Chapter 1: Problem 6
Sketch or graph some of the given curves. Guess what their orthogonal trajectories may look like. Find these trajectories (Show the details of your work.) $$y=c e^{-3 x}$$
Short Answer
Expert verified
The orthogonal trajectories are given by the parabolic family \( \frac{3}{2}y^2 = x + A \).
Step by step solution
01
Identify the Given Curve
The given equation of the curve is written as \( y = c e^{-3x} \), where \( c \) is a constant. This represents a family of exponential curves that decay exponentially as \( x \) increases. Each curve corresponds to a different value of \( c \).
02
Differentiate to Find Orthogonal Condition
To find the orthogonal trajectories, we must ensure that the product of the slopes of the given curve and its orthogonal trajectory is \(-1\). First, differentiate \( y = c e^{-3x} \) with respect to \( x \) to obtain the slope of the curve:\[ \frac{dy}{dx} = -3c e^{-3x} = -3y \]
03
Obtain the Slope of Orthogonal Trajectories
Since the trajectories must be orthogonal to the original curves, the slope of the orthogonal trajectory must satisfy:\[ m_1 \times m_2 = -1 \] where \( m_1 = -3y \). Thus:\[ -3y \times m_2 = -1 \] \[ m_2 = \frac{1}{3y} \]
04
Set Up and Solve the Differential Equation for Trajectories
We need to solve the differential equation given by the slope: \( \frac{dy}{dx} = \frac{1}{3y} \). Rearrange and integrate both sides:\[ 3y\, dy = dx \]Integrating both sides gives:\[ \frac{3}{2}y^2 = x + A \]where \( A \) is the constant of integration.
05
Find the Family of Orthogonal Trajectories
The equation \( \frac{3}{2}y^2 = x + A \) represents a family of parabolic curves, which are the orthogonal trajectories to the original exponential family. Each trajectory corresponds to a different value of the constant \( A \).
06
Sketching the Curves
To visualize, draw the exponential family curves \( y = c e^{-3x} \), which decrease rapidly and flatten out as \( x \) increases. Then, draw their orthogonal trajectories \( \frac{3}{2}y^2 = x + A \), which are symmetric parabolas opening to the right or left, intersecting the exponential curves perpendicularly.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Decay
Exponential decay is a fundamental concept often encountered in various scientific fields such as physics, biology, and finance. It describes a process where a quantity decreases at a rate proportional to its current value. In mathematical terms, it usually takes the form of an equation like:
- \( y = c e^{-kx} \)
- \( y \) is the quantity that changes over time,
- \( c \) is a constant representing the initial amount,
- \( e \) is the base of the natural logarithm, and
- \( -k \) is the exponential rate of decay.
Differential Equations
Differential equations are equations that involve a function and its derivatives. They are essential tools for modeling real-world systems where change occurs over time. The process usually involves:
- Determining the rate of change of a variable.
- Understanding the relationship between different rates of change in a system.
- Using this understanding to predict future behavior.
- \( \frac{dy}{dx} = -3y \)
- \( \frac{dy}{dx} = \frac{1}{3y} \)
Parabolic Curves
Parabolic curves are an important family of conic sections characterized by a U-shaped symmetry. They can take different orientations depending on the equation. For a parabola defined as \( y^2 = 4ax \), the curve opens to the right if \( x \) is positive, and to the left if \( x \) is negative. These curves can be represented by the general equation of a parabola:
- \( ay^2 + bx + cy = d \)
- \( y^2 \) correlates with the parabolic form,
- \( A \) is a constant that determines the position of the parabola along the x-axis.