Chapter 17: Problem 2
Show that substituting a linear fractional transformation ( \(\mathrm{LFT}\) ) into a LFT gives a LFT.
Short Answer
Expert verified
Substituting a LFT into another LFT results in another LFT.
Step by step solution
01
Understand the Linear Fractional Transformation (LFT)
A linear fractional transformation, also known as a Möbius transformation, is a function of the form:\[T(z) = \frac{az + b}{cz + d},\]where \(a\), \(b\), \(c\), and \(d\) are complex numbers, and \(ad - bc eq 0\) to ensure the transformation is not degenerate.
02
Formulate the Composition of Two LFTs
Consider two LFTs:\[T_1(z) = \frac{a_1z + b_1}{c_1z + d_1}\]and \[T_2(z) = \frac{a_2z + b_2}{c_2z + d_2}.\]We want to find the form of the LFT resulting from substituting \(T_2(z)\) into \(T_1(z)\). Substituting \(T_2(z)\) into \(T_1\) gives:\[T_1(T_2(z)) = T_1\left(\frac{a_2z + b_2}{c_2z + d_2}\right).\]
03
Determine the Composition
Substitute \(T_2(z)\) into \(T_1(z)\):\[T_1\left(\frac{a_2z + b_2}{c_2z + d_2}\right) = \frac{a_1\left(\frac{a_2z + b_2}{c_2z + d_2}\right) + b_1}{c_1\left(\frac{a_2z + b_2}{c_2z + d_2}\right) + d_1}.\]
04
Simplify the Expression
Simplify and rewrite the expression:\[a_1\left(\frac{a_2z + b_2}{c_2z + d_2}\right) + b_1 = \frac{a_1(a_2z + b_2) + b_1(c_2z + d_2)}{c_2z + d_2}\]and\[c_1\left(\frac{a_2z + b_2}{c_2z + d_2}\right) + d_1 = \frac{c_1(a_2z + b_2) + d_1(c_2z + d_2)}{c_2z + d_2}.\]
05
Express the Result as a Single LFT
Combine these results to form a single fraction:\[T_1(T_2(z)) = \frac{[a_1a_2 + b_1c_2]z + [a_1b_2 + b_1d_2]}{[c_1a_2 + d_1c_2]z + [c_1b_2 + d_1d_2]},\]which is of the form \(\frac{a'z + b'}{c'z + d'}\). This confirms that the composition of two LFTs is another LFT.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Möbius Transformation
A Möbius transformation is a type of function that operates within the realm of complex numbers, providing a mapping from one set of complex numbers to another. It is defined by a specific form:
- \( T(z) = \frac{az + b}{cz + d} \)
- where \( a, b, c, \) and \( d \) are complex constants.
- The condition \( ad - bc eq 0 \) needs to be satisfied to ensure that the function is valid and retains its properties.
Complex Numbers
Complex numbers are a fundamental aspect of Möbius transformations. They extend the idea of one-dimensional number lines to two dimensions, acting as coordinates on a plane referred to as the complex plane. Each complex number is expressed as \( z = x + yi \), where:
- \( x \) is the real part.
- \( y \) is the imaginary part, and \( i \) is the imaginary unit with the property \( i^2 = -1 \).
Function Composition
Function composition involves combining two functions such that the output of one function becomes the input of another. Consider two functions: \( f(x) \) and \( g(x) \). The composition of these functions is written as \( f(g(x)) \), meaning we first apply \( g \) to \( x \), and then \( f \) to the result. In the context of Möbius transformations:
- We start with two transformations: \( T_1(z) = \frac{a_1z + b_1}{c_1z + d_1} \) and \( T_2(z) = \frac{a_2z + b_2}{c_2z + d_2} \).
- The goal is to find the transformation resulting from \( T_1(T_2(z)) \).