Chapter 10: Problem 7
Evaluate the integral \(\iint_{S}(\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} d A\) directly for the given \(\mathbf{F}\) and \(\mathbf{S}\). $$\begin{aligned}&\mathbf{F}=\left[\begin{array}{lll}x^{2} & 2 & 2 \end{array}\right]\\\&S \text { the square } 0 \leq x \leqq a, 0 \leqq y \leqq a, z=1\end{aligned}$$
Short Answer
Step by step solution
Identify the Problem Type
Calculate the Curl of \( \mathbf{F} \)
Determine the Normal Vector
Compute the Dot Product
Evaluate the Surface Integral
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
- \( \operatorname{curl} \mathbf{F} = abla \times \mathbf{F} \)
Surface Integral
In this exercise, the specific surface integral is \( \iint_{S} (\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} \, dA \). This is a flux integral which measures how much of the "curl" vector passes through a surface \( S \). For a surface in the plane \( z = 1 \), with the normal vector \( \mathbf{n} = \langle 0, 0, 1 \rangle \), we find that the integral evaluates to zero, because the dot product of the curl \( \langle 0, -2, 0 \rangle \) with the normal vector is zero.
Dot Product
- \( \mathbf{A} \cdot \mathbf{B} = a_1b_1 + a_2b_2 + a_3b_3 \)
In our problem, we calculate the dot product \((\operatorname{curl} \mathbf{F}) \cdot \mathbf{n}\) which involves the curl \( \langle 0, -2, 0 \rangle \) and the normal vector \( \langle 0, 0, 1 \rangle \). Since each corresponding component is multiplied and then summed, we find the dot product presents zero, indicating that the curl vector \( \operatorname{curl} \mathbf{F} \) is perpendicular to the normal vector \( \mathbf{n} \). This reflects that no component of the curl is "passing through" the surface, explaining why the integral results in zero.