Chapter 10: Problem 10
Find the \((2 n)\) th derivative of (a) \(y=x^{2} \sinh x\) (b) \(y=x^{3} \cosh x\).
Short Answer
Expert verified
The \(2n\)th derivative of \(y = x^2 \sinh x \) is \((2n)! x^{2} \sinh x \). The \(2n\)th derivative of \(y = x^3 \cosh x \) is \((2n)! x^{3} \cosh x \).
Step by step solution
01
Understand the Problem
We need to find the \(2n\)th derivative of \(y=x^{2} \sinh x\) and \(y=x^{3} \cosh x \). This involves finding the general formula for derivatives of products of polynomials and hyperbolic functions.
02
Recall the Derivatives of Hyperbolic Functions
Recall that \(\frac{d}{dx} \sinh x = \cosh x \) and \(\frac{d}{dx} \cosh x = \sinh x \). Knowing these will help simplify the derivatives.
03
Apply the Product Rule
Use the product rule to find the first few derivatives, then look for a pattern. The product rule is given by \(\frac{d}{dx}[u(x)v(x)] = u'(x)v(x) + u(x)v'(x)\).
04
Find the First Derivative of \(y = x^{2} \sinh x \)
Use the product rule: \(\frac{d}{dx}[x^2 \sinh x] = 2x \sinh x + x^2 \cosh x \).
05
Identify the General Pattern for Higher Derivatives
Using the product rule repeatedly and observing the pattern: The \(2n\)th derivative for \[y = x^2 \sinh x \] is \((2n)! x^{2} \sinh x \).
06
Find the First Derivative of \(y = x^3 \cosh x \)
Use the product rule: \(\frac{d}{dx}[x^3 \cosh x] = 3x^2 \cosh x + x^3 \sinh x \).
07
Identify the General Pattern for Higher Derivatives
Using the product rule repeatedly and observing the pattern: The \(2n\)th derivative for \[y = x^3 \cosh x \] is \((2n)! x^{3} \cosh x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hyperbolic Functions
Hyperbolic functions are analogs of the trigonometric functions but for a hyperbola instead of a circle. Two common hyperbolic functions are the hyperbolic sine, \(\text{sinh}(x)\), and the hyperbolic cosine, \(\text{cosh}(x)\).
Understanding how to differentiate these functions is essential for solving problems involving higher-order derivatives. To derive these functions:
Understanding how to differentiate these functions is essential for solving problems involving higher-order derivatives. To derive these functions:
- The derivative of \(\text{sinh}(x)\) is \(\text{cosh}(x)\).
- The derivative of \(\text{cosh}(x)\) is \(\text{sinh}(x)\).
Product Rule
The product rule is a fundamental tool in calculus used to differentiate products of two functions. Suppose you have two functions, \(u(x)\) and \(v(x)\). The product rule states that:
\[\frac{d}{dx} [u(x) \, v(x)] = u'(x) \, v(x) + u(x) \, v'(x)\]
This rule can be applied iteratively to find higher-order derivatives. For instance, to differentiate \(y = x^{2} \, \text{sinh}(x)\), we apply the product rule as follows:
\[\frac{d}{dx} [x^2 \, \text{sinh}(x)] = 2x \, \text{sinh}(x) + x^2 \, \text{cosh}(x)\]
Repeating such steps will reveal the general pattern which helps in determining higher-order derivatives. Similarly, for \(y = x^{3} \, \text{cosh}(x)\), the first derivative is found using:
\[\frac{d}{dx} [x^3 \, \text{cosh}(x)] = 3x^2 \, \text{cosh}(x) + x^3 \, \text{sinh}(x)\]
\[\frac{d}{dx} [u(x) \, v(x)] = u'(x) \, v(x) + u(x) \, v'(x)\]
This rule can be applied iteratively to find higher-order derivatives. For instance, to differentiate \(y = x^{2} \, \text{sinh}(x)\), we apply the product rule as follows:
\[\frac{d}{dx} [x^2 \, \text{sinh}(x)] = 2x \, \text{sinh}(x) + x^2 \, \text{cosh}(x)\]
Repeating such steps will reveal the general pattern which helps in determining higher-order derivatives. Similarly, for \(y = x^{3} \, \text{cosh}(x)\), the first derivative is found using:
\[\frac{d}{dx} [x^3 \, \text{cosh}(x)] = 3x^2 \, \text{cosh}(x) + x^3 \, \text{sinh}(x)\]
Derivative Patterns
When solving problems involving higher-order derivatives, it is important to identify derivative patterns. By repeatedly applying the product rule, you will often notice a pattern. For example:
For \(y = x^{2} \, \text{sinh}(x)\), and identifying after multiple differentiations, we see:
For \(y = x^{2} \, \text{sinh}(x)\): \[ (2n)! x^{2} \, \text{sinh}(x) \]
For \(y = x^{3} \, \text{cosh}(x)\): \[ (2n)! x^{3} \, \text{cosh}(x) \]
For \(y = x^{2} \, \text{sinh}(x)\), and identifying after multiple differentiations, we see:
- First derivative: \( 2x \, \text{sinh}(x) + x^2 \, \text{cosh}(x) \)
- Second derivative: \( 6x \, \text{cosh}(x) + x^2 \, \text{sinh}(x) \)
- First derivative: \( 3x^2 \, \text{cosh}(x) + x^3 \, \text{sinh}(x) \)
- Second derivative: \( 15x \, \text{sinh}(x) + x^3 \, \text{cosh}(x) \)
For \(y = x^{2} \, \text{sinh}(x)\): \[ (2n)! x^{2} \, \text{sinh}(x) \]
For \(y = x^{3} \, \text{cosh}(x)\): \[ (2n)! x^{3} \, \text{cosh}(x) \]