Chapter 9: Problem 8
In Problems \(7-16\), find the curl and the divergence of the given vector field. $$ \mathbf{F}(x, y, z)=10 y z \mathbf{i}+2 x^{2} z \mathbf{j}+6 x^{3} \mathbf{k} $$
Short Answer
Expert verified
The curl of \( \mathbf{F} \) is \(-2x^2\mathbf{i} + (18x^2 - 10y)\mathbf{j} + (4xz - 10z)\mathbf{k} \) and the divergence is 0.
Step by step solution
01
Understand the Vector Field Components
The vector field \( \mathbf{F}(x,y,z) \) is given by \( \mathbf{F}(x,y,z) = 10yz \mathbf{i} + 2x^2 z \mathbf{j} + 6x^3 \mathbf{k} \). This means the components of the vector field are \( F_1 = 10yz \), \( F_2 = 2x^2z \), and \( F_3 = 6x^3 \).
02
Calculate the Curl of \( \mathbf{F} \)
The formula for the curl of a vector field \( \mathbf{F} = (F_1, F_2, F_3) \) is: \[ abla \times \mathbf{F} = abla \times (F_1 \mathbf{i} + F_2 \mathbf{j} + F_3 \mathbf{k}) = \left( \frac{\partial F_3}{\partial y} - \frac{\partial F_2}{\partial z} \right) \mathbf{i} - \left( \frac{\partial F_3}{\partial x} - \frac{\partial F_1}{\partial z} \right) \mathbf{j} + \left( \frac{\partial F_2}{\partial x} - \frac{\partial F_1}{\partial y} \right) \mathbf{k} \]Substituting in the components:- \( \frac{\partial F_3}{\partial y} = 0 \) and \( \frac{\partial F_2}{\partial z} = 2x^2 \), so the \( \mathbf{i} \)-component is \( 0 - 2x^2 = -2x^2 \).- \( \frac{\partial F_3}{\partial x} = 18x^2 \) and \( \frac{\partial F_1}{\partial z} = 10y \), so the \( \mathbf{j} \)-component is \( 18x^2 - 10y \).- \( \frac{\partial F_2}{\partial x} = 4xz \) and \( \frac{\partial F_1}{\partial y} = 10z \), so the \( \mathbf{k} \)-component is \( 4xz - 10z \).The curl is \(-2x^2\mathbf{i} + (18x^2 - 10y)\mathbf{j} + (4xz - 10z)\mathbf{k} \).
03
Calculate the Divergence of \( \mathbf{F} \)
The formula for the divergence of a vector field \( \mathbf{F} = (F_1, F_2, F_3) \) is:\[ abla \cdot \mathbf{F} = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z} \]Calculating each partial derivative:- \( \frac{\partial F_1}{\partial x} = 0 \).- \( \frac{\partial F_2}{\partial y} = 0 \).- \( \frac{\partial F_3}{\partial z} = 0 \).Thus, \( abla \cdot \mathbf{F} = 0 + 0 + 0 = 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
Understanding the concept of the extbf{curl} of a vector field is crucial in vector calculus. The curl essentially measures the rotation or "swirl" of the field at a point, helping to identify the presence of any rotational motion. Think of the curl as how much the vector field resembles a rotational or swirling motion around a point.
