot 10}}{2 \cdot 1} = -1 \pm 3i \). Then, the solution for the homogeneous equation is \( y_h = e^{-x}(C_1 \cos 3x + C_2 \sin 3x) \).
03
Solve the Particular Solution Using Undetermined Coefficients
For the particular solution, use the method of undetermined coefficients. Assume \( y_p = A\sin x + B\cos x + C\sin 3x + D\cos 3x \). Differentiate to find \( y_p' \) and \( y_p'' \), and substitute back into the differential equation. Collect like terms and equate coefficients with those on the right-hand side: \( 17\sin x + 37\sin 3x \). Solve to find the coefficients: \( A = -2 \), \( B = 0 \), \( C = 3.7 \), \( D = 0 \). So, \( y_p = -2\sin x + 3.7\sin 3x \).
04
Construct the General Solution
The general solution of the differential equation is the sum of the homogeneous and particular solutions: \( y = y_h + y_p = e^{-x}(C_1 \cos 3x + C_2 \sin 3x) - 2\sin x + 3.7\sin 3x \).
05
Apply Initial Conditions
To apply the initial conditions \( y(0) = 6.6 \) and \( y'(0) = -2.2 \), calculate \( y(0) \) and \( y'(0) \) using the general solution. Substituting \( x = 0 \) gives \( y(0) = C_1 + 3.7 = 6.6 \), so \( C_1 = 2.9 \). Differentiate \( y \) to find \( y'(0) = -3C_1 - C_2 - 2 = -2.2 \), solve this to get \( C_2 = 3.5 \).
06
Write the Final Solution with Constants
The final solution with the calculated constants is \( y = e^{-x}(2.9 \cos 3x + 3.5 \sin 3x) - 2\sin x + 3.7\sin 3x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Initial Value Problem
An initial value problem in differential equations involves finding a solution to a differential equation which also satisfies given initial conditions. Here, our task is to solve a non-homogeneous second-order linear differential equation and find values for an unknown function at a specific point. This initial condition is crucial as it ensures the solution meets certain criteria at the start, defining a unique path for the function in its domain.
Imagine you have the equation \( y'' + 2y' + 10y = 17\sin x + 37\sin 3x \) along with initial conditions \( y(0)=6.6 \) and \( y'(0)=-2.2 \). These tell us that at \( x = 0 \), the value of the function is \( 6.6 \) and the slope is \(-2.2 \).
Imagine you have the equation \( y'' + 2y' + 10y = 17\sin x + 37\sin 3x \) along with initial conditions \( y(0)=6.6 \) and \( y'(0)=-2.2 \). These tell us that at \( x = 0 \), the value of the function is \( 6.6 \) and the slope is \(-2.2 \).
- First, we must find the general solution for the differential equation.
- Second, we need to ensure this solution fits the initial conditions provided.
Method of Undetermined Coefficients
The method of undetermined coefficients is a powerful tool for solving non-homogeneous linear differential equations, particularly when the non-homogeneous part is a simple function like a sine, cosine, exponential, or polynomial. This technique involves guessing a specific form for the particular solution based on the non-homogeneous part of the differential equation.
In our given equation, the non-homogeneous part consists of terms like \( 17\sin x \) and \( 37\sin 3x \). We assume a solution that mirrors these forms: \( y_p = A\sin x + B\cos x + C\sin 3x + D\cos 3x \). This assumption simplifies our search for a solution, providing a template which we can differentiate and substitute back into the original equation.
In our given equation, the non-homogeneous part consists of terms like \( 17\sin x \) and \( 37\sin 3x \). We assume a solution that mirrors these forms: \( y_p = A\sin x + B\cos x + C\sin 3x + D\cos 3x \). This assumption simplifies our search for a solution, providing a template which we can differentiate and substitute back into the original equation.
- Substituting and differentiating help identify relations between assumed coefficients and the terms on the right-hand side.
- By equating coefficients, we can solve for constants \( A, B, C, \) and \( D \), adjusting the particular solution until it fits seamlessly into the overall differential equation.
Homogeneous Solutions
Finding homogeneous solutions involves solving the differential equation when the non-homogeneous part is set to zero. For our equation, this means working with \( y'' + 2y' + 10y = 0 \). The goal is to find a general solution derived from this simplified form, which is then combined with the particular solution for the non-homogeneous part to get a complete solution.
We start by assuming a solution of the form \( y_h = e^{rx} \). This leads to a 'characteristic equation' which needs to be solved. In our example, it is \( r^2 + 2r + 10 = 0 \). Solving this quadratic equation using the quadratic formula gives us complex roots: \(-1 \pm 3i\).
We start by assuming a solution of the form \( y_h = e^{rx} \). This leads to a 'characteristic equation' which needs to be solved. In our example, it is \( r^2 + 2r + 10 = 0 \). Solving this quadratic equation using the quadratic formula gives us complex roots: \(-1 \pm 3i\).
- The presence of imaginary parts suggests that the solution will involve sine and cosine terms: \( y_h = e^{-x}(C_1 \cos 3x + C_2 \sin 3x) \).
- This solution represents the behavior of the differential equation as if it were 'empty' or zero on the right side, focusing solely on intrinsic characteristics.