Chapter 10: Problem 25
Evaluate this integral by the divergence theorem. (Show the details.) \(\mathbf{F}=\left[\begin{array}{lll}5 x^{2}, & 5 y^{2}, & 5 z^{3}\end{array}\right], S \cdot x^{2}+y^{2}+z^{2}=4\)
Short Answer
Expert verified
The integral evaluates to \( \frac{96\pi}{5} \).
Step by step solution
01
Understand the Divergence Theorem
The divergence theorem relates the flux of a vector field through a closed surface to the divergence of the field in the volume bounded by the surface. Mathematically, it states that \( \int \int_S \mathbf{F} \cdot \mathbf{n} \, dS = \int \int \int_V abla \cdot \mathbf{F} \, dV \), where \( S \) is the closed surface, \( \mathbf{n} \) is the outward normal, and \( V \) is the volume bounded by \( S \).
02
Define the Surface and Volume
The surface \( S \) is defined by the equation \( x^2 + y^2 + z^2 = 4 \), a sphere with radius 2 centered at the origin. The volume \( V \) is the volume inside this sphere.
03
Compute the Divergence of \( \mathbf{F} \)
The vector field is \( \mathbf{F} = (5x^2, 5y^2, 5z^3) \). The divergence of \( \mathbf{F} \) is computed as: \[ abla \cdot \mathbf{F} = \frac{\partial}{\partial x}(5x^2) + \frac{\partial}{\partial y}(5y^2) + \frac{\partial}{\partial z}(5z^3). \] Calculating each term, \( \frac{\partial}{\partial x}(5x^2) = 10x \), \( \frac{\partial}{\partial y}(5y^2) = 10y \), and \( \frac{\partial}{\partial z}(5z^3) = 15z^2 \), so: \[ abla \cdot \mathbf{F} = 10x + 10y + 15z^2. \]
04
Set Up the Volume Integral
Next, we need to evaluate \( \int \int \int_V (10x + 10y + 15z^2) \, dV \) for the sphere of radius 2. It's convenient to convert to spherical coordinates: \( x = \rho \sin \phi \cos \theta \), \( y = \rho \sin \phi \sin \theta \), \( z = \rho \cos \phi \), where \( 0 \leq \rho \leq 2 \), \( 0 \leq \phi \leq \pi \), and \( 0 \leq \theta \leq 2\pi \).
05
Evaluate the Volume Integral in Spherical Coordinates
Convert the divergence to spherical coordinates: \( 10x + 10y + 15z^2 \) becomes \( 10\rho\sin\phi\cos\theta + 10\rho\sin\phi\sin\theta + 15\rho^2\cos^2\phi \). The volume element \( dV \) in spherical coordinates is \( \rho^2 \sin \phi \, d\rho \, d\phi \, d\theta \). So, the integral becomes: \[ \int_0^{2} \int_0^{\pi} \int_0^{2\pi} (10\rho\sin\phi(\cos\theta + \sin\theta) + 15\rho^2\cos^2\phi) \rho^2 \sin \phi \, d\theta \, d\phi \, d\rho. \]
06
Simplify and Calculate the Integral
First, separate the terms and calculate each integral. Term 1: Integral of \( 10\rho^3\sin^2\phi(\cos\theta + \sin\theta) \); due to symmetry, \( \cos\theta \) and \( \sin\theta \) integrate to 0 over \([0, 2\pi]\). Term 2: \( 15 \int_0^{2} \int_0^{\pi} \int_0^{2\pi} \rho^4 \cos^2 \phi \sin \phi \, d\theta \, d\phi \, d\rho \) = (30\pi/3)([\rho^5/5] from 0 to 2). Thus, evaluate to get: \[ 30\pi \cdot \int_0^{2} \rho^4 \, \frac 15 [1/2 - \cos(2\phi)/4] \, d\rho \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Field
A vector field is a function that assigns a vector to every point in space. Imagine it like a map of arrows, where each arrow shows both a direction and a magnitude at that point in space. In our exercise, we deal with the vector field \( \mathbf{F} = (5x^2, 5y^2, 5z^3) \). This means:
- The first component, \( 5x^2 \), indicates how the field behaves along the x-axis.
- The second component, \( 5y^2 \), shows the behavior along the y-axis.
- The third component, \( 5z^3 \), is about the z-axis.
Closed Surface
A closed surface refers to a boundary that completely encloses a volume in three-dimensional space. Imagine a bubble; the surface of the bubble is closed because it wraps around the air inside it. In our exercise, the closed surface \( S \) is a sphere defined by the equation \( x^2 + y^2 + z^2 = 4 \), which is a perfect example:
- This equation depicts a sphere centered at the origin \((0, 0, 0)\).
- The radius of the sphere is 2 because \( x^2 + y^2 + z^2 = 4 \) suggests \( (x, y, z) \) is on a sphere with a radius of 2.
- Spheres are simple geometric shapes that encapsulate the volume within them.
Volume Integral
A volume integral extends the concept of integration to three dimensions, allowing us to compute quantities over a 3D region. When using the divergence theorem, you convert a surface integral into a volume integral, which is often easier to compute.
In the exercise, we compute the volume integral of the divergence of a vector field over the sphere's volume. The divergence \( abla \cdot \mathbf{F} = 10x + 10y + 15z^2 \) tells us about how much the vector field spreads out from each point. Then, the integral \( \int \int \int_V abla \cdot \mathbf{F} \ dV \) gives:
In the exercise, we compute the volume integral of the divergence of a vector field over the sphere's volume. The divergence \( abla \cdot \mathbf{F} = 10x + 10y + 15z^2 \) tells us about how much the vector field spreads out from each point. Then, the integral \( \int \int \int_V abla \cdot \mathbf{F} \ dV \) gives:
- The total flux through the entire volume inside the sphere.
- This transformation leverages the fact that it is sometimes simpler to calculate within a volume than across its boundary.
Spherical Coordinates
Spherical coordinates are a system of three numbers \((\rho, \phi, \theta)\) used to define positions in three-dimensional space. They are particularly useful for problems with symmetry around a point, like spheres. In this coordinate system:
- \( \rho \) is the radial distance from the origin to the point.
- \( \phi \) is the inclination angle from the positive z-axis.
- \( \theta \) is the azimuth angle in the xy-plane from the positive x-axis.
- \( x = \rho \sin \phi \cos \theta \).
- \( y = \rho \sin \phi \sin \theta \).
- \( z = \rho \cos \phi \).