Chapter 15: Problem 14
Find the region of uniform convergance, (Give reason) $$\sum_{n=1}^{\infty}\left(3^{n} \tanh n\right) z^{2 n}$$
Short Answer
Expert verified
The series uniformly converges for \(|z| < \frac{1}{\sqrt{3}}\).
Step by step solution
01
Identify the Series
The given series is \( \sum_{n=1}^{\infty} (3^n \tanh n) z^{2n} \), where each term is of the form \((3^n \tanh n)z^{2n}\). To determine the uniform convergence, we need to consider the behavior of the terms as \( n \to \infty \).
02
Determine the Region of Convergence
To find the region of convergence, examine when the series \( \sum_{n=1}^{\infty} |3^n \tanh n| |z|^{2n} \) converges. Notice \( |\tanh n| \leq 1 \), so we have \( |3^n \tanh n| \leq 3^n \). Therefore, examine the simpler series \( \sum_{n=1}^{\infty} (3^n |z|^{2n}) \).
03
Apply the Ratio Test for Convergence
Apply the ratio test to the series \( \sum_{n=1}^{\infty} 3^n |z|^{2n} \). The ratio of consecutive terms is: \[ \frac{3^{n+1} |z|^{2(n+1)}}{3^n |z|^{2n}} = 3 |z|^2. \] According to the ratio test, the series converges if \( 3|z|^2 < 1 \), i.e., when \( |z| < \frac{1}{\sqrt{3}} \).
04
Check the Boundaries for Uniform Convergence
We have found the series converges for \(|z| < \frac{1}{\sqrt{3}}\). For uniform convergence, consider the boundary \( |z| = \frac{1}{\sqrt{3}} \). On this boundary, the series \( \sum_{n=1}^{\infty} (3^n |z|^{2n}) = \sum_{n=1}^{\infty} 1^n \) diverges, as the terms do not tend to zero. Thus, uniform convergence does not hold at \(|z| = \frac{1}{\sqrt{3}}\).
05
Conclusion on Uniform Convergence
The series uniformly converges for \( |z| < \frac{1}{\sqrt{3}} \), since each term of the form \( (3^n \tanh n) z^{2n} \) and the series \( \sum_{n=1}^{\infty} (3^n |z|^{2n}) \) converges absolutely in this region. Therefore, \( |z| < \frac{1}{\sqrt{3}} \) is the region of uniform convergence.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Region of Convergence
The region of convergence for a series is the set of values for which the series converges. Understanding this region is essential because it tells us where our series behaves well, meaning it settles into a definite value.
In our exercise, we are dealing with the series \( \sum_{n=1}^{\infty} (3^n \tanh n) z^{2n} \). To find its region of convergence, we need to look at the absolute values:
Once we find when this series converges, it indicates the region in the complex plane (the values of \( z \)) where our original series converges. This region is crucial for understanding the uniform behavior of the series across different values of \( z \).
In our exercise, we are dealing with the series \( \sum_{n=1}^{\infty} (3^n \tanh n) z^{2n} \). To find its region of convergence, we need to look at the absolute values:
- Consider the series \( \sum_{n=1}^{\infty} |3^n \tanh n| |z|^{2n} \).
- Since the hyperbolic tangent \( |\tanh n| \leq 1 \), it simplifies to \( |3^n \tanh n| \leq 3^n \).
Once we find when this series converges, it indicates the region in the complex plane (the values of \( z \)) where our original series converges. This region is crucial for understanding the uniform behavior of the series across different values of \( z \).
Ratio Test
The ratio test is an essential tool for determining convergence of a series. This test involves comparing the ratio of successive terms in a series and checking whether this ratio is less than 1.
For the series \( \sum_{n=1}^{\infty} 3^n |z|^{2n} \):
For the series \( \sum_{n=1}^{\infty} 3^n |z|^{2n} \):
- We compute the ratio of consecutive terms: \[\frac{3^{n+1} |z|^{2(n+1)}}{3^n |z|^{2n}} = 3 |z|^2\]
- The series converges if this ratio is strictly less than 1, i.e., when \( 3|z|^2 < 1 \).
- This simplifies to \( |z| < \frac{1}{\sqrt{3}} \).
Absolute Convergence
Absolute convergence is a stronger form of convergence. If a series converges absolutely, it means that the series formed by taking absolute values of the original terms also converges.
Why is this important?
Why is this important?
- Absolute convergence guarantees ordinary convergence.
- This implies stability in the value of the series across different ways of grouping terms.
- The simplification using absolute values ensures convergence even under rearrangements of terms.
- For \( |z| = \frac{1}{\sqrt{3}} \), the series diverges because its terms do not approach zero.
Series Behavior
The behavior of a series tells us how the series values change in response to changes in elements or regions such as \( z \).
Our series \( \sum_{n=1}^{\infty} (3^n \tanh n) z^{2n} \) behaves differently based on the magnitude of \(|z|\):
Our series \( \sum_{n=1}^{\infty} (3^n \tanh n) z^{2n} \) behaves differently based on the magnitude of \(|z|\):
- For \(|z| < \frac{1}{\sqrt{3}}\), the behavior is predictable as it converges uniformly.
- At \(|z| = \frac{1}{\sqrt{3}}\), the behavior changes - divergence occurs as terms stop decreasing towards zero.