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Are the following sequences \(z_{1}, z_{2}, \cdots, z_{n}, \cdots,\) bounded? Convergent? Find their limit points, (Show the details of your work.) $$z_{n}=(-1)^{n} /(n+i)$$

Short Answer

Expert verified
The sequence is bounded, converges to 0, which is its limit point.

Step by step solution

01

Determine if the sequence is bounded

A sequence is bounded if there exists a real number \(M\) such that \(|z_n| < M\) for all \(n\). The given sequence is \(z_n = \frac{(-1)^n}{n+i}\). To find if it is bounded, calculate the modulus: \(|z_n| = \left|\frac{(-1)^n}{n+i}\right| = \frac{1}{\sqrt{n^2+1}}\). Since \(0 < \frac{1}{\sqrt{n^2+1}} < 1\) for all \( n \), the sequence is bounded.
02

Determine if the sequence is convergent

A sequence converges if it approaches a limit as \(n\) tends to infinity. Find the limit of \(z_n = \frac{(-1)^n}{n+i}\) as \(n \to \infty\). As \(n\) grows, the denominator \(\sqrt{n^2+1}\) grows, making \(\frac{1}{\sqrt{n^2+1}} \to 0\), thus \(z_n \to 0\). If a sequence converges, it must also be bounded, which accords with Step 1.
03

Determine the limit point

The limit points of a sequence are the values the sequence accumulates to. From Step 2, we found that \( z_n \to 0 \) as \( n \to \infty \). Therefore, the only limit point of this sequence is 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bounded Sequence
A sequence is considered "bounded" if its terms do not stray too far from a certain range of values. Specifically, for a sequence \( z_n \), if there exists a real number \( M \) such that all terms \( |z_n| < M \), then we say the sequence is bounded. In simple terms, a bounded sequence will not go off towards infinity or negative infinity.

In the given exercise, the sequence is \( z_n = \frac{(-1)^n}{n+i} \). To determine boundedness, we calculate the magnitude of each term, denoted by \( |z_n| \). The calculation is as follows:
  • \( |z_n| = \left|\frac{(-1)^n}{n+i}\right| = \frac{1}{\sqrt{n^2+1}} \)
This result indicates the sequence is always between 0 and 1 for all natural numbers \( n \). Thus, it is clear that the sequence does not exceed these bounds, making it a bounded sequence.

Recognizing boundedness is crucial because it assures us that the sequence's values remain manageable and do not diverge."
Convergent Sequences
A sequence is called "convergent" if it approaches a particular number, known as the limit, as the index \( n \) becomes very large, essentially going towards infinity. In formal terms, a sequence \( z_n \) converges to a limit \( L \) if the values of \( z_n \) get arbitrarily close to \(L \) for sufficiently large \( n \).

For the sequence in our exercise, \( z_n = \frac{(-1)^n}{n+i} \), convergence can be analyzed as follows:
  • As \( n \) grows, the imaginary component \( i \) becomes negligible compared to \( n \), simplifying the denominator to \( \sqrt{n^2+1} \).
  • The term \( \frac{1}{\sqrt{n^2+1}} \) shrinks towards zero.
Therefore, the elements of the sequence \( z_n \) get closer and closer to zero, indicating that this sequence converges.

The significance of identifying a convergent sequence lies in knowing that it reaches a stable value, facilitating predictions of future behavior for large terms."
Limit Points
The concept of "limit points" for a sequence relates to the idea of accumulation values. A limit point is where the terms of a sequence cluster as \( n \) tends to infinity.

For the sequence in question, \( z_n = \frac{(-1)^n}{n+i} \), the investigation into limit points is already simplified by the finding in Step 2: that it converges to zero. Therefore, zero becomes the limit point of the sequence because the values \( z_n \) get infinitesimally close to zero as \( n \) increases.
  • The trend is evident in larger terms, as their proximity to zero demonstrates clustering at this point.
Understanding limit points reveals where most terms lie or the sequence "accumulates" to a specific value, offering insights into the sequence's long-term behavior."

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