Chapter 10: Problem 11
Using Green's theorem, evaluate \(\int_{c} \mathbf{F}(\mathbf{r}) \cdot d \mathbf{r}\) counterclockwise around the boundary curve \(C\) of the region \(R\), where $$F=[2 x-3 y, \quad x+5 y], R: 16 x^{2}+25 y^{2} \leq 400, y \geq 0$$
Short Answer
Expert verified
The integral evaluates to \( 40\pi \).
Step by step solution
01
Understanding Green's Theorem
Green's Theorem relates a line integral around a simple closed curve C to a double integral over the plane region R bounded by C. It is given by: \(\int_{C} \mathbf{F} \cdot d\mathbf{r} = \iint_{R} \left( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \right) dA \) where \( \mathbf{F} = [M, N] \).
02
Identifying M and N
In the given vector field \( \mathbf{F} = [2x - 3y, x + 5y] \), identify \( M = 2x - 3y \) and \( N = x + 5y \).
03
Computing Partial Derivatives
Compute the partial derivative \( \frac{\partial N}{\partial x} = \frac{\partial}{\partial x}(x + 5y) = 1 \) and \( \frac{\partial M}{\partial y} = \frac{\partial}{\partial y}(2x - 3y) = -3 \).
04
Setting up the Double Integral
The double integral to evaluate is \( \iint_{R} (1 + 3) dA = \iint_{R} 4 \, dA \).
05
Identifying the Region R
The region R is defined by \( 16x^2 + 25y^2 \leq 400 \) and \( y \geq 0 \). This describes an ellipse in the upper half-plane with semi-major axis \( a = 5 \) and semi-minor axis \( b = 4 \).
06
Converting to Polar-like Coordinates
Since the region is elliptical, use transformation \( x = 5\cos\theta \) and \( y = 4\sin\theta \). The Jacobian of this transformation is \( 20 \).
07
Evaluating the Double Integral
Convert the integral to polar-like form: \( \iint_{R} 4 \, dA = 4 \times \int_{0}^{\pi} \int_{0}^{1} 20r \, dr \, d\theta = 80 \int_{0}^{\pi} \left[ \frac{r^2}{2} \right]_{0}^{1} \, d\theta = 80 \int_{0}^{\pi} \frac{1}{2} \, d\theta = 40 \pi \).
08
Final Result
The value of the double integral, and hence the line integral around curve C, is \( 40\pi \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Line Integral
A line integral is a powerful concept that extends the idea of integrating a function over a line or curve. This is particularly important in the context of physics and engineering for calculating work done by a force field, among other applications. When dealing with a line integral, you consider a vector field, denoted as \( \mathbf{F} \), and you integrate along a particular path or curve, noted as \( C \).
The key idea behind a line integral is that it sums up values of a vector field along a curve, taking into account both the field's magnitude and direction, relative to the curve's orientation. In mathematical terms, a line integral can be expressed as \( \int_{C} \mathbf{F} \cdot d\mathbf{r} \), where \( d\mathbf{r} \) represents an infinitesimal vector along the curve \( C \).
In practical applications, we often use Green's Theorem to transform a complicated line integral into a simpler double integral over a plane region. Green's Theorem precisely relates the line integral around the curve \( C \) to a double integral over the region \( R \) it encloses:
The key idea behind a line integral is that it sums up values of a vector field along a curve, taking into account both the field's magnitude and direction, relative to the curve's orientation. In mathematical terms, a line integral can be expressed as \( \int_{C} \mathbf{F} \cdot d\mathbf{r} \), where \( d\mathbf{r} \) represents an infinitesimal vector along the curve \( C \).
In practical applications, we often use Green's Theorem to transform a complicated line integral into a simpler double integral over a plane region. Green's Theorem precisely relates the line integral around the curve \( C \) to a double integral over the region \( R \) it encloses:
- Green's Theorem is immensely helpful to evaluate line integrals around closed curves.
- This simplification is particularly useful in complex geometrical regions, like ellipses.
Vector Field
A vector field is essentially a function that assigns a vector to each point in a given space. Think of it as a field of arrows spread throughout space, where each arrow indicates direction and magnitude. In a two-dimensional space, a vector field can be expressed as \( \mathbf{F} = [M, N] \), where \( M \) and \( N \) are scalar functions of \( x \) and \( y \).
For the exercise at hand, the vector field is described as \( \mathbf{F} = [2x - 3y, x + 5y] \). This represents a set of vectors pointing in different directions across a plane, and its behavior can influence things like fluid flow or electromagnetic fields.
Key aspects of vector fields emphasize:
For the exercise at hand, the vector field is described as \( \mathbf{F} = [2x - 3y, x + 5y] \). This represents a set of vectors pointing in different directions across a plane, and its behavior can influence things like fluid flow or electromagnetic fields.
Key aspects of vector fields emphasize:
- Each component, \( M \) and \( N \), defines the vector's behavior along the x-axis and y-axis respectively.
- Understanding the components \( M \) and \( N \) is crucial when determining the nature of the field, especially in physics and engineering.
- Green's Theorem leverages these components to simplify calculations involving curves.
Ellipse
An ellipse is a smooth, symmetric curve that resembles a squished or stretched circle. In mathematics, ellipses are defined by their geometric properties: a point set where the sum of the distances from two fixed points, the foci, is constant.
In the given problem, the region \( R \) is an ellipse represented by the equation \( 16x^2 + 25y^2 \leq 400 \). This specifies an elliptical shape in space, defining the boundary for the line integral.
Some pertinent notes about ellipses:
In the given problem, the region \( R \) is an ellipse represented by the equation \( 16x^2 + 25y^2 \leq 400 \). This specifies an elliptical shape in space, defining the boundary for the line integral.
Some pertinent notes about ellipses:
- Ellipses are characterized by their semi-major and semi-minor axes, defining their width and height.
- In this scenario, with \( a = 5 \) and \( b = 4 \), the ellipse lies in the upper-half plane \( y \geq 0 \).
- When integrating over an ellipse, it's often useful to employ transformations (e.g., polar-like coordinates) to simplify calculations.