Given a vector field \( \mathbf{F}(x,y,z) = (F_1, F_2, F_3) \), the curl is computed using the cross product of the del operator \( abla \) with the vector field \( \mathbf{F} \). The formula for this operation is expressed as:
\[ abla \times \mathbf{F} = \left( \frac{\partial F_3}{\partial y} - \frac{\partial F_2}{\partial z} \right) \mathbf{i} - \left( \frac{\partial F_3}{\partial x} - \frac{\partial F_1}{\partial z} \right) \mathbf{j} + \left( \frac{\partial F_2}{\partial x} - \frac{\partial F_1}{\partial y} \right) \mathbf{k} \]
In our example, after substituting and calculating these partial derivatives, the curl results in:
Given a vector field \( \mathbf{F}(x,y,z) = (F_1, F_2, F_3) \), the curl is computed using the cross product of the del operator \( abla \) with the vector field \( \mathbf{F} \). The formula for this operation is expressed as:
\[ abla \times \mathbf{F} = \left( \frac{\partial F_3}{\partial y} - \frac{\partial F_2}{\partial z} \right) \mathbf{i} - \left( \frac{\partial F_3}{\partial x} - \frac{\partial F_1}{\partial z} \right) \mathbf{j} + \left( \frac{\partial F_2}{\partial x} - \frac{\partial F_1}{\partial y} \right) \mathbf{k} \]
In our example, after substituting and calculating these partial derivatives, the curl results in:
- \( -2x^2 \mathbf{i} \)
- \( (18x^2 - 10y) \mathbf{j} \)
- \( (4xz - 10z) \mathbf{k} \)
Divergence of a Vector Field
Next, let's dive into the extbf{divergence} of a vector field, which tells us how much a vector field spreads out from a point. Unlike curl, which focuses on rotation, divergence measures the "outflow" or "inflow" at a single point.
Consider a vector field \( \mathbf{F} = (F_1, F_2, F_3) \). The divergence \( abla \cdot \mathbf{F} \) sums the rates of change of each component in the direction of its respective axis, and is calculated as:
\[ abla \cdot \mathbf{F} = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z} \]
In this case, the computed partial derivatives are zero for each component, leading to:\
\( abla \cdot \mathbf{F} = 0 \)
Zero divergence suggests that the vector field is neither diverging nor converging at any point, indicating a balanced inflow and outflow across the field.
Consider a vector field \( \mathbf{F} = (F_1, F_2, F_3) \). The divergence \( abla \cdot \mathbf{F} \) sums the rates of change of each component in the direction of its respective axis, and is calculated as:
\[ abla \cdot \mathbf{F} = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z} \]
In this case, the computed partial derivatives are zero for each component, leading to:\
\( abla \cdot \mathbf{F} = 0 \)
Zero divergence suggests that the vector field is neither diverging nor converging at any point, indicating a balanced inflow and outflow across the field.
Partial Derivatives
Partial derivatives are a fundamental concept in vector calculus, and they form the basis for finding both curl and divergence.
They represent the rate at which a function changes as only one of its many variables is varied, while the others are kept constant. For example, \( \frac{\partial F_1}{\partial x} \) gives the rate of change of the function \( F_1 \) as \( x \) changes, assuming \( y \) and \( z \) remain constant.
This concept factors prominently when calculating both the curl and divergence. Each partial derivative occurs with respect to the vector field's individual components:\
They represent the rate at which a function changes as only one of its many variables is varied, while the others are kept constant. For example, \( \frac{\partial F_1}{\partial x} \) gives the rate of change of the function \( F_1 \) as \( x \) changes, assuming \( y \) and \( z \) remain constant.
This concept factors prominently when calculating both the curl and divergence. Each partial derivative occurs with respect to the vector field's individual components:\
- For curl, it involves mixing changes across different directions.
- For divergence, it involves summing changes along each axis.
Vector Field Components
The concept of extbf{vector field components} is key to understanding vector calculus and solving related problems. Each vector field can be seen as an assignment of a vector to each point in space, described as components that are functions of coordinates (e.g., \( x, y, z \)).
In the given vector field \( \mathbf{F}(x, y, z) = 10yz \mathbf{i} + 2x^2z \mathbf{j} + 6x^3 \mathbf{k} \), we have:
Analyzing these components lets us break down complex multidimensional functions into more manageable parts, aiding in calculating quantities like curl and divergence.
In the given vector field \( \mathbf{F}(x, y, z) = 10yz \mathbf{i} + 2x^2z \mathbf{j} + 6x^3 \mathbf{k} \), we have:
- \( F_1 = 10yz \), representing the \( i \)-component.
- \( F_2 = 2x^2z \), representing the \( j \)-component.
- \( F_3 = 6x^3 \), representing the \( k \)-component.
Analyzing these components lets us break down complex multidimensional functions into more manageable parts, aiding in calculating quantities like curl and divergence.