Chapter 9: Problem 8
In Problems, show that the given line integral is independent of the path. Evaluate in two ways: (a) Find a potential function \(\phi\) and then use Theorem \(9.9 .1\), and (b) Use any convenient path between the endpoints of the path. $$ \int_{(-1,1)}^{(0,0)}(5 x+4 y) d x+\left(4 x-8 y^{3}\right) d y $$
Short Answer
Step by step solution
Confirm the Line Integral's Independence from the Path
Calculate Partial Derivatives
Find the Potential Function \(\phi\)
Use Potential Function for Integral
Evaluate Using a Convenient Path
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conservative Vector Field
To determine if a vector field \( \mathbf{F} \) is conservative, we check whether there exists a potential function \( \phi \) such that \( \mathbf{F} = abla \phi \). In mathematical terms, \( \mathbf{F} \) is conservative if its curl is zero or its components satisfy \( \frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x} \), where \( P \) and \( Q \) are the components of \( \mathbf{F} \). If this condition holds, the vector field has a potential function, and the line integral is path-independent.
Potential Function
To find a potential function, start by integrating the component \( P \) with respect to \( x \) and then the component \( Q \) with respect to \( y \). Combine these to form the complete potential function \( \phi \). If the partial derivatives satisfy the condition for a conservative field, the integrated result is consistent, rendering the vector field path-independent. Once the potential function is known, evaluating the integral between two points is simply the difference \( \phi \) at these points.
Path Independence
Path independence assures that by finding a potential function, we can evaluate the integral simply using endpoint values. It assures that intricate path-specific calculations are bypassed. This quality of path independence, owing to its reliance on only endpoints, makes calculations both straightforward and efficient in practice.
Green's Theorem
Mathematically, it states that a line integral of a vector field around a simple, closed curve is equal to the double integral of the curl of the field over the interior of the curve. Formulated as \( \int_{C} P \, dx + Q \, dy = \iint_{R} \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) dA \), it provides an alternate way of understanding and solving line integrals.
Though in our original exercise we don't use Green's Theorem directly, understanding it highlights how different integral concepts interconnect, offering a broader perspective in vector analysis